By the end of this chapter you'll be able to…

  • 1Determine the order and degree of a differential equation, recognising when the degree is not defined
  • 2Distinguish a general solution (with arbitrary constants equal to the order) from a particular solution (with none)
  • 3Solve a variable separable differential equation by separating x and y terms onto opposite sides before integrating
  • 4Recognise a homogeneous differential equation and solve it using the substitution y=vx (or x=vy when that direction is simpler)
  • 5Solve a linear differential equation of the form dy/dx+Py=Q using the integrating factor e^(integral of P dx), including its mirror-image form in x(y)
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Why this chapter matters
This is where integration finally answers a different kind of question — not 'what is the area' but 'given how something changes, what is it.' The three solving techniques here (separable, homogeneous, linear) recur throughout physics, economics, and biology wherever a rate of change is known and the underlying function is not.

Differential Equations

1. Check this before you revise anything

"Formation of a differential equation" is gone. Older editions had a dedicated section — given a family of curves with arbitrary constants, differentiate times and eliminate the constants to build the differential equation they satisfy — complete with its own worked examples and its own exercise. The current book's section list is just:

SectionTopic
9.1Introduction
9.2Basic Concepts (9.2.1 order, 9.2.2 degree)
9.3General and Particular Solutions of a Differential Equation
9.4Methods of Solving First Order, First Degree Differential Equations (9.4.1 variable separable, 9.4.2 homogeneous, 9.4.3 linear)

A full-text search of the entire 38-page chapter for "formation," "eliminating arbitrary constants," or any "differentiate times" technique returns zero hits.

Across all 98 questions in this chapter's five exercises and Miscellaneous Exercise, not one asks you to build a differential equation from a given family of curves — every question either classifies an equation (order/degree), verifies a proposed solution, or solves one using separation, the homogeneous substitution, or the linear integrating-factor method. This matches the syllabus line exactly: "definition, order and degree, general and particular solutions... solution of differential equations."

The old stub taught formation as its own section, with the rule "differentiate as many times as there are constants; the number of arbitrary constants equals the order" — a real technique, just not one that exists in this edition. Removed entirely from this rebuild.

This is also a large chapter — 98 questions across five exercises plus a Miscellaneous Exercise. Several exercises hide extra questions past their own stated range: Exercise 9.1's instruction says "Exercises 1 to 10" but the exercise actually runs to Q12 (two unannounced MCQs on degree and order); Exercise 9.2 says "Exercises 1 to 10" but runs to Q12; Exercise 9.4 and 9.5 both add MCQs the same way.

None of these trailing MCQs are flagged by an explicit "Choose the correct answer in Exercises X and Y" instruction line the way they are in other chapters — they simply appear as directly-numbered questions with inline options.

ExerciseTopicQuestions
9.1Order and degree12
9.2Verifying solutions12
9.3General/particular solutions, variable separable, word problems23
9.4Homogeneous differential equations17
9.5Linear differential equations19
MiscellaneousMixed methods, plus two "verify/prove" identities15

2. What a Differential Equation Is (Textbook 9.1 to 9.2)

An ordinary algebraic equation such as asks for a number. A differential equation asks for a function, and it does so by stating a relationship that the function and its derivatives must satisfy.

The defining feature is that a derivative appears. An equation involving derivatives of a dependent variable with respect to a single independent variable is an ordinary differential equation. This chapter deals only with ordinary equations, and only with functions of one variable.

Notice immediately that the solution is not one function but a whole family — every value of gives a curve satisfying the equation. That plurality is the central fact of the chapter, and sections 9.3 onwards are largely about managing it.

Why this matters beyond the exam. Any statement of the form "the rate of change of is proportional to " is a differential equation. Population growth, radioactive decay, Newton's law of cooling and the draining of a tank are all in Exercise 9.3 for exactly this reason.


3. Order and Degree (Textbook 9.2.1 to 9.2.2)

These two classifications are what the whole of Exercise 9.1 tests, and they are asked separately.

Order is the order of the highest derivative appearing in the equation. It requires no preparation of the equation — you simply look for the highest derivative present.

EquationOrder
1
2
3

Note the last row: the highest derivative is , so the order is 3. The power of 2 on it does not affect the order at all — that power is the degree.

Degree is the power of the highest-order derivative, after the equation has been cleared of radicals and fractions in its derivatives. Two conditions must be met before the question is even meaningful.

First, the equation must be expressible as a polynomial in its derivatives. Second, it must actually be cleared — an equation containing has no degree until you square to remove the radical.

When degree is undefined. If the derivatives appear inside a transcendental function, no amount of rearranging produces a polynomial, and the degree does not exist:

because expands to an infinite series in . The same applies to , and similar terms. Exercise 9.1 includes several of these, and the expected answer is explicitly "degree not defined" — not zero, and not left blank.


4. General and Particular Solutions (Textbook 9.3)

A solution of a differential equation is a function that satisfies it identically when substituted in. Exercise 9.2 consists entirely of verifying that a proposed function is a solution, which is done by differentiating it the required number of times and substituting back.

General solution. The solution containing as many independent arbitrary constants as the order of the equation. A first-order equation has one constant, a second-order equation has two.

Geometrically the general solution is a family of curves. The equation has general solution , which is the set of all vertically-shifted parabolas.

Particular solution. Obtained by assigning specific values to every arbitrary constant, which picks out one curve from the family. A particular solution therefore contains zero arbitrary constants, whatever the order of the equation.

The values are fixed by extra information, usually an initial condition of the form when . Substituting the condition into the general solution produces an equation in the constants, and solving it completes the problem.

The standard exam shape is: solve the equation to get the general solution, then apply the given condition to find the constant, then state the particular solution. Marks are allocated to all three steps, so write the general solution as an explicit intermediate line even when the question only asks for the particular one.


5. Variables Separable (Textbook 9.4.1)

The first and simplest of the three methods. It applies when the equation can be written with all the terms on one side and all the terms on the other.

The test. The equation has the form:

that is, the right-hand side factorises into a function of alone times a function of alone.

The method. Divide through by , multiply by , and integrate each side with respect to its own variable:

Only one constant of integration is needed. Writing on the left and on the right and then combining them into a single is correct but wastes time.

A practical point on the constant. When both integrals produce logarithms, it is almost always cleaner to write the constant as rather than . Then becomes directly, instead of requiring a second renaming. Several Exercise 9.3 answers are stated in this form.

Word problems on growth, decay and cooling all reduce to this method, since "rate proportional to amount" gives , which separates immediately.


6. Homogeneous Differential Equations (Textbook 9.4.2)

The test. A function is homogeneous of degree zero if:

for every non-zero . In practice this means every term in the expression has the same total degree in and , so the scaling cancels. Examples include and .

A differential equation with such an is called homogeneous. Equivalently, the whole right-hand side can be written as a function of the single combination .

The substitution. Put , where is a new function of . Differentiating as a product:

Substituting both into the equation turns it into a relation between and only — and that relation is always separable. Solve it by the method of the previous section, then replace by at the very end.

Do not forget the back-substitution. Leaving the answer in terms of is a common way to lose the final mark, since was never part of the original problem.

The mirror-image case. Sometimes the equation is more naturally homogeneous when read as in terms of , that is . Then substitute instead, giving , and proceed identically. Choosing the wrong direction still works in principle but usually produces a far messier integral, so inspect the equation before committing.


7. Linear Differential Equations (Textbook 9.4.3)

The standard form. A first-order equation is linear when it can be written as:

where and are functions of alone, or constants. The defining feature is that and each appear to the first power and are not multiplied together.

The integrating factor. Define:

Multiplying the equation through by this factor makes the left-hand side an exact derivative — it becomes precisely . That is the entire point of the construction, and it is why the method works.

Integrating both sides then gives the solution:

Simplifying the integrating factor. The exponential and logarithm almost always collapse. If then , so . Leaving it as an unsimplified exponential makes the next integral far harder than it needs to be.

The mirror-image form. When isolating produces a messy equation but isolating does not, use:

with functions of , solving for as a function of . Exercise 9.5 questions 10 to 12 are built specifically to reward spotting this.

Worked, mirroring the textbook's own technique. Solve , given when .

This is linear with and , so .

Then , giving the general solution .

Substituting the condition : , so . The particular solution is .


Summary

  • A differential equation relates a function to its derivatives, and its solution is a family of functions, not a single one.
  • Order is the highest derivative present and needs no preparation of the equation; degree is the power of that highest derivative after clearing radicals and fractions.
  • Degree is undefined whenever a derivative sits inside a transcendental function such as , or — the expected answer is "not defined", not zero.
  • The general solution carries as many arbitrary constants as the order and represents a family of curves; a particular solution fixes them all using an initial condition and carries none.
  • "Formation of a differential equation" from a family of curves is not part of the current edition — every question here classifies, verifies, or solves an equation, never builds one.
  • Variable separable: write and integrate each side; use as the constant when logarithms appear on both sides.
  • Homogeneous: confirm , substitute with , solve the resulting separable equation, then substitute back.
  • Use instead whenever the equation is more naturally homogeneous in the other direction.
  • Linear: gives and ; always simplify the integrating factor before integrating.
  • Several exercises hide extra MCQs past their own stated question range, with no "choose the correct answer" lead-in line — always check the actual last page, not just the instruction sentence.

Key formulas & results

Everything you need to memorise, in one card. Screenshot this for revision.

Order of a differential equation
The order of the highest derivative appearing in the equation
Requires no preparation of the equation; a power on the highest derivative affects degree, not order
Degree of a differential equation
The power of the highest-order derivative, after clearing all radicals and fractions in the derivatives
Defined only when the equation is a polynomial in its derivatives
When degree is undefined
If a derivative appears inside a transcendental function such as sin(y''), e^(y') or log(y'), the degree does not exist
The expected exam answer is 'degree not defined' — not zero, and not left blank
General solution
A solution containing as many independent arbitrary constants as the order of the equation
Geometrically a family of curves; a first-order equation gives a one-parameter family
Particular solution
Obtained by assigning specific values to every arbitrary constant, usually via an initial condition y = y0 at x = x0
Contains zero arbitrary constants regardless of the order; write the general solution as an explicit intermediate step for marks
Variable separable form
dy/dx = g(x).h(y)
The test is that the right-hand side factorises into a function of x alone times a function of y alone
Solving by separation
(1/h(y)) dy = g(x) dx, then integral of (1/h(y)) dy = integral of g(x) dx + C
Only one constant of integration is needed; use log C when both sides produce logarithms
Homogeneous function test
F(lambda.x, lambda.y) = F(x,y), that is F is homogeneous of degree zero
In practice every term has the same total degree, so the right-hand side can be written in terms of y/x alone
Homogeneous substitution
Put y = vx, so dy/dx = v + x.dv/dx; the equation becomes separable in v and x
Substitute v = y/x back at the very end — leaving the answer in v loses the final mark
Mirror-image homogeneous substitution
When the equation is homogeneous as dx/dy = G(x,y), put x = vy so that dx/dy = v + y.dv/dy
Choosing the wrong direction still works but usually produces a far messier integral
Linear differential equation, standard form
dy/dx + Py = Q, where P and Q are functions of x alone or constants
y and dy/dx each appear to the first power and are not multiplied together
Integrating factor
I.F. = e^(integral of P dx)
Multiplying through by it makes the left side exactly d/dx (y . I.F.), which is why the method works
Solution of a linear equation
y . I.F. = integral of (Q . I.F.) dx + C
Always simplify the integrating factor first, for example e^(2 log|sec x|) = sec^2 x
Mirror-image linear form
dx/dy + P1.x = Q1 with P1, Q1 functions of y, and I.F. = e^(integral of P1 dy)
Used when isolating y is messy but isolating x is not, as in Exercise 9.5 questions 10 to 12
Growth and decay model
dy/dt = ky separates to give y = A.e^(kt)
Every 'rate proportional to amount' word problem in Exercise 9.3 reduces to this
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Common mistakes & fixes

These are the exact errors that cost students marks in board exams. Read them once, save yourself the trouble.

WATCH OUT
Assuming an equation has a defined degree just because it has a well-defined order
Degree is only defined when the equation is a polynomial in its derivatives — an equation containing sin, cos, log, or e of a derivative has order but no degree.
WATCH OUT
Missing a trailing MCQ or two at the end of an exercise because the instruction line only announces the earlier question range
Several exercises in this chapter add unannounced questions (often MCQs) past their own stated 'Exercises 1 to N' range, with no separate lead-in line — always check the actual last few questions of an exercise, not just its opening instruction.
WATCH OUT
Trying to 'form' a differential equation from a family of curves by differentiating and eliminating constants
That technique is not part of the current edition of this chapter — every question here classifies, verifies, or solves an already-given differential equation, never builds one from scratch.
WATCH OUT
Choosing y=vx for a homogeneous equation when x=vy would make the algebra dramatically simpler
When the equation is given (or rearranges more naturally) as dx/dy=h(x/y) rather than dy/dx=h(y/x), substitute x=vy instead — forcing y=vx on such an equation leads to much messier integrals.
WATCH OUT
Forgetting to divide the whole equation by the coefficient of dy/dx before reading off P and Q for a linear equation
The standard form requires the coefficient of dy/dx to be exactly 1 — always divide through first, or P and Q will be wrong and the integrating factor will not work.

Practice problems

Work through this chapter's problems as a readiness check — reveal each solution, mark yourself honestly, and get your gap report at the end.

Readiness check

Are you exam-ready for Differential Equations?

8 problems from this chapter. Try each one, reveal the worked solution, mark yourself honestly — get your gap report at the end.

8 questions~6 min worth ~35 marks in CBSE exams

5-minute revision

The whole chapter, distilled. Read this the night before the exam.

  • Degree is only defined when the equation is a polynomial in its derivatives — order alone does not guarantee a defined degree
  • A general solution has as many arbitrary constants as the order; a particular solution has none, since every constant is fixed by given conditions
  • Variable separable: separate x and y terms fully, then integrate each side independently
  • Homogeneous: substitute y=vx (dy/dx=v+x.dv/dx) or x=vy when that direction is more natural, reducing to a separable equation in v
  • Linear: I.F.=e^(integral of P dx), solution y.(I.F.)=integral of (Q.I.F.)dx+C — or the mirror x(y) form when isolating x is simpler
  • 'Formation of a differential equation' from a family of curves by eliminating arbitrary constants is not part of the current edition
  • Several exercises hide extra MCQs past their own stated question range, with no separate lead-in instruction line

CBSE marks blueprint

Where the marks come from in this chapter — so you can plan your prep.

Typical chapter weightage: Unit III: part of the 35-mark Calculus block, no chapter-wise split published by CBSE

Question typeMarks eachTypical countWhat it tests
Order and Degree, and General/Particular Solutions2-31Reading off order and degree, and distinguishing general from particular solutions
Variable Separable and Homogeneous Differential Equations4-51Separating variables directly, or substituting y=vx (or x=vy) to reduce a homogeneous equation to a separable one
Linear Differential Equations, including Word Problems5-61-2Finding the integrating factor and applying the solution formula, including the mirror-image x(y) form and translating word problems into a differential equation
Prep strategy
  • Always check whether the equation is already separable before trying the homogeneous or linear method — it is the fastest technique when it applies
  • For a homogeneous-looking equation, check both directions (y=vx and x=vy) mentally before committing — one direction is often dramatically simpler
  • For a linear equation, divide through by the coefficient of the highest derivative first, so P and Q are read off correctly before computing the integrating factor
  • For word problems, write the geometric or physical condition as an explicit equation in dy/dx before attempting to classify or solve it
  • Do not spend time trying to 'form' a differential equation from a family of curves — that technique is not part of the current syllabus for this chapter

Where this shows up in the real world

This chapter isn't just an exam topic — it lives in the world around you.

Population growth and radioactive decay

dP/dt=kP (continuous growth) and dN/dt=-lambda.N (decay) are both variable-separable differential equations solved with exactly the technique in Exercise 9.3 — the same equation models bacterial growth, compound interest, and carbon dating.

Newton's law of cooling

The rate at which an object's temperature approaches its surroundings, dT/dt=-k(T-T_ambient), is a linear differential equation solved with the same integrating-factor method as Exercise 9.5.

Electrical circuits: RL and RC transients

The current in a circuit with a resistor and inductor (or capacitor) obeys a first-order linear differential equation identical in structure to the ones in this chapter, with the integrating factor giving the exponential charging/discharging curve.

Exam strategy

Battle-tested tips from teachers and toppers for this chapter.

1
State explicitly which method you are using (variable separable, homogeneous, or linear) before starting — this signals the correct setup even if later algebra has an error
2
For homogeneous equations, show the substitution step (y=vx, dy/dx=v+x.dv/dx) explicitly rather than jumping straight to the separated form
3
For linear equations, write out P, Q, and the integrating factor as three separate labelled steps — examiners award marks for each
4
For word problems, write the translated differential equation as its own labelled line before solving, so the setup can earn marks even if the final integration has an error

Going beyond the textbook

For olympiad aspirants and curious learners — topics that build on this chapter.

STRETCH
Second and higher-order linear differential equations with constant coefficients (not covered in this syllabus) generalise the linear method here to equations like y''+ay'+by=0, solved via a characteristic equation
STRETCH
Exact differential equations and integrating factors for non-linear cases extend the integrating-factor idea beyond the first-order-linear form covered here
STRETCH
Systems of differential equations, where several unknown functions and their derivatives are coupled together, are the natural next step beyond a single equation in one unknown function
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JEE Main & Advanced practice

Competitive-level problems on this chapter, above the board pattern. Try each one on paper before opening the solution.

JEE MainHomogeneous equation requiring the x=vy substitutionRecognising which variable's substitution simplifies the algebra

Solve .

Stuck? Show the approach

This is homogeneous, but attempting y=vx leaves e^{x/y} unwieldy; substituting x=vy instead makes every exponential term a clean function of v alone.

Show the full solution

With , , and the equation reduces to . Since has a numerator that is exactly the derivative of its denominator, separating and integrating gives , i.e. .

Answer: x+y.e^(x/y)=C
The trap

Attempting the more familiar y=vx substitution here produces e^{y/x} terms tangled with both x and y in a way that never separates cleanly — recognising which substitution direction actually simplifies the equation is the entire difficulty of this problem.

JEE MainLinear equation solved in the mirror-image x(y) directionRecognising when isolating x instead of y avoids a non-linear equation entirely

Solve .

Stuck? Show the approach

Isolating dy/dx gives a non-linear equation in y; rewriting as dx/dy=x+y instead reveals a linear equation in x(y).

Show the full solution

Rewriting as , this is linear in with integrating factor . Then (by parts), giving .

Answer: x=-y-1+Ce^y
The trap

Treating dy/dx=1/(x+y) as the starting point and trying to solve for y directly leads nowhere with elementary methods — the equation is only linear in the other direction, x as a function of y.

JEE AdvancedWord problem requiring translation into a linear differential equationSetting up dy/dx from a geometric description before solving

Find the equation of a curve passing through the point given that the sum of the coordinates of any point on the curve exceeds the magnitude of the slope of the tangent to the curve at that point by 5.

Stuck? Show the approach

Translate 'sum of coordinates exceeds the slope by 5' into , then solve the resulting linear equation.

Show the full solution

The condition gives , i.e. , linear with integrating factor . Integrating (by parts) gives ; substituting gives .

Answer: y=4-x-2e^x
The trap

Misreading the word problem's direction (writing instead of ) is the single most common error — always isolate on one side before identifying and .

Where else this chapter is tested

CBSE board isn't the only one — other exams test this chapter too.

CBSE Class 12 BoardVery High
JEE MainHigh
JEE AdvancedMedium

Questions students ask

The real ones — pulled from the Q&A community and tutor sessions.

No — the current edition's section list runs straight from order/degree (9.2) to general/particular solutions (9.3) to solving methods (9.4), with no formation section in between. A full-text search of all 98 questions finds none that ask you to build a differential equation from a given family; every question classifies, verifies, or solves an already-given equation.

Try whichever direction the equation is naturally given in first: if it's dy/dx=F(x,y), start with y=vx; if it's more naturally dx/dy=G(x,y) (or contains terms like e^(x/y) that would stay tangled under y=vx), use x=vy instead. A few questions in Exercise 9.4 and the Miscellaneous Exercise are specifically chosen to require the x=vy direction.

Several exercises (9.1, 9.2, 9.4, 9.5) add one or two extra questions — usually MCQs — after the range stated in their opening instruction line, with no separate 'choose the correct answer' sentence announcing them. They are easy to miss if you stop reading after the stated range; always check the actual last page of an exercise.

Whenever isolating dy/dx produces an equation that is not linear in y, but rearranging as dx/dy does produce something linear in x — this happens whenever the equation looks like (x+f(y))dy/dx=1 or similar, seen directly in Exercise 9.5, Questions 10 through 12.
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Last reviewed on 17 August 2026. Written and reviewed by subject-matter experts — read about our process.
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