By the end of this chapter you'll be able to…

  • 1Solve compound-position questions (Nth to the left of Mth from the right)
  • 2Count 'immediately preceded/followed by' patterns without direction errors
  • 3Use EJOTY landmarks and the 27−position rule for alphabet questions
  • 4Apply string transformations (drop symbols, reverse) before answering
  • 5Avoid boundary and off-by-one counting traps
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Why this chapter matters in IBPS PO
Alphanumeric series are 3–5 quick Prelims marks won by careful condition-reading and clean counting, not cleverness. The EJOTY letter-position landmarks make the alphabet variants instant, and the preceded-vs-followed discipline transfers to other scanning questions. It's a low-effort, high-accuracy block that helps clear the reasoning sectional cut.

Alphanumeric & Alphabet Series — IBPS PO Reasoning

An alphanumeric series is a string mixing letters, numbers and symbols — e.g. P 3 @ K 7 M % 2 R… — followed by quick questions: which element is third to the left of the seventh from the right, how many numbers are immediately followed by a symbol, and so on. These are 3–5 fast Prelims marks. The skill is not cleverness but careful condition-reading and clean counting, plus the EJOTY letter-position landmarks for the alphabet-based variants. Get the counting discipline right and these are 20-second wins.


1. What IBPS actually asks

  • "Which element is Nth from the left/right?" — direct position counting.
  • "Nth to the left of the Mth from the right" — a compound position (the classic).
  • "How many numbers/letters/symbols are immediately preceded/followed by …?" — pattern-matching counts.
  • Alphabet series: letter gaps, "which letter is Nth to the right of X", and word-based rearrangements (see also Coding–Decoding).

2. The compound-position rule (the classic question)

"3rd to the left of the 7th from the right" is done in two steps:

  1. Find the anchor: the 7th from the right — count 7 in from the right end.
  2. Move from the anchor: 3 positions to its left.

Do it in the stated order: locate the from-the-right/left reference first, then step the second count. A quick tip for a single string: "Nth to the left of Mth from the right" = (M + N)th from the right — but only verify with the actual string until the shortcut is second nature.


3. Counting "immediately preceded / followed by"

These are pattern-scans across the string:

  • "A number immediately followed by a symbol" → scan for the pattern number, symbol (in that order) and count each occurrence.
  • "Immediately preceded by" flips the order: symbol, number means the number is preceded by a symbol.
  • Watch the boundary: the first element has nothing before it, the last has nothing after — they can't satisfy a "preceded/followed" condition on the missing side.

Read whether it's preceded (the thing comes before) or followed (the thing comes after). Swapping these is the single biggest error, and the two answers usually differ.


4. Alphabet series & EJOTY

For letter-position questions, anchor with the EJOTY landmarks so you never count from A:

E = 5, J = 10, O = 15, T = 20, Y = 25.

  • "Which letter is 5th to the right of the 12th letter?" → 12th = L; 5 right = 17th = Q (O=15, +2).
  • Opposite letter: position from the other end = 27 − position (A↔Z, B↔Y).
  • Gap between letters: subtract their positions.

5. New-pattern variants

IBPS sometimes adds a rule layer: "if each symbol is dropped, which is 4th from the left?", or "after reversing the string, …". Apply the transformation to the string first (rewrite it), then answer normally. Never try to count on the original and the transformed string at once.


Solved examples

Question 1 of 4

Q1 (compound position). String: P 3 @ K 7 M % 2 R 9 B. Which is 2nd to the left of the 4th from the right?

Show explanation

Solution. 4th from right: counting from the right (B,9,R,2) → the 4th is 2. 2nd to its left: from 2, two left = M. Answer: M.

Question 2 of 4

Q2 (count followed by). In P 3 @ K 7 M % 2 R 9 B, how many numbers are immediately followed by a letter?

Show explanation

Solution. Scan number,letter: 7→M ✓, 2→R ✓, 9→B ✓ (3 is followed by @, no). Answer: 3.

Question 3 of 4

Q3 (alphabet). Which letter is 4th to the right of the 11th letter from the left?

Show explanation

Solution. 11th = K; 4 to the right = 15th = O (EJOTY).

Question 4 of 4

Q4 (opposite). What is the 6th letter from the right in the English alphabet?

Show explanation

Solution. 6th from right = 27 − 6 = 21st = U.


7. The protocol

  1. Number the string lightly if it helps, or count carefully from the stated end.
  2. Compound positions: find the "from-the-end" anchor first, then step the second count.
  3. Preceded vs followed: confirm direction; scan for the exact ordered pattern; mind the boundaries.
  4. Alphabet questions: anchor on EJOTY; use 27 − position for opposites.
  5. Transformed strings: apply the rule to rewrite the string first, then answer.

Key formulas & results

Everything to memorise for the exam hall, in one card. Screenshot this for revision.

Compound position
Nth to the left of Mth from the right = (M+N)th from the right (single string)
Verify against the actual string until automatic.
Preceded vs followed
'followed by' = pattern X,Y (Y after X); 'preceded by' = Y,X
Direction reversal is the #1 error.
EJOTY
E=5, J=10, O=15, T=20, Y=25
Anchor letter positions without counting from A.
Opposite letter
position from the other end = 27 − position
A↔Z, B↔Y.
Boundary rule
First element has nothing before it; last has nothing after
They can't satisfy the missing-side condition.
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Traps IBPS PO sets — and how to dodge them

These are the exact option-traps and misreads that cost marks under negative marking.

WATCH OUT
Swapping 'immediately preceded by' and 'immediately followed by'
'Followed by' means the second thing comes AFTER; 'preceded by' means it comes BEFORE. Scan for the exact ordered pattern — the two counts usually differ.
WATCH OUT
Doing the compound position in the wrong order
Locate the 'from-the-end' anchor first, then step the second count from it. Reversing the order lands you on the wrong element.
WATCH OUT
Counting alphabet positions from A every time
Anchor on EJOTY (E5, J10, O15, T20, Y25) and step a few from the nearest landmark. For opposites use 27 − position.
WATCH OUT
Ignoring boundary elements
The first element can't be 'preceded' and the last can't be 'followed'. Don't count them for the missing-side condition.
WATCH OUT
Answering on the original string when a transformation is asked
If the question says 'after dropping symbols' or 'after reversing', rewrite the string first, then count on the new string.

Exam-pattern practice

PYQ-style questions with full solutions. Work through them as a readiness check — mark yourself honestly and get your gap report at the end.

Readiness check

Are you exam-ready for Alphanumeric & Alphabet Series?

6 problems from this chapter. Try each one, reveal the worked solution, mark yourself honestly — get your gap report at the end.

6 questions~4 min worth ~5 marks in IBPS PO exams

5-minute revision

The whole chapter, distilled. Read this the night before the exam.

  • Read the exact condition — preceded (before) vs followed (after).
  • Compound position: find the from-the-end anchor first, then step.
  • Nth left of Mth from right = (M+N)th from right (single string).
  • EJOTY: E5, J10, O15, T20, Y25; opposite = 27 − position.
  • First element can't be preceded; last can't be followed.
  • Apply any transformation (drop symbols/reverse) to the string first.
  • Count carefully — these are off-by-one traps, not hard logic.

IBPS PO question blueprint

How this topic is asked, tier by tier — so you can prep to the pattern.

Typical weightage: Prelims: 3–5 marks (of 40) · Mains: 0–2 marks (of 60)

Question styleMarks eachTypical countWhat it tests
Compound position1 each1–2Nth-left-of-Mth-from-right counting
Preceded/followed counts1 each1–2Ordered-pattern scanning
Alphabet position1 each1EJOTY and opposite-letter rules
Prep strategy
  • Day 1: memorise EJOTY and the 27−position rule.
  • Day 2: 15 mixed strings daily, focusing on preceded-vs-followed accuracy.
  • Day 3: transformation variants (drop symbols/reverse) under a 20-second cap.

Exam-hall strategy

Battle-tested tips from mentors and toppers for this topic under the sectional clock.

  1. Read the exact condition (preceded vs followed) before counting.
  2. For compound positions, anchor on the from-the-end reference first.
  3. Use EJOTY and 27−position for alphabet questions.
  4. Rewrite the string for any transformation before answering.
  5. Mind boundary elements; target 20 seconds per question.

Beyond the exam

Where this skill shows up in the job you're competing for — and in life.

Careful data reading

Scanning a string for an exact ordered pattern is the same precision needed when reading account numbers or reference codes.

Attention to condition

The preceded-vs-followed discipline trains the exact-condition reading that prevents processing errors at a bank desk.

Where else this topic is tested

Prepare once, score in every exam that asks it.

IBPS Clerk / SBI ClerkVery high — a larger share of the reasoning section
SBI PO / RRB PO & ClerkHigh — 3–5 questions per paper
SSC CGLMedium — alphabet-position questions

Questions aspirants ask

Pulled from the Q&A community and mentor sessions.

Usually 3–5 in Prelims and occasionally a couple in Mains. They're fast, counting-based marks that help clear the reasoning sectional cut.

Find the Mth-from-the-right element first, then move N places to its left. For a single string it equals the (M+N)th element from the right — but verify against the string until you trust the shortcut.

Because the direction is easy to flip. 'Followed by' puts the second element AFTER; 'preceded by' puts it BEFORE. Scan for the exact ordered pair and remember the first/last elements can't satisfy the missing-side condition.

EJOTY is a memory aid for letter positions: E=5, J=10, O=15, T=20, Y=25. Counting from the nearest landmark (rather than from A) makes alphabet-position questions almost instant.
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