By the end of this chapter you'll be able to…

  • 1State what makes a collection a set - well-defined and distinct - and decide whether a given collection qualifies
  • 2Use the membership symbols for belongs to and does not belong to correctly in both directions
  • 3Write a set in roster form, dropping repeats and treating order as immaterial
  • 4Write a set in set-builder form, reading the colon as 'such that', and convert freely between the two forms
  • 5Recognise an empty set from its description, and distinguish the empty set from the set containing zero
  • 6Identify the universal set in a problem and draw it as the rectangle of a Venn diagram
  • 7Decide whether one set is a subset of another, and distinguish a proper subset from a subset
  • 8List all the subsets of a small finite set, including the empty set and the set itself
  • 9Compute the union, intersection and difference of two given sets, and shade each on a Venn diagram
  • 10Recognise disjoint sets and state that their intersection is the empty set
  • 11Prove two sets equal by showing each is a subset of the other
  • 12Classify a set as finite or infinite and state the cardinality of a finite set, including n(empty set) = 0
💡
Why this chapter matters
Sets is the chapter that hands you the language the rest of mathematics is written in. The number systems you have been using since class 6 - naturals, integers, rationals, reals - are named and related here for the first time as sets, and the chain N is a subset of Z is a subset of Q is a subset of R is the statement chapter 1's irrationality proofs were really about. Beyond the syllabus, the ideas transfer almost unchanged: a database query is set-builder notation, a search that asks for 'A and B' is an intersection, and the counting rule that the last Think-and-discuss box points at is the first case of inclusion-exclusion, which reappears in Probability in chapter 13 of this same book. It is also the cheapest chapter in the book to score full marks in, provided the vocabulary is exact.

Sets

1. What This Chapter Covers

The chapter opens with a question that is not about mathematics at all: when you are asked to describe a person, how would you do it?

The book's four examples answer it the same way each time:

  • Ramanujan was a mathematician, interested in number theory.
  • Dasarathi was a Telugu poet and also a freedom fighter.
  • Albert Einstein was a physicist who proposed the theory of relativity.
  • Maryam Mirzakhani is the only woman mathematician to win the Fields Medal.

Every one of those puts the person into a larger recognisable group first — mathematician, poet, physicist — and only then adds the specific detail. That is what classification is, and the book points out we do it everywhere: library books are shelved by subject, chemical elements are sorted into groups and classes, and your own mathematics syllabus is cut into 14 chapters under different headings.

The book's fourth example is no longer accurate. Maryna Viazovska won the Fields Medal in 2022, two years before this impression was printed, so Maryam Mirzakhani is the first woman to win it, not the only one. The name is also printed "Mirzakhan". Reproduced here as printed, with the correction noted.

The opening box gives a real classification to hold on to: the dental formula. Human permanent teeth divide into four types by chewing function — incisors, canines, premolars and molars — and the formula for that set is 2, 1, 2, 3. The teeth come back three more times in this chapter, as the example for universal sets and subsets.

The chapter is allotted 8 periods in June and runs from textbook page 28 to page 50.

2. What a Set Is

Before any notation, the book lists the number collections you already use:

SymbolCollection
ℕnatural numbers 1, 2, 3, …
𝕎whole numbers 0, 1, 2, 3, …
𝕀 or ℤintegers 0, ±1, ±2, ±3, …
ℚrational numbers, those that can be written as p/q with p, q integers and q ≠ 0
ℝreal numbers, those that have a decimal expansion

Then the definition, which is three conditions packed into one line:

A set is a well-defined collection of distinct objects. The objects in a set are called elements. Sets are written by enclosing all of its elements between the brackets { }.

Well-defined is the load-bearing word. It means that for any object you name, there is no argument about whether it is in the collection. "The first five prime numbers" is well-defined: {2, 3, 5, 7, 11}. "The ten most talented writers of India" is not, because two people will disagree about the list — which is exactly why Exercise 2.1 asks you to sort five collections into sets and non-sets.

Distinct is the second condition, and it is the one that shows up in marks. An element is never repeated: the set of letters in the word SCHOOL is {s, c, h, o, l}, not {s, c, h, o, o, l}.

Membership has its own symbol. "Second molar is in the set of molars" is written second molar ∈ M, read "second molar belongs to set M". The negation is square ∉ M, read "square does not belong to the set M".

3. Roster Form and Set-Builder Form

Sets are named with capital letters — A, B, C — and written down in one of two ways.

Roster form lists the elements. M = {first molar, second molar, third molar}. Q = {square, rectangle, rhombus, parallelogram, kite, isosceles trapezium}, the set of quadrilaterals with at least two equal sides.

The book attaches two notes to roster form, and both are examinable:

  1. The order is immaterial. The digits of the Ramanujan number can be written {7, 2, 1, 9} or {1, 2, 7, 9} or {1, 7, 2, 9}; they are the same set.
  2. An element is not repeated, as with SCHOOL above.

Roster form breaks down when the set is infinite. Can you write ℚ by listing its elements? The book's Think and discuss box asks exactly that, and the answer is no — which forces the second notation.

Set-builder form describes the elements by a common property instead of naming them.

Set-builder form, read left to right A = { x : x is a multiple of 3 and x < 20 } the set of all x such that the property x must have The same set in roster form: A = {3, 6, 9, 12, 15, 18}

The colon is always read "such that"; everything after it is the test an object has to pass to get in.

The same syntax writes the rationals compactly: ℚ = {x : x = p/q, p and q are integers and q ≠ 0}.

The book puts four sets side by side in both forms:

Roster formSet-builder form
V = {a, e, i, o, u}V = {x : x is a vowel in the English alphabet}
A = {−2, −1, 0, 1, 2}A = {x : −2 ≤ x ≤ 2, x ∈ ℤ}
B = {1, 1/2, 1/3, 1/4, 1/5}B = {x : x = 1/n, n ∈ ℕ, n ≤ 5}
C = {2, 5, 10, 17}C = {x : x = n² + 1, n ∈ ℕ, n ≤ 4}

Read the last row backwards to check it: n = 1, 2, 3, 4 gives 2, 5, 10, 17.

4. The Empty Set

Some descriptions pass the well-defined test and still catch nothing.

  • A = {x : x is a natural number smaller than 1} — there is no such natural number.
  • D = {x : x is an odd number divisible by 2} — there is no such number either.

A set which does not contain any element is called an empty set, or a Null set, or a void set. It is denoted by φ or { }.

Three more of the book's examples, each empty for a different reason: {x : 1 < x < 2, x is a natural number}; {x : x² − 2 = 0 and x is rational}, which is empty because √2 is irrational — the result proved in chapter 1; and {x : x² = 4, x is an odd number}.

The book then prints a Note that is worth its own figure, because it is the single most common slip in the chapter.

φ and {0} are not the same set φ or { } no elements at all { 0 } 0 φ has no elements: n = 0 {0} has one element: n = 1

Zero is a perfectly good element; a box containing a zero is not an empty box.

5. The Universal Set and Venn Diagrams

Go back to the teeth. You split the whole set into incisors, canines, premolars and molars — but are the molars still members of the whole teeth set? Obviously yes. The whole teeth set is the universal set of those four.

The universal set is the frame of reference: everything under discussion in a particular problem lives inside it. If you are studying groups of people in Telangana, the universal set is all the people in Telangana; if you are studying groups in India, it is everyone in India.

The universal set is generally denoted by μ, and sometimes by U. It is usually drawn as a rectangle.

Using μ for the universal set is this book's convention and is worth noticing, because other books write U or ξ for the same thing.

A Venn diagram — properly a Venn-Euler diagram — draws the universal set as a rectangle and the sets inside it as closed curves, usually circles.

The rectangle is everything; the oval is the subset μ A 2 4 6 8 10 1 3 5 7 9 Everything under discussion lives in μ, drawn as the rectangle.

The book asks what the empty part of the diagram represents; it is every member of μ that is not in A.

Two symbols get introduced in a side box here and are used from now on. "If x < 3 then x < 4" is written with a one-way implication arrow, and "x − 2 = 5 exactly when x = 7" with a two-way implication, read "if and only if" and often shortened to iff.

6. Subsets

Take A = {1, 2, 3}. How many sets can you build using as many of its elements as you like?

There are eight: { }, {1}, {2}, {3}, {1, 2}, {2, 3}, {1, 3} and {1, 2, 3}. Every one of them is a subset of A — including the empty set at one end and A itself at the other.

If all elements of set A are present in B, then A is said to be a subset of B, written A ⊆ B. Equivalently, A ⊆ B if and only if a ∈ A implies a ∈ B.

Two consequences are boxed in the book:

Null set is a subset of every set. If φ were not a subset of A, it would have to contain an element that is not in A — and it contains no elements at all.

Every set is a subset of itself. Every element of A is an element of A.

When B sits inside A but does not fill it, B is a proper subset. The vowels V = {a, e, i, o, u} are a proper subset of the alphabet A = {a, b, c, …, z}, because every vowel is a letter but not every letter is a vowel.

The book states on page 37 that ⊂ denotes a proper subset and ⊆ denotes a subset. It then uses ⊂ loosely for "subset" elsewhere — writing A ⊂ A for "every set is a subset of itself" on page 36, and defining subset with ⊂ in the chapter summary. Strictly, a set is never a proper subset of itself. Read ⊂ in this book as "subset" unless the sentence is drawing the distinction.

Inside, or only overlapping? a proper subset A 1 3 C 5 7 9 every element of A is in C, so A ⊂ C not a subset A B 3 1 5 9 3 ∈ A but 3 ∉ B, so A ⊄ B

Sharing some elements is not enough; a subset needs every one of its elements to be in the larger set.

The number systems give a chain of subsets: ℕ ⊂ ℤ ⊂ ℚ ⊂ ℝ, and also ℚ' ⊂ ℝ, where ℚ' is the set of irrationals — every real that is not rational, so ℚ' = {x : x ∈ ℝ and x ∉ ℚ}. But ℕ ⊄ ℚ': no natural number is irrational.

7. Union, Intersection and Difference

Arithmetic has addition, subtraction, multiplication and division. Sets have three operations of their own, and the book introduces all three through one situation: μ is everyone in your school, A is the students in your class absent on Tuesday, B those absent on Wednesday.

A = {Roja, Ramu, Ravi} and B = {Ramu, Preethi, Haneef}.

Union. Who was absent on Tuesday or Wednesday? Roja, Ramu, Ravi, Haneef and Preethi — but not Akhila, who is always present.

A ∪ B = {x : x ∈ A or x ∈ B}, read "A union B".

Intersection. Who was absent on Tuesday and Wednesday? Only Ramu.

A ∩ B = {x : x ∈ A and x ∈ B}, read "A intersection B".

Difference. Which odd numbers under 10 are not prime? With A = {1, 3, 5, 7, 9} and B = {3, 5, 7}, the answer is {1, 9}.

A − B = {x : x ∈ A and x ∉ B}, read "A difference B" or "A minus B".

The same two sets, three different regions A B A ∪ B A B A ∩ B A B A − B

Union takes everything either circle holds, intersection only the overlap, difference only the part of A the overlap leaves behind.

Four results follow from the definitions and are worth holding:

  • The common element is written once. {2, 5, 6, 8} ∪ {5, 7, 9, 1} = {1, 2, 5, 6, 7, 8, 9}, not eight elements.
  • If B ⊂ A then A ∪ B = A. Adding a subset back in adds nothing new.
  • Sets with no common element are disjoint, and for them A ∩ B = φ. {1, 3, 5, 7} and {2, 4, 6, 8} are disjoint; their Venn circles are drawn apart.
  • A − B ≠ B − A. With A = {1, 2, 3, 4, 5} and B = {4, 5, 6, 7}, A − B = {1, 2, 3} while B − A = {6, 7}. Subtraction of sets is no more symmetric than subtraction of numbers.

A Think and discuss box adds a fourth observation to check for yourself: A − B, B − A and A ∩ B are mutually disjoint, and together they make up A ∪ B.

8. Equal Sets

Three sets of cricketers:

  • A = {Sachin, Dravid, Kohli}
  • B = {Dravid, Sachin, Dhoni}
  • C = {Kohli, Dravid, Sachin}

A and C contain exactly the same players in a different order, so they are equal. A and B are not, because Kohli is in one and Dhoni in the other.

Two sets A and C are equal if every element of A belongs to C and every element of C belongs to A — that is, A ⊆ C and C ⊆ A. Written A = C.

The two-way condition is the whole definition, and it is why equality is usually proved in two halves. Example 11 is the model: C is the set of letters in ASSASSINATION and B the set of letters in STATION. Written in roster form with repeats dropped, both are {A, S, I, N, T, O}, so C ⊆ B and B ⊆ C, hence C = B.

Example 9 is the contrast: A = {1, 2, 3} and B = {1, 2, 3, 4}. Here A ⊂ B but B ⊄ A, so A ≠ B. One-way containment is not equality.

Example 10 uses the same test on two differently-described sets: the primes smaller than 6 are {2, 3, 5}, and the prime factors of 30 are also 2, 3 and 5, so the two sets are equal despite having nothing in common in their wording.

9. Finite Sets, Infinite Sets and Cardinality

Some sets you can count to the end of, and some you cannot.

  • A = {the students of your school} — countable, however large the school.
  • L = {2, 3, 5, 7} — four elements.
  • B = {x : x is an even number} — no end.
  • J = {x : x is a multiple of 7} — no end either.

A set whose number of elements can be expressed as a definite whole number is a finite set. Otherwise it is an infinite set.

The book's further examples separate the idea from mere size: the days of the week form a finite set; the solutions of x² − 16 = 0 form a finite set with two elements; but the points on a line, or the lines through a single point, form infinite sets.

Example 13 is a useful drill because the answers do not match first impressions. {x : x ∈ ℕ and x² = 4} looks like it should have two elements, but −2 is not a natural number, so the set is {2} and finite. {x : x ∈ ℕ and 2x − 2 = 0} is {1}, finite. {x : x ∈ ℕ and x is prime} is infinite, because the primes never run out.

For a finite set, the count itself gets a name.

The number of elements in a finite set is called the cardinal number, or the cardinality, of the set, written n(A).

With A = {1, 2, 4}, B = {6, 7, 8, 9, 10} and C = {x : x is a letter in the word INDIA}, we get n(A) = 3, n(B) = 5 and n(C) = 4 — because I repeats in INDIA and elements of a set are distinct, so C = {I, N, D, A}.

The note that follows is the counterpart of the φ versus {0} warning: n(φ) = 0. The empty set is finite, and its count is zero.

Example 14 then sets a trap deliberately. With A = {1, 2, 3, 4, 5} and B = {2, 4, 6, 8}, n(A) = 5 and n(B) = 4, yet A ∪ B = {1, 2, 3, 4, 5, 6, 8} has seven elements, not nine.

Why 5 + 4 is not 7 μ A B 1 3 5 2 4 6 8 n(A) = 5 and n(B) = 4, but n(A ∪ B) = 7, not 9, because 2 and 4 were counted twice.

The two elements in the overlap belong to both sets, so adding the counts charges for them twice.

The book leaves the fix as its closing Think and discuss: what is the relation between n(A), n(B), n(A ∩ B) and n(A ∪ B), and what happens when A and B are disjoint?

Working the example backwards answers both. Here n(A ∩ B) = 2, and 5 + 4 − 2 = 7, so n(A ∪ B) = n(A) + n(B) − n(A ∩ B). When the sets are disjoint that last term is zero and the counts simply add.

Note that the book poses this only as a question and never states the formula as a result, so quote it as reasoning from Example 14 rather than as a textbook theorem.

10. What the Exercises Ask, and What the Book Answers

The chapter carries four numbered exercises, and unusually for this book all four have printed answers, at textbook pages 371 to 373.

  • Exercise 2.1 (8 questions) is about notation: which collections are sets, filling ∈ or ∉, writing statements in symbols, true-or-false with justification, and converting between roster and set-builder form in both directions.
  • Exercise 2.2 (7 questions) drills union, intersection and difference, including the ten-part question on A − B, A − C, A − D and so on for four given sets.
  • Exercise 2.3 (5 questions) is equality and subsets, ending with listing all the subsets of five given sets — the answer for a four-element set runs to sixteen.
  • Exercise 2.4 (2 questions) sorts sets into empty or not, and finite or infinite.

Two answers in that key are wrong, and both are in Exercise 2.2 question 5, where A is the naturals, B the even naturals, C the odd naturals and D the primes:

  • B ∩ D is printed as "{even natural number}". The even naturals and the primes share exactly one member, so B ∩ D = {2}.
  • A ∩ D is printed as {2, 3, 5, 7, 11, …, 97}. A is every natural number and D is every prime, so A ∩ D is the whole infinite set of primes; stopping at 97 has no basis in the question.

Check your own work against the key, but not blindly.

11. Summary

A set is a well-defined collection of distinct objects, written inside braces; membership is ∈ and non-membership ∉. Well-defined means no one can argue about whether a given object is in; distinct means nothing is listed twice.

It can be written in roster form, listing the elements, where order does not matter and repeats are dropped; or in set-builder form, {x : x has some property}, with the colon read "such that". Infinite sets force the second form.

The empty set φ has no elements and n(φ) = 0, and it is not the same as {0}. The universal set μ is the frame everything in a problem sits inside, drawn as a rectangle in a Venn diagram.

A is a subset of B when every element of A is in B. The empty set is a subset of every set, and every set is a subset of itself; a proper subset leaves something out. For the number systems, ℕ ⊂ ℤ ⊂ ℚ ⊂ ℝ and ℚ' ⊂ ℝ, but ℕ ⊄ ℚ'.

Three operations: A ∪ B collects elements in either set, A ∩ B only those in both, and A − B those in A but not B. Sets with A ∩ B = φ are disjoint, and A − B is generally not B − A.

Two sets are equal when each is a subset of the other — a two-way test, which is why one-way containment such as {1, 2, 3} ⊂ {1, 2, 3, 4} does not make them equal.

A set is finite if its element count is a whole number and infinite otherwise, and for a finite set that count is its cardinality n(A). Because shared elements belong to both sets, n(A ∪ B) is not n(A) + n(B) unless the sets are disjoint.

Key formulas & results

Everything you need to memorise, in one card. Screenshot this for revision.

Set-builder form
A = {x : x has some property}
The colon is read 'such that'. Example: A = {x : x is a multiple of 3 and x < 20} is the same set as {3, 6, 9, 12, 15, 18}.
Membership
a belongs to A ; a does not belong to A
Written with the epsilon-like symbol and its struck-through form. Membership relates an ELEMENT to a set, never a set to a set.
Subset
A is a subset of B if and only if (a belongs to A implies a belongs to B)
Every element of A must be in B. The book writes this with the subset symbol and states it again in the chapter summary.
Union
A union B = {x : x belongs to A OR x belongs to B}
A shared element is written once. If B is a subset of A then A union B = A.
Intersection
A intersection B = {x : x belongs to A AND x belongs to B}
For disjoint sets this is the empty set - that is the definition of disjoint.
Difference
A minus B = {x : x belongs to A AND x does not belong to B}
NOT symmetric: A minus B is generally different from B minus A. With A = {1,2,3,4,5} and B = {4,5,6,7} they are {1,2,3} and {6,7}.
Equal sets
A = B if and only if A is a subset of B and B is a subset of A
A two-way test. One-way containment such as {1,2,3} inside {1,2,3,4} gives a subset, not equality.
Cardinality
n(A) = the number of distinct elements in the finite set A
n(empty set) = 0. For C = {x : x is a letter in INDIA}, n(C) = 4, because I is not counted twice.
Counting a union (the book's closing question, not a stated theorem)
n(A union B) = n(A) + n(B) - n(A intersection B)
The chapter poses this as a Think-and-discuss question and never states it as a result. It follows from Example 14: 5 + 4 - 2 = 7. For disjoint sets the last term is zero.
Two facts about subsets
The empty set is a subset of every set ; every set is a subset of itself
Both are boxed in the book. The first holds because the empty set has no element that could fail to be in A.
⚠️

Common mistakes & fixes

These are the exact errors that cost students marks in board exams. Read them once, save yourself the trouble.

WATCH OUT
✗ Treating the empty set and the set containing zero as the same thing
✓ The book prints this as a Note: {0} is a set containing the element 0, while the empty set has no elements. So n(empty set) = 0 but n({0}) = 1. A box with a zero in it is not an empty box.
WATCH OUT
✗ Counting a repeated letter or number twice when writing roster form or cardinality
✓ A set contains DISTINCT elements. The letters of SCHOOL are {s, c, h, o, l} with five elements, and the letters of INDIA give n = 4, not 5. This is the most common one-mark loss in the chapter.
WATCH OUT
✗ Adding cardinalities to get the size of a union
✓ Elements in the overlap belong to both sets, so adding charges for them twice. In the book's Example 14, n(A) = 5 and n(B) = 4 but n(A union B) = 7, because 2 and 4 are in both. Subtract n(A intersection B), or just list the union and count.
WATCH OUT
✗ Calling two sets equal because they overlap, or because one contains the other
✓ Equality needs containment BOTH ways. {1, 2, 3} is a subset of {1, 2, 3, 4} but the second is not a subset of the first, so they are not equal - that is the book's Example 9.
WATCH OUT
✗ Writing A minus B when B minus A was asked, or assuming they are the same
✓ Set difference is as unsymmetric as number subtraction. A minus B keeps what is in A and not in B; B minus A keeps what is in B and not in A. The book prints the warning immediately after Example 6.
WATCH OUT
✗ Using the membership symbol between two sets, or the subset symbol between an element and a set
✓ Membership relates an element to a set; subset relates a set to a set. In Example 12, the empty set is a SUBSET of B, while 3 is a MEMBER of A. Mixing them is a definition error, not a slip.
WATCH OUT
✗ Forgetting the empty set and the set itself when listing all subsets
✓ A three-element set has eight subsets, not six: the book lists { }, {1}, {2}, {3}, {1,2}, {2,3}, {1,3} and {1,2,3} for A = {1,2,3}. The printed answer key for a four-element set runs to sixteen.
WATCH OUT
✗ Calling a collection a set when it depends on opinion
✓ Well-defined means nobody can argue about membership. 'The ten most talented writers of India' and 'a team of eleven best cricket batsmen of the world' are both NOT sets, which is exactly what Exercise 2.1 question 1 is testing.
WATCH OUT
✗ Assuming an equation with two roots always gives a two-element set
✓ The universe the set is drawn from decides. In Example 13, {x : x belongs to N and x squared = 4} is {2}, not {2, -2}, because -2 is not a natural number. Always read the condition that names the number system.

Practice problems

Work through this chapter's problems as a readiness check — reveal each solution, mark yourself honestly, and get your gap report at the end.

Readiness check

Are you exam-ready for Sets?

16 problems from this chapter. Try each one, reveal the worked solution, mark yourself honestly — get your gap report at the end.

16 questions~11 min

5-minute revision

The whole chapter, distilled. Read this the night before the exam.

  • •A set is a WELL-DEFINED collection of DISTINCT objects, written inside braces; both adjectives are examinable
  • •Well-defined means membership is never a matter of opinion - 'ten most talented writers' is not a set
  • •Distinct means no repeats: the letters of SCHOOL are {s, c, h, o, l}, five elements not six
  • •Membership is written with the belongs-to symbol; it relates an ELEMENT to a set, never a set to a set
  • •Roster form lists the elements; order is immaterial and repeats are dropped
  • •Set-builder form gives a common property, with the colon read 'such that'
  • •Infinite sets such as the rationals cannot be written in roster form, which is why set-builder form exists
  • •The number sets: N naturals, W wholes, I or Z integers, Q rationals, R reals
  • •An empty, null or void set has no elements and is written as the Greek phi or as empty braces
  • •phi and {0} are DIFFERENT: n(phi) = 0 but n({0}) = 1
  • •The universal set holds everything under discussion; this book denotes it by the Greek mu, sometimes U, and draws it as a rectangle
  • •A Venn diagram draws the universal set as a rectangle and its subsets as closed curves inside
  • •A is a subset of B when every element of A is an element of B
  • •The empty set is a subset of every set; every set is a subset of itself
  • •A proper subset leaves something out - the vowels are a proper subset of the alphabet
  • •N is a subset of Z is a subset of Q is a subset of R; also Q' is a subset of R, but N is NOT a subset of Q'
  • •A union B collects elements in either set, and a shared element is written only once
  • •If B is a subset of A then A union B = A
  • •A intersection B collects only elements in both sets
  • •Sets with no common element are DISJOINT and their intersection is the empty set
  • •A minus B keeps what is in A and not in B; A minus B is generally NOT B minus A
  • •A minus B, B minus A and A intersection B are mutually disjoint and together make up A union B
  • •Two sets are equal when each is a subset of the other - a two-way test
  • •ASSASSINATION and STATION give the same set of letters, {A, S, I, N, T, O}
  • •A set is finite if its element count is a whole number, infinite otherwise
  • •The count of a finite set is its cardinal number or cardinality, written n(A); n(phi) = 0
  • •n(A union B) is NOT n(A) + n(B) unless the sets are disjoint - subtract n(A intersection B)
  • •The number of subsets of a set with n elements is 2 to the n: four elements give sixteen subsets

Telangana (TSBIE) marks blueprint

Where the marks come from in this chapter — so you can plan your prep.

Typical chapter weightage: No marks distribution is printed in the textbook for this chapter or anywhere in the volume, so no total is claimed. The index allots 8 periods in June. The categories below are the book's own four numbered exercises plus its in-chapter boxes; the marks column indicates question size rather than official weightage. Unusually, all four exercises have printed answers at textbook pages 371-373 - but two of them are wrong, both in Exercise 2.2 question 5: B intersection D is given as the even naturals when it is {2}, and A intersection D is truncated at 97 when it is the whole infinite set of primes. The key also mis-numbers Exercise 2.4, splitting the seven parts of question 2 across a '2.' and a '3.' although the exercise has only two questions, and gives a condition for Exercise 2.1 question 6(iv) that yields only {1, 4, 9}.

Question typeMarks eachTypical countWhat it tests
Exercise 2.1208
Exercise 2.2227
Exercise 2.3185
Exercise 2.4102
Do This / Try This / Think and Discuss022
Suggested Projects51

Where this shows up in the real world

This chapter isn't just an exam topic — it lives in the world around you.

A database query is set-builder notation with different p…

A database query is set-builder notation with different punctuation: SELECT rows WHERE a condition holds is exactly {x : x has the property}

Search filters combine as set operations

Search filters combine as set operations - narrowing with AND is an intersection, widening with OR is a union, and excluding a term is a difference

Library and retail classification

Library and retail classification, which is where the chapter starts: books by subject, elements by group, teeth by chewing function

Survey analysis of the kind the chapter's Suggested Proje…

Survey analysis of the kind the chapter's Suggested Project asks for: how many liked A only, B only, both, or neither, read off a Venn diagram

Blood group and allergy screening

Blood group and allergy screening, where a patient is matched against the intersection of several compatible donor sets

Timetabling and seat allocation

Timetabling and seat allocation, where two events clash exactly when the sets of people attending them are not disjoint

Spreadsheet and programming languages ship a set type who…

Spreadsheet and programming languages ship a set type whose union, intersection and difference operations are the ones defined in this chapter

Exam strategy

Battle-tested tips from teachers and toppers for this chapter.

1
Convert to roster form before doing anything else - most union, intersection and difference marks are lost in the reading, not the operation
2
In every roster answer, scan once for a repeated element before you write the final brace; repeats cost a mark on their own
3
For 'is this a set' questions, name the test: say whether membership is decidable, rather than just answering yes or no
4
For equality questions, show containment BOTH ways explicitly; examiners award the two halves separately
5
When listing all subsets, go by size and count against 2 to the n before moving on - it catches the missing one immediately
6
Draw the Venn diagram even when the question does not ask for one; it costs thirty seconds and makes difference and union questions self-checking
7
The book prints answers for all four exercises at pages 371-373 - use them to check, but verify Exercise 2.2 question 5 against the definitions, where the key is wrong

Going beyond the textbook

For olympiad aspirants and curious learners — topics that build on this chapter.

STRETCH
Prove the two De Morgan laws, that the complement of a union is the intersection of the complements and vice versa, and check them on a Venn diagram
STRETCH
Extend the counting rule to three sets and derive n(A union B union C) with its three pairwise subtractions and one triple addition
STRETCH
Show that the number of subsets of an n-element set is 2 to the n by a bijection with binary strings of length n
STRETCH
Prove that the power set of a set is always strictly larger than the set itself, and see why that rules out a set of all sets
STRETCH
Investigate the symmetric difference, the set of elements in exactly one of A and B, and show it equals (A union B) minus (A intersection B)
STRETCH
Look up Russell's paradox and explain what goes wrong with 'the set of all sets that are not members of themselves' - the reason 'well-defined' is a serious condition and not a formality

Where else this chapter is tested

CBSE board isn't the only one — other exams test this chapter too.

Telangana SSC public examination - Mathematics Paper I, where Sets supplies reliable short-answer marks on roster and set-builder conversion, operations and cardinality
Polytechnic and Navodaya entrance tests, which draw Venn-diagram counting questions in the survey format of this chapter's Suggested Project
CAT, CSAT and bank aptitude papers, where two- and three-set Venn counting is a standing question type built on the rule this chapter only hints at

Questions students ask

The real ones — pulled from the Q&A community and tutor sessions.

Because the first has a decidable test and the second does not. Point at any person and there is a fact of the matter about whether they are a boy in your class; nobody can argue. Talent has no such test, so two people compiling the list would disagree about who belongs, and the collection has no definite membership. That is what 'well-defined' rules out. Note that a collection can be well-defined and still be hard to compute - the set of primes below a billion is a perfectly good set even though you have not listed it.

A proper subset is contained in the larger set AND different from it, so A is a proper subset of B rules out A = B; a plain subset allows equality. The book states that distinction on page 37. It then writes 'A is a subset of A' using the proper-subset symbol on page 36 and defines subset with the same symbol in the chapter summary, which is strictly inconsistent - a set is never a proper subset of itself. In practice, read this book's subset symbol as plain 'subset' unless the sentence is drawing the distinction, and in an exam use the symbol the question uses.

Both, and neither is more correct - the universal set has no single standard symbol. This book prints 'generally denoted by mu and sometimes by U'. Other books and most competitive exam papers use U, and some use the Greek xi. It is a naming convention, not mathematics. Write whichever the question writes, define it once if you introduce it yourself, and do not lose marks arguing about it.

Because anything sitting in both sets gets counted once in n(A) and again in n(B), so the sum charges for it twice. The book's Example 14 makes it concrete: A = {1,2,3,4,5} and B = {2,4,6,8}, so 5 + 4 = 9, but the union {1,2,3,4,5,6,8} has only 7 members, and the two overcounted elements are exactly 2 and 4, the intersection. Subtracting n(A intersection B) removes the double count. When the sets are disjoint there is nothing shared and the counts do simply add.

No, and this is the trap in Example 13. The equation x squared = 4 does have two roots, but the set-builder form imposes a second condition: x must be a natural number. Minus 2 fails that, so it never gets in. The set is {2} and it is finite. The habit to build is to read both halves of the condition every time - the equation AND the universe it is drawn from. The same trap appears in Exercise 2.1 with B = {x : x is an integer and x squared = 4}, where the answer IS {2, -2}, because there the universe is the integers.

A set with n elements has 2 to the power n subsets. The reason is a choice for each element, independently: in or out. Two elements give 4 subsets, three give 8, four give 16 - which is why Exercise 2.3's four-element set produces such a long printed answer. Listing them by size, as 1 + 4 + 6 + 4 + 1 for four elements, is the safe way to avoid missing one, and it also stops you forgetting the empty set and the whole set, which are the two most commonly dropped.

No - it is one of two errors in the key for that question. With B the even naturals and D the primes, an element of B intersection D has to be both even and prime. Every even number other than 2 has 2 as a proper factor and so is composite, which leaves B intersection D = {2}. The same question's A intersection D is printed as ending at 97, but A is every natural number and D every prime, so that intersection is the whole infinite set of primes. Use the key for the other questions, which are correct, but work this one from the definitions.
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