By the end of this chapter you'll be able to…

  • 1Describe the properties of magnetic field lines and explain why poles cannot be isolated
  • 2Treat a solenoid as an equivalent bar magnet and compute its magnetic moment
  • 3Calculate the torque and potential energy of a magnetic dipole in a uniform field
  • 4Distinguish stable from unstable equilibrium using the potential energy rather than the torque
  • 5Compute the axial and equatorial fields of a short bar magnet and state their directions
  • 6State Gauss's law for magnetism and explain its physical meaning
  • 7Relate B, H and M through the susceptibility and classify materials as diamagnetic, paramagnetic or ferromagnetic
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Why this chapter matters
This chapter completes the dipole picture begun in Chapter 4, showing that a bar magnet is a solenoid in disguise, that isolated poles do not exist, and how materials respond to a field. It is short, heavily formula-based, and reliably scores marks if the torque and energy relations are secure.

Magnetism and Matter

1. Check this before you revise anything

The "Additional Exercises" section has been removed from this chapter, as from all 14 chapters of the current Class 12 Physics book. The questions run contiguously from 5.1 to 5.7 with no gaps.

That leaves 7 questions for the whole chapter, five of which are variations on the torque and potential energy of a dipole.

The Earth's magnetism is gone entirely. Older editions devoted a full section to it — magnetic declination, angle of dip, the horizontal component, and the Earth as a giant dipole. A full-text search of this chapter returns zero occurrences of the word "Earth", and zero for "declination" and "dip".

Permanent magnets, electromagnets and the hysteresis loop are gone too. Searching for "hysteresis", "retentivity" and "coercivity" returns zero hits each. The chapter now ends at section 5.5.

Curie's law and the Curie temperature have been removed. Zero occurrences of "Curie" appear anywhere in the chapter. Section 5.5.2 still describes paramagnetism qualitatively and mentions that alignment improves at low temperatures, but the inverse-temperature law itself is no longer stated.

If you are revising from an older guide, a past paper, or a coaching sheet, expect it to test several topics this book no longer contains.

Textbook sectionTopic
5.1Introduction
5.2The bar magnet: field lines, the equivalent solenoid, the dipole in a uniform field, the electrostatic analogue
5.3Magnetism and Gauss's law
5.4Magnetisation and magnetic intensity
5.5Magnetic properties of materials: diamagnetism, paramagnetism, ferromagnetism

A numbering error in the exercises. Exercise 5.4 begins "If the solenoid in Exercise 5.5 is free to turn about the vertical direction..." — but Exercise 5.5 is about a bar magnet. The solenoid is defined in Exercise 5.3, and its magnetic moment of J T is what 5.4 needs. Our solution uses the correct cross-reference and says so explicitly, rather than silently patching the book.


2. The Bar Magnet and Its Field Lines (Textbook 5.2 to 5.2.1)

A bar magnet has two poles, and the properties of its field lines are a standard two-mark question.

Properties of magnetic field lines:

  • They form continuous closed loops, running from north to south outside the magnet and from south to north inside it. Electric field lines, by contrast, start and end on charges.
  • The tangent at any point gives the direction of there.
  • Line density represents field strength: crowded lines mean a strong field.
  • Two field lines never intersect. If they did, the field would have two directions at one point, which is impossible.

Poles cannot be separated. Cutting a bar magnet in half does not isolate a north pole; it produces two shorter magnets, each with both poles. This is the experimental fact behind section 5.3.

The bar magnet as an equivalent solenoid (5.2.2). The previous chapter showed that a current loop behaves as a magnetic dipole. Stacking many loops into a solenoid gives an external field pattern indistinguishable from a bar magnet's, with the ends acting as poles.

The magnetic moment of a solenoid of turns, area , carrying current is:

This is the whole content of Exercises 5.3 and 5.6, and it is the conceptual bridge from Chapter 4 into this one.


3. The Dipole in a Uniform Field (Textbook 5.2.3)

Because the two poles feel equal and opposite forces, a dipole in a uniform field feels no net force — only a torque:

Potential energy. Work done in rotating the dipole is stored as potential energy:

Work done between two orientations is the difference of the potential energies:

Exercise 5.5 uses exactly this, first for a rotation to and then to .

Reading the two equilibria off the energy. Setting and in the energy expression:

TorqueEnergyEquilibrium
zero, minimumStable
maximum,
zero, maximumUnstable

Both extremes have zero torque, so torque alone cannot tell them apart. The energy does. A minimum is stable and a maximum unstable, which is what Exercise 5.2 asks you to identify and Exercise 5.5(b)(ii) exploits when the torque comes out as zero at .

The electrostatic analogue (5.2.4). Replacing and converts every electric dipole result into its magnetic counterpart. For a short bar magnet at distance :

The axial field is twice the equatorial field at the same distance, and it points along the moment while the equatorial field points opposite to it. Exercise 5.7 tests both the factor of two and the two directions.


4. Gauss's Law for Magnetism (Textbook 5.3)

The net magnetic flux through any closed surface is zero:

Compare this with the electric case. Gauss's law in electrostatics gives , which is non-zero whenever the surface contains net charge. The magnetic version has zero on the right always.

The physical statement is that isolated magnetic poles do not exist. Every field line that enters a closed surface must leave it, because field lines are closed loops with no beginning or end. There is no magnetic charge for them to start on.

This is why breaking a magnet never yields a monopole, and it is one of the four Maxwell equations assembled in Chapter 8.


5. Magnetisation and Magnetic Intensity (Textbook 5.4)

Inside a material, the applied field and the material's own response must be separated.

Magnetisation is the net magnetic moment per unit volume:

Magnetic intensity describes the applied field alone, independent of the medium. The total field inside is the sum of both contributions:

Susceptibility measures how strongly a material responds:

Relative permeability then follows:

is a pure number with no units, and its sign and size are what classify the material. Note that and share the unit A m, while is in tesla — mixing them up is the standard error here.


6. Diamagnetism, Paramagnetism and Ferromagnetism (Textbook 5.5)

The three classes are distinguished by the sign and magnitude of , and by how they behave in a non-uniform field.

DiamagneticParamagneticFerromagnetic
Susceptibility Small, negative, Small, positiveLarge, positive
Relative permeability , slightly
In a non-uniform fieldMoves to weaker fieldMoves to stronger fieldStrongly to stronger field
Field lines insideExpelledSlightly concentratedStrongly concentrated
Atomic momentZero without a fieldPermanent, randomised by heatPermanent, aligned in domains
ExamplesBismuth, copper, water, leadAluminium, sodium, oxygenIron, cobalt, nickel

Diamagnetism (5.5.1) exists in every material. The atoms have no permanent moment; an applied field induces one that opposes the field, by the same argument as Lenz's law in the next chapter. It is usually masked by the stronger para- or ferromagnetic response when either is present.

The perfect diamagnet. A superconductor expels magnetic flux entirely, giving and — the Meissner effect, and the extreme end of the diamagnetic range.

Paramagnetism (5.5.2). The atoms carry permanent moments, but thermal motion randomises them so no net magnetisation appears. A strong field at low temperature aligns them, and the field inside is enhanced slightly — the book quotes about one part in .

Ferromagnetism (5.5.3). Atomic moments align spontaneously into domains, regions in which vast numbers of moments point the same way. An applied field grows the favourably aligned domains at the expense of the others, producing a very large magnetisation that can persist after the field is removed.


Summary

  • Magnetic field lines form closed loops, running north to south outside a magnet and south to north inside; they never intersect.
  • Cutting a magnet produces two magnets, never an isolated pole.
  • A solenoid is equivalent to a bar magnet, with moment .
  • In a uniform field a dipole feels zero net force but a torque , of magnitude .
  • , so work done in rotating is .
  • is stable with ; is unstable with . Both have zero torque, so use the energy to distinguish them.
  • Short bar magnet: along the moment, and opposite to it — a factor of two apart.
  • Gauss's law for magnetism: always, because isolated magnetic poles do not exist.
  • ; ; ; .
  • and are both in A m while is in tesla; is dimensionless.
  • Diamagnetic: small and negative, , repelled towards weaker field, no permanent atomic moment.
  • Paramagnetic: small and positive, slightly above 1, attracted to stronger field, permanent moments randomised by heat.
  • Ferromagnetic: large and positive, , domain structure, magnetisation can persist.
  • A superconductor is a perfect diamagnet with and , the Meissner effect.
  • The Earth's magnetism, permanent magnets and electromagnets, the hysteresis loop and Curie's law have all been removed from this chapter.
  • Exercise 5.4's reference to "the solenoid in Exercise 5.5" is a misprint; the solenoid is in Exercise 5.3.

Key formulas & results

Everything you need to memorise, in one card. Screenshot this for revision.

Magnetic moment of a solenoid or coil
m = N I A
N turns, area A, current I; this is what makes a solenoid equivalent to a bar magnet
Torque on a magnetic dipole
torque = m x B, with magnitude m B sin(theta)
Maximum at 90 degrees; zero at both 0 and 180 degrees, which is why torque cannot identify the type of equilibrium
Potential energy of a magnetic dipole
U = -m.B = -m B cos(theta)
Minimum -mB at 0 degrees and maximum +mB at 180 degrees
Work done in rotating a dipole
W = U2 - U1 = -m B (cos theta2 - cos theta1)
Equals the change in potential energy, not the torque multiplied by the angle
Stable and unstable equilibrium
Stable at theta = 0 with U = -mB; unstable at theta = 180 degrees with U = +mB
Both positions have zero torque, so the energy is what distinguishes them
Axial field of a short bar magnet
B = (mu_0/4 pi)(2m/r cubed), directed along the magnetic moment
Twice the equatorial value at the same distance
Equatorial field of a short bar magnet
B = (mu_0/4 pi)(m/r cubed), directed opposite to the magnetic moment
Half the axial value, and pointing the other way
Gauss's law for magnetism
The net magnetic flux through any closed surface is zero
Always zero, because isolated magnetic poles do not exist; contrast the electric case which gives q/epsilon_0
Magnetisation
M = net magnetic moment divided by volume
Measured in ampere per metre, the same unit as H
Total field inside a material
B = mu_0 (H + M)
H is the applied intensity and M the material's own response
Magnetic susceptibility
M = chi H
A dimensionless number whose sign and size classify the material
Relative permeability
mu_r = 1 + chi, and mu = mu_0 mu_r
mu_r is below 1 for diamagnets, slightly above 1 for paramagnets, and very large for ferromagnets
Classification by susceptibility
Diamagnetic: chi small and negative. Paramagnetic: chi small and positive. Ferromagnetic: chi large and positive
The sign alone tells you whether the material is pushed towards weaker or stronger field
The perfect diamagnet
A superconductor has chi = -1 and mu_r = 0
Magnetic flux is expelled completely, the Meissner effect
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Common mistakes & fixes

These are the exact errors that cost students marks in board exams. Read them once, save yourself the trouble.

WATCH OUT
Using the torque to decide whether an equilibrium is stable
The torque is zero at both 0 and 180 degrees, so it cannot distinguish them. Use the potential energy: a minimum at U = -mB is stable and a maximum at U = +mB is unstable.
WATCH OUT
Computing work as torque multiplied by angle
The torque varies with angle, so the product is not the work. Use the difference of potential energies, W = -mB(cos theta2 - cos theta1).
WATCH OUT
Forgetting the factor of two between the axial and equatorial fields
The axial field is twice the equatorial field at the same distance, and the two point in opposite senses relative to the magnetic moment. Exercise 5.7 tests both facts at once.
WATCH OUT
Expecting a net force on a magnet in a uniform field
In a uniform field the forces on the two poles are equal and opposite, so the net force is zero and only a torque acts. A net force appears only in a non-uniform field.
WATCH OUT
Believing a magnet can be cut to isolate a north pole
Every piece is a complete magnet with both poles. This is the experimental content of Gauss's law for magnetism, which sets the net flux through any closed surface to exactly zero.
WATCH OUT
Mixing up the units of B, H and M
H and M are both measured in ampere per metre, while B is in tesla. The susceptibility chi, being a ratio of M to H, has no units at all.
WATCH OUT
Assuming a diamagnetic material is simply unmagnetic
Diamagnetism is an active response: an induced moment opposes the applied field, so the material is pushed towards the weaker field region and mu_r falls below 1.
WATCH OUT
Revising the Earth's magnetism, dip and declination from an older guide
That section has been removed. The word Earth does not appear anywhere in the current chapter, and neither do declination or angle of dip.
WATCH OUT
Preparing the hysteresis loop, retentivity, coercivity or Curie's law
All of these have been removed. Section 5.5.3 describes ferromagnetism and domains qualitatively, but the loop and the temperature law are no longer part of the chapter.
WATCH OUT
Taking Exercise 5.4's reference to Exercise 5.5 at face value
That is a misprint. Exercise 5.5 concerns a bar magnet; the solenoid is defined in Exercise 5.3, and its moment of 0.60 J per tesla is the value 5.4 requires.

Practice problems

Work through this chapter's problems as a readiness check — reveal each solution, mark yourself honestly, and get your gap report at the end.

Readiness check

Are you exam-ready for Magnetism and Matter?

9 problems from this chapter. Try each one, reveal the worked solution, mark yourself honestly — get your gap report at the end.

9 questions~6 min

5-minute revision

The whole chapter, distilled. Read this the night before the exam.

  • Field lines are closed loops, north to south outside and south to north inside a magnet
  • Two field lines never intersect, since the field would then have two directions at one point
  • Cutting a magnet gives two magnets; isolated poles do not exist
  • A solenoid is equivalent to a bar magnet, with moment m = N I A
  • In a uniform field a dipole feels zero net force but a torque m B sin(theta)
  • U = -m B cos(theta), minimum -mB at 0 degrees and maximum +mB at 180 degrees
  • Work done rotating is the energy difference, W = -mB(cos theta2 - cos theta1)
  • Stable at 0 degrees, unstable at 180 degrees; both have zero torque so use the energy
  • Axial field = (mu_0/4 pi)(2m/r cubed), along the moment
  • Equatorial field = (mu_0/4 pi)(m/r cubed), opposite to the moment; the axial is twice as large
  • Gauss's law for magnetism: the net flux through any closed surface is always zero
  • B = mu_0(H + M), with H and M both in ampere per metre and B in tesla
  • M = chi H and mu_r = 1 + chi, with chi dimensionless
  • Diamagnetic: chi small negative, mu_r below 1, moves to weaker field, no permanent atomic moment
  • Paramagnetic: chi small positive, mu_r slightly above 1, moves to stronger field
  • Ferromagnetic: chi large positive, mu_r very large, domain structure, magnetisation can persist
  • A superconductor is a perfect diamagnet with chi = -1 and mu_r = 0, the Meissner effect
  • The Earth's magnetism, permanent magnets, hysteresis and Curie's law have been removed from this chapter
  • The Additional Exercises block has been removed, leaving Exercises 5.1 to 5.7

CBSE marks blueprint

Where the marks come from in this chapter — so you can plan your prep.

Typical chapter weightage: Unit III: Magnetic Effects of Current and Magnetism, no chapter-wise split published by CBSE

Question typeMarks eachTypical countWhat it tests
Torque on a Magnetic Dipole, Potential Energy of a Dipole and Work Done in Rotating a Magnet3-41Torque, energy, stable and unstable equilibrium, and work between orientations
Magnetic Moment of a Solenoid, Axial and Equatorial Field, and Gauss's Law for Magnetism2-31The solenoid as an equivalent magnet, dipole fields, and the absence of monopoles
Magnetisation and Susceptibility, and Magnetic Properties of Materials2-31B, H and M relations, and the classification into diamagnetic, paramagnetic and ferromagnetic
Prep strategy
  • Decide first whether the question wants a torque or an energy, since one uses sine and the other cosine
  • For any equilibrium question, write the energy rather than the torque, because the torque vanishes in both cases
  • State the direction of the axial and equatorial fields in words, not only their magnitudes
  • Check the sign of chi before naming a material's class, since that single sign settles it
  • Do not revise the Earth's magnetism, hysteresis or Curie's law for this chapter, as all have been removed

Where this shows up in the real world

This chapter isn't just an exam topic — it lives in the world around you.

Compasses and navigation

A pivoted magnetic needle aligns itself with the ambient field, settling at the stable orientation where its energy is at a minimum.

Magnetic storage

Ferromagnetic domains retain their alignment after the writing field is removed, which is what lets a magnetic disk or tape hold data.

Magnetic separation

Because paramagnetic and ferromagnetic materials move towards a stronger field while diamagnetic ones move away, mixtures can be sorted in a non-uniform field.

Magnetic levitation

A superconductor expels flux completely, the Meissner effect, and the resulting repulsion is strong enough to support a magnet in mid-air.

Transformer and motor cores

Soft ferromagnetic cores with very high relative permeability concentrate flux where it is wanted, which is why they appear in almost every electrical machine.

Exam strategy

Battle-tested tips from teachers and toppers for this chapter.

1
Write the moment m = N I A as an explicit first step whenever a solenoid or coil appears
2
Choose sine for torque and cosine for energy, and state which you are using before substituting
3
Answer equilibrium questions with the energy, giving both the value and whether it is a minimum or maximum
4
Give the direction along with the magnitude in every dipole-field question
5
Convert distances to metres before cubing them, since the error is magnified threefold
6
Read the sign of chi first in any materials question, as it settles the classification immediately
7
Ignore older material on the Earth's field, hysteresis and Curie's law, which are no longer in this chapter

Going beyond the textbook

For olympiad aspirants and curious learners — topics that build on this chapter.

STRETCH
The classical Langevin theory of paramagnetism, which derives the temperature dependence from the Boltzmann distribution of dipole orientations
STRETCH
The exchange interaction, the quantum-mechanical origin of the spontaneous alignment that produces ferromagnetic domains
STRETCH
Magnetic monopoles as predicted by Dirac, and the charge-quantisation argument that would follow if even one existed
STRETCH
Nuclear magnetic resonance, in which nuclear dipole moments precess in a strong field and reveal molecular structure
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JEE Main & Advanced practice

Competitive-level problems on this chapter, above the board pattern. Try each one on paper before opening the solution.

JEE MainStable and unstable equilibrium of a dipoleTorque and potential energy

A short bar magnet of moment J T is placed in a uniform field of T. Identify the orientations of stable and unstable equilibrium and give the potential energy of each.

Stuck? Show the approach

Write the torque and the energy, then note that both equilibria have zero torque so the energy must decide.

Show the full solution

The torque vanishes at and at , so torque alone cannot separate them. The energy gives J at , a minimum and therefore stable, and J at , a maximum and therefore unstable. A small displacement from the aligned position produces a restoring torque, while a small displacement from the antiparallel position produces a torque that turns the magnet further away.

Answer: Stable at 0 degrees with U = -4.8 x 10^-2 J; unstable at 180 degrees with U = +4.8 x 10^-2 J
The trap

Trying to classify the equilibria from the torque. It is zero in both cases, and only the sign of the second change in energy separates them.

JEE MainWork done rotating a magnetChange in dipole potential energy

A bar magnet of moment J T lies aligned with a uniform field of T. Find the work needed to turn it to (i) and (ii) , and the torque on it in each final position.

Stuck? Show the approach

Use the change in potential energy for the work, then evaluate the torque separately at each final angle.

Show the full solution

With J, the work is starting from . For , J. For , J. The torque is , giving N m at and zero at , since . The magnet is in equilibrium there, but an unstable one.

Answer: (i) 0.33 J, torque 0.33 N m (ii) 0.66 J, torque zero
The trap

Assuming the torque must be largest where the most work was done. At 180 degrees the work is maximal but the torque is exactly zero.

JEE AdvancedAxial versus equatorial fieldShort bar magnet as a dipole

A short bar magnet has magnetic moment J T. Find the magnitude and direction of the field at a point cm from its centre (a) on its axis, and (b) on its equatorial line.

Stuck? Show the approach

Apply the two dipole expressions, keeping careful track of the direction of each relative to the moment.

Show the full solution

With m and T m A: on the axis, T, directed along the magnetic moment, that is from south to north inside the magnet. On the equatorial line, T, directed opposite to the moment. The axial value is exactly twice the equatorial one.

Answer: (a) 9.6 x 10^-5 T along the moment (b) 4.8 x 10^-5 T opposite to the moment
The trap

Giving both fields the same direction, or forgetting the factor of two. Both marks are usually allocated to these two points.

Where else this chapter is tested

CBSE board isn't the only one — other exams test this chapter too.

CBSE Class 12 BoardHigh
JEE MainMedium
NEETMedium
JEE AdvancedMedium

Questions students ask

The real ones — pulled from the Q&A community and tutor sessions.

Because the torque m B sin(theta) is zero at theta equal to 0 and also at theta equal to 180 degrees. Both orientations are therefore equilibrium positions and the torque cannot separate them. The potential energy does: U = -m B cos(theta) is at its minimum of -mB when the magnet is aligned and at its maximum of +mB when it is antiparallel. A displacement from the minimum produces a restoring torque, while a displacement from the maximum drives the magnet further away.

It comes out of the geometry of the two pole contributions. On the axis the fields of the two poles point the same way and reinforce, whereas on the equatorial line their components along the axis are opposite in one direction and only the perpendicular parts survive. Carrying the algebra through for a short magnet leaves an extra factor of two in the axial case. The directions differ too: the axial field points along the moment and the equatorial field points against it.

Because there is no magnetic charge for field lines to begin or end on. Every magnetic field line is a closed loop, so any line entering a closed surface must also leave it, and the two contributions cancel exactly. In electrostatics the corresponding law gives q divided by epsilon nought, which is non-zero whenever the surface encloses charge. This difference is the formal statement that magnetic monopoles have never been observed.

No. Older editions had a full section covering magnetic declination, the angle of dip, the horizontal component and the Earth as a giant dipole. None of that survives: a full-text search of the current chapter finds zero occurrences of the word Earth, and none of declination or dip either. If a practice paper asks about the angle of dip, it is drawing on an older syllabus.

Not for this chapter as it now stands. Searching for hysteresis, retentivity and coercivity returns no hits, and neither does Curie. Section 5.5.3 still explains ferromagnetism through domains and notes that alignment improves at low temperature, but the loop and the inverse-temperature law are no longer stated. Focus instead on the sign and magnitude of the susceptibility, which is what the current text uses to classify materials.

H is the magnetic intensity, describing the applied field independently of what material is present. M is the magnetisation, the net magnetic moment per unit volume, describing the material's own response. B is the total field inside, combining both through B = mu_0(H + M). H and M share the unit ampere per metre while B is measured in tesla, and the susceptibility chi, being the ratio of M to H, is a pure number.

Exercise 5.3. The printed text of 5.4 says the solenoid in Exercise 5.5, but 5.5 is about a bar magnet aligned with a field, not a solenoid. The solenoid of 800 turns and area 2.5 x 10^-4 m squared carrying 3.0 A is defined in Exercise 5.3, and its magnetic moment of 0.60 joule per tesla is exactly the value 5.4 needs to compute the torque. Use 5.3 and note the misprint rather than assuming your reading is wrong.
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Last reviewed on 18 August 2026. Written and reviewed by subject-matter experts — read about our process.
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