UPSC ESE — Conventional Papers — Answer Writing
ESE is the rare engineering exam that still asks a candidate to write. Two conventional papers of three hours each, where the assumptions, the governing equation and the units are worth as much as the final number.
Candidates should attempt Question No. 1 which is compulsory and any four of the remaining questions. Assume suitable data if necessary and indicate the same clearly. Neat sketches are to be drawn wherever required.
- Q1. (a)A simply supported beam of span L carries a uniformly distributed load w per unit length. Derive the expression for maximum deflection, stating your assumptions.10
- (b)Draw the shear force and bending moment diagrams for the loading shown, marking all salient values.12
- Q2. (a)Design a singly reinforced rectangular section for the given factored moment, using limit state method.20
One ESE Conventional answer, from question to marked report
A real question, an attempt with the weaknesses a real attempt has, and the report an AI examiner hands back — in the marking unit ESE Conventional genuinely uses. This is the whole product; there is nothing else to sign up for.
Scoped to the paper and topic you pick, at the marks it is genuinely set at.
A simply supported beam of span L carries a uniformly distributed load w per unit length. Derive the expression for maximum deflection, stating your assumptions.
Type it, dictate it, or write on paper and photograph the page — your handwriting is read.
Photographed, read, and marked in red — every expected step scored down the right margin and the omissions written in.
For a simply supported beam with UDL, maximum deflection = 5wL^4 / 384EI at the centre. This is a standard result obtained from the double integration method by integrating the bending moment equation twice and applying boundary conditions. This standard result is used directly in design, where the span and the load are known and the section has to be selected. Here E is the modulus of elasticity of the material and I is the moment of inertia of the section about the neutral axis, so the product EI is the flexural rigidity of the beam. The deflection varies as the fourth power of the span, which means that doubling the span increases the deflection sixteen times for the same load and the same section. The value obtained is then checked against the permissible deflection given in the code, which is usually expressed as a fraction of the span.
- The assumptions, which were explicitly asked for and are free marks
- M(x) = wLx/2 minus wx squared over 2, written before integrating
- Boundary conditions at both supports and the symmetry condition at midspan
Model answer for this question
State assumptions: linear elastic material, Euler-Bernoulli beam theory, small deflections, constant EI, self-weight ignored. Write M(x) for a section at distance x. Substitute into EI times the second derivative of y equals M(x) and integrate twice. Apply y equals zero at both supports and slope zero at midspan by symmetry to evaluate the constants. Obtain the deflection curve, then substitute x equals L over 2 to reach 5wL to the fourth over 384EI. State units.
Photograph the page from your phone and the Studio reads your handwriting — the only way to practise the speed and layout the paper actually tests.
Fast enough to write, read the report and rewrite the same answer in one sitting — which is where the improvement actually comes from.
The scoring behind those pen marks: every expected step, what it was worth, what you earned, and a model answer.
- Assumptions stated — Euler-Bernoulli, small deflection, constant EI0/2
The question asked for them explicitly and none is given.
- Bending moment expression set up0/2
Not written. This is the first mark of the derivation.
- Double integration with constants evaluated from boundary conditions0/3
Described, not performed.
- Final expression and location2/2
Correct.
- Units and dimensional consistency1/1
Consistent.
ESE Conventional at a glance
| Conducting body | Union Public Service Commission |
|---|---|
| Mode | Handwritten in an answer booklet |
| Papers | 2 |
| Total | 600 across the two conventional papers |
| Marking | ESE Conventional — step marking |
What ESE Conventional sets
The papers you sit, and what each is worth.
Core engineering discipline.
Core engineering discipline.
- Marked to the ESE Conventional scheme
- Model answer, every time
- Handwriting read from a photo
- AI viva on any topic
- Full timed papers
- Every attempt kept in your archive
- WriteA question, answered and marked.
- VivaQuestioned on Bending moment and shear force and more.
- Full paperA timed paper, one scorecard.