By the end of this chapter you'll be able to…

  • 1Represent vectors using direction, magnitude, and component form; perform addition and scalar multiplication
  • 2Compute the dot product a⃗·b⃗ = |a⃗||b⃗|cos θ and use it to find angles, projections, and check perpendicularity
  • 3Compute the cross product a⃗ × b⃗ (using determinant formula) and use it to find area of parallelogram/triangle
  • 4Evaluate the scalar triple product [a⃗ b⃗ c⃗] = a⃗·(b⃗ × c⃗) and apply the coplanarity test
  • 5Find unit vectors, position vectors, and section formula in vector form
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Why this chapter matters
Vector Algebra is the foundation for 3D Geometry (Chapter 11). Dot product (scalar product) and cross product (vector product) are tested in every CBSE board exam — finding the angle between vectors, projection, area of triangle/parallelogram, and checking perpendicularity. Students who master vectors here find 3D geometry straightforward.

Vector Algebra

"A vector is a quantity with magnitude AND direction. It is the mathematics of arrows."

1. Chapter Overview

VECTORS are quantities with BOTH magnitude and direction (displacement, velocity, force). This chapter covers: vector representation, types (zero, unit, co-initial, collinear, coplanar), OPERATIONS (addition, scalar multiplication), DOT PRODUCT (scalar product), and CROSS PRODUCT (vector product).


2. Basic Concepts

  • Vector a⃗ = directed line segment. Magnitude |a⃗|.
  • Unit vector: magnitude = 1. â = a⃗/|a⃗|.
  • î, ĵ, k̂: Unit vectors along x, y, z axes.
  • Position vector: vector from origin to a point P(x,y,z) = xî + yĵ + zk̂.

3. Vector Operations

  • Addition: Triangle law / parallelogram law. a⃗ + b⃗ = (a₁+b₁)î + (a₂+b₂)ĵ + (a₃+b₃)k̂
  • Scalar multiplication: k a⃗ = k(a₁î + a₂ĵ + a₃k̂). Changes magnitude. Direction: same if k>0, opposite if k<0.

4. Dot Product (Scalar Product)

  • a⃗ · b⃗ = |a⃗||b⃗| cos θ = a₁b₁ + a₂b₂ + a₃b₃
  • a⃗ · b⃗ = 0 ⇔ a⃗ ⟂ b⃗ (perpendicular)
  • Commutative. Distributive.
  • Projection of a⃗ on b⃗ = (a⃗·b⃗)/|b⃗|

5. Cross Product (Vector Product)

  • a⃗ × b⃗ = |a⃗||b⃗| sin θ · n̂ (where n̂ is a UNIT VECTOR perpendicular to BOTH a⃗ and b⃗)
  • |a⃗ × b⃗| = AREA of parallelogram formed by a⃗ and b⃗
  • a⃗ × b⃗ = 0⃗ ⇔ a⃗ ∥ b⃗ (parallel)
  • ANTI-COMMUTATIVE: a⃗ × b⃗ = —(b⃗ × a⃗)
  • Determinant form using î,ĵ,k̂

6. Scalar Triple Product

  • [a⃗ b⃗ c⃗] = a⃗ · (b⃗ × c⃗) = determinant of the 3×3 matrix. Volume of parallelepiped.
  • Coplanarity: a⃗, b⃗, c⃗ are coplanar ⇔ [a⃗ b⃗ c⃗] = 0.

7. Exam Focus

  1. Vector basics — position vector, direction cosines. Section formula.
  2. Dot product — a⃗·b⃗ = 0 for perpendicular. Projection formula.
  3. Cross product — |a⃗×b⃗| = area of parallelogram. a⃗×b⃗ = 0 for parallel.
  4. Scalar triple product — volume. Coplanarity test.

8. Conclusion

Vectors are the FOUNDATION of 3D geometry and physics:

  • DOT: Measures ALIGNMENT. 'How much of a points in the direction of b?'
  • CROSS: Measures PERPENDICULARITY. 'The area spanned by a and b — and the direction perpendicular to both.'
  • TRIPLE: 'The volume spanned by three vectors in space.'

'The laws of physics are written in vectors. The dot product and cross product are the grammar of that language.'

Key formulas & results

Everything you need to memorise, in one card. Screenshot this for revision.

Types of Vectors and Basic Operations
MAGNITUDE: If a⃗ = aᵢ î + aⱼ ĵ + aₖ k̂, then |a⃗| = √(aᵢ² + aⱼ² + aₖ²). UNIT VECTOR: â = a⃗/|a⃗|. ZERO VECTOR: 0⃗ has zero magnitude, arbitrary direction. EQUAL VECTORS: same magnitude AND direction. NEGATIVE: −a⃗ has same magnitude, opposite direction. ADDITION (Triangle Law): a⃗ + b⃗ completes the triangle. PARALLELOGRAM LAW: resultant is the diagonal. POSITION VECTOR of point P(x,y,z): OP⃗ = xî + yĵ + zk̂. SECTION FORMULA: point dividing AB in ratio m:n internally: r⃗ = (m·b⃗ + n·a⃗)/(m+n).
COLLINEAR VECTORS: a⃗ and b⃗ are collinear if a⃗ = λb⃗ for some scalar λ (one is a scalar multiple of the other). PARALLEL: collinear in the same direction (λ > 0). ANTI-PARALLEL: collinear in opposite direction (λ < 0). KEY: î, ĵ, k̂ are mutually perpendicular unit vectors. î·î = 1, î·ĵ = 0. î × ĵ = k̂, ĵ × k̂ = î, k̂ × î = ĵ (cyclic order).
Dot Product (Scalar Product)
DEFINITION: a⃗·b⃗ = |a⃗||b⃗|cos θ where θ ∈ [0, π] is the angle between them. COMPONENT FORM: a⃗·b⃗ = a₁b₁ + a₂b₂ + a₃b₃. SPECIAL CASES: a⃗·a⃗ = |a⃗|². Perpendicular vectors: a⃗·b⃗ = 0 (θ = 90°). Parallel vectors: a⃗·b⃗ = |a⃗||b⃗| (θ = 0°). ANGLE: cos θ = (a⃗·b⃗)/(|a⃗||b⃗|). PROJECTION of a⃗ on b⃗ = (a⃗·b⃗)/|b⃗|. PROJECTION VECTOR of a⃗ on b⃗ = [(a⃗·b⃗)/|b⃗|²]·b⃗. PROPERTIES: commutative (a⃗·b⃗ = b⃗·a⃗), distributive over addition.
The dot product is a SCALAR (number), not a vector. Common error: writing a⃗·b⃗ as a vector. For PERPENDICULARITY: if the dot product = 0, the vectors are perpendicular — this is the algebraic test. For î × ĵ = k̂ but î · ĵ = 0.
Cross Product (Vector Product)
DEFINITION: a⃗ × b⃗ = |a⃗||b⃗|sin θ · n̂, where n̂ is the unit vector perpendicular to both (right-hand rule), θ ∈ [0, π]. DETERMINANT FORM: a⃗ × b⃗ = |î ĵ k̂; a₁ a₂ a₃; b₁ b₂ b₃| = î(a₂b₃−a₃b₂) − ĵ(a₁b₃−a₃b₁) + k̂(a₁b₂−a₂b₁). MAGNITUDE: |a⃗ × b⃗| = |a⃗||b⃗|sin θ. PARALLEL VECTORS: a⃗ × b⃗ = 0⃗ (θ = 0° or 180°). AREA OF PARALLELOGRAM with sides a⃗ and b⃗: Area = |a⃗ × b⃗|. AREA OF TRIANGLE with sides a⃗ and b⃗: Area = ½|a⃗ × b⃗|. PROPERTIES: ANTI-commutative: a⃗ × b⃗ = −(b⃗ × a⃗). NOT associative.
The cross product is a VECTOR (unlike dot product which is a scalar). The sign in the determinant expansion: +î, −ĵ, +k̂ (standard cofactor pattern). Common error: missing the negative sign before ĵ. Also: a⃗ × a⃗ = 0⃗ (cross product with itself is zero). For UNIT VECTORS: î × ĵ = k̂, ĵ × k̂ = î, k̂ × î = ĵ. Reversed: ĵ × î = −k̂.
Scalar Triple Product and Coplanarity
SCALAR TRIPLE PRODUCT: [a⃗ b⃗ c⃗] = a⃗·(b⃗ × c⃗). In determinant form: [a⃗ b⃗ c⃗] = |a₁ a₂ a₃; b₁ b₂ b₃; c₁ c₂ c₃|. GEOMETRIC MEANING: |[a⃗ b⃗ c⃗]| = volume of parallelepiped with edges a⃗, b⃗, c⃗. COPLANARITY TEST: a⃗, b⃗, c⃗ are COPLANAR ⟺ [a⃗ b⃗ c⃗] = 0 (volume of parallelepiped = 0). PROPERTIES: [a⃗ b⃗ c⃗] = [b⃗ c⃗ a⃗] = [c⃗ a⃗ b⃗] (cyclic permutation preserves value). [a⃗ b⃗ c⃗] = −[a⃗ c⃗ b⃗] (swap any two → sign changes).
Scalar triple product gives a SCALAR (despite combining two vector operations). Volume of tetrahedron with edges a⃗, b⃗, c⃗ = (1/6)|[a⃗ b⃗ c⃗]|. For coplanarity of four points A, B, C, D: check if vectors AB⃗, AC⃗, AD⃗ have scalar triple product = 0.
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Common mistakes & fixes

These are the exact errors that cost students marks in board exams. Read them once, save yourself the trouble.

WATCH OUT
Forgetting the negative sign before ĵ in the cross product determinant expansion
The cross product a⃗ × b⃗ expands as: +î(a₂b₃−a₃b₂) − ĵ(a₁b₃−a₃b₁) + k̂(a₁b₂−a₂b₁). The ĵ term has a NEGATIVE sign. This follows from the cofactor sign pattern (+ − +) for the first row. After computing the ĵ minor (a₁b₃−a₃b₁), multiply by −1. Forgetting this negative sign is the most common cross product error.
WATCH OUT
Treating the cross product as commutative (writing a⃗ × b⃗ = b⃗ × a⃗)
Cross product is ANTI-COMMUTATIVE: a⃗ × b⃗ = −(b⃗ × a⃗). The direction of the result reverses when operands are swapped. Dot product IS commutative (a⃗·b⃗ = b⃗·a⃗). For area of triangle using ½|a⃗ × b⃗|, the order doesn't matter (we take magnitude), but in other contexts the sign matters.
WATCH OUT
Using cos θ = (a⃗·b⃗)/(|a⃗||b⃗|) to find angle and getting θ > 90° from dot product
If the dot product is negative, cos θ < 0, which means θ ∈ (90°, 180°). This is valid — vectors can make an obtuse angle. Accept θ = cos⁻¹(negative value) as the answer (e.g., θ = 2π/3 = 120°). Do NOT take |dot product| — the angle between vectors is measured in [0°, 180°], and a negative dot product correctly gives an obtuse angle.

Practice problems

Try each one yourself before tapping "Show solution". Active recall > rereading.

Q1EASY· dot-product-angle
Find the angle between a⃗ = 2î − ĵ + k̂ and b⃗ = î + ĵ − 2k̂.
Show solution
a⃗·b⃗ = (2)(1) + (−1)(1) + (1)(−2) = 2 − 1 − 2 = −1. |a⃗| = √(4+1+1) = √6. |b⃗| = √(1+1+4) = √6. cos θ = (a⃗·b⃗)/(|a⃗||b⃗|) = −1/(√6·√6) = −1/6. θ = cos⁻¹(−1/6). The angle between the vectors is cos⁻¹(−1/6).
Q2MEDIUM· cross-product-area
Find the area of a triangle with vertices A(1, 2, 3), B(2, −1, 4), C(4, 5, −1).
Show solution
AB⃗ = B − A = (2−1)î + (−1−2)ĵ + (4−3)k̂ = î − 3ĵ + k̂. AC⃗ = C − A = (4−1)î + (5−2)ĵ + (−1−3)k̂ = 3î + 3ĵ − 4k̂. AB⃗ × AC⃗ = |î ĵ k̂; 1 −3 1; 3 3 −4|. = î[(−3)(−4)−(1)(3)] − ĵ[(1)(−4)−(1)(3)] + k̂[(1)(3)−(−3)(3)]. = î[12−3] − ĵ[−4−3] + k̂[3+9]. = 9î + 7ĵ + 12k̂. |AB⃗ × AC⃗| = √(81+49+144) = √274. Area of triangle = ½|AB⃗ × AC⃗| = ½√274 square units.
Q3HARD· scalar-triple-product
Show that vectors a⃗ = î − 2ĵ + 3k̂, b⃗ = −2î + 3ĵ − 4k̂, c⃗ = î − 3ĵ + 5k̂ are coplanar.
Show solution
For coplanarity: [a⃗ b⃗ c⃗] = a⃗·(b⃗ × c⃗) must equal 0. Compute using determinant: [a⃗ b⃗ c⃗] = |1 −2 3; −2 3 −4; 1 −3 5|. Expand along Row 1: = 1·|3 −4; −3 5| − (−2)·|−2 −4; 1 5| + 3·|−2 3; 1 −3|. = 1·(15−12) + 2·(−10+4) + 3·(6−3). = 1·(3) + 2·(−6) + 3·(3). = 3 − 12 + 9. = 0. Since [a⃗ b⃗ c⃗] = 0, the three vectors are COPLANAR. ✓

5-minute revision

The whole chapter, distilled. Read this the night before the exam.

  • a⃗·b⃗ = a₁b₁+a₂b₂+a₃b₃ = |a⃗||b⃗|cos θ. Perpendicular ⟺ dot product = 0.
  • a⃗ × b⃗ = |î ĵ k̂; a₁ a₂ a₃; b₁ b₂ b₃|. Expansion: +î(minor) − ĵ(minor) + k̂(minor).
  • a⃗ × b⃗ = −(b⃗ × a⃗). Anti-commutative. |a⃗ × a⃗| = 0.
  • Area of parallelogram = |a⃗ × b⃗|. Area of triangle = ½|a⃗ × b⃗|.
  • Scalar triple product [a⃗ b⃗ c⃗] = det of 3×3 matrix. Coplanar ⟺ [a⃗ b⃗ c⃗] = 0.
  • Projection of a⃗ on b⃗ = (a⃗·b⃗)/|b⃗|. Projection vector = [(a⃗·b⃗)/|b⃗|²]b⃗.
  • Unit vector: â = a⃗/|a⃗|.
  • î × ĵ = k̂, ĵ × k̂ = î, k̂ × î = ĵ (cyclic). î·ĵ = 0, î·î = 1.

CBSE marks blueprint

Where the marks come from in this chapter — so you can plan your prep.

Typical chapter weightage: 6-8 marks

Question typeMarks eachTypical countWhat it tests
Short — Dot/Cross Product Application3-41Find angle between vectors; find projection; check perpendicularity; area of triangle/parallelogram
Long — Scalar Triple Product / Combined4-51Coplanarity using scalar triple product; find unit vector perpendicular to two vectors; combined dot-cross problems
Prep strategy
  • Cross product determinant: write the 3×3 with î, ĵ, k̂ in row 1, vector a components in row 2, vector b components in row 3. Expand along row 1 using cofactors (+−+). Show all three cofactors explicitly — each sub-determinant earns a mark.
  • For angle problems: compute dot product first, then compute both magnitudes, then divide. Write each step on a separate line. The final answer as cos⁻¹(value) is acceptable — you do NOT need to find the decimal angle.
  • Memorise î × ĵ = k̂, ĵ × k̂ = î, k̂ × î = ĵ and their reverses (with negative signs). These appear directly in shortcut cross product evaluations.

Where this shows up in the real world

This chapter isn't just an exam topic — it lives in the world around you.

Torque and Angular Motion in Engineering

Torque — the rotational equivalent of force — is defined as τ⃗ = r⃗ × F⃗ (the cross product of position vector and force). The magnitude |r⃗ × F⃗| = |r⃗||F⃗|sin θ shows that maximum torque occurs when the force is perpendicular to the lever arm (θ = 90°, sin = 1). Every wrench, gear, engine crankshaft, and robotic arm uses cross products. Electric motors, wind turbines, and the gyroscopic stabilisers in aircraft and ships all depend on cross product physics.

Exam strategy

Battle-tested tips from teachers and toppers for this chapter.

  1. For cross product: expand the determinant in full, showing all three 2×2 sub-determinants. Write: 'a⃗ × b⃗ = î(a₂b₃−a₃b₂) − ĵ(a₁b₃−a₃b₁) + k̂(a₁b₂−a₂b₁).' Then substitute values. Never try to compute it mentally — arithmetic errors in cross products cost 3-4 marks.
  2. When asked to show coplanarity using scalar triple product: write the 3×3 determinant explicitly, expand along any row, and conclude 'Since [a⃗ b⃗ c⃗] = 0, the vectors are coplanar.' This structured approach earns all partial marks.

Going beyond the textbook

For olympiad aspirants and curious learners — topics that build on this chapter.

  • Study the VECTOR TRIPLE PRODUCT identity: a⃗ × (b⃗ × c⃗) = b⃗(a⃗·c⃗) − c⃗(a⃗·b⃗). This 'BAC-CAB' rule converts a double cross product into a combination of dot products — essential in electromagnetic field theory and fluid mechanics
  • Explore QUATERNIONS (discovered by Hamilton in 1843): a 4D number system i²=j²=k²=ijk=−1 that generalises complex numbers and encodes 3D rotations without the 'gimbal lock' problem of Euler angles. Every modern 3D game engine and drone flight controller uses quaternion mathematics for rotation

Where else this chapter is tested

CBSE board isn't the only one — other exams test this chapter too.

CBSE Class 12 Board (Mathematics)High
JEE Main (Vector Algebra)High
CUET (Mathematics)Medium

Questions students ask

The real ones — pulled from the Q&A community and tutor sessions.

DOT PRODUCT (a⃗·b⃗ = |a⃗||b⃗|cos θ): measures how much one vector PROJECTS onto another. It gives a SCALAR. It is zero when vectors are perpendicular (cos 90° = 0). Maximum when parallel (cos 0° = 1). CROSS PRODUCT (|a⃗ × b⃗| = |a⃗||b⃗|sin θ): measures the area of the parallelogram formed by the two vectors. It gives a VECTOR perpendicular to both. It is zero when vectors are parallel (sin 0° = 0). Maximum when perpendicular (sin 90° = 1). Summary: dot product ↔ projection/angle, cross product ↔ area/perpendicular direction.
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Last reviewed on 27 May 2026. Written and reviewed by subject-matter experts — read about our process.
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