By the end of this chapter you'll be able to…

  • 1Assign IUPAC names using the functional-group priority order
  • 2Identify structural and stereoisomerism, including chirality and geometrical isomerism
  • 3Explain reactivity from inductive, resonance and hyperconjugation effects
  • 4Rank carbocation, carbanion and free-radical stability
  • 5Predict alkane halogenation and alkene addition products (Markovnikov and peroxide)
  • 6Explain alkyne acidity and apply aromaticity and electrophilic-substitution directing rules
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Why this chapter matters in NEET UG
Organic chemistry looks like endless reactions until you learn the logic underneath — a few electronic effects and the stability of a handful of intermediates make reactions predictable rather than memorised. This foundation plus the hydrocarbons built on it is NEET's single largest organic block, a reliable 4–5 questions on nomenclature, isomerism, stability orders and reaction mechanisms. This chapter builds that logic from the ground up (inductive, resonance and hyperconjugation effects; carbocation, carbanion and radical stability) and applies it to alkane free-radical halogenation, alkene Markovnikov and peroxide addition, alkyne acidity and aromatic electrophilic substitution with directing effects.

Basic Organic Chemistry and Hydrocarbons — NEET Chemistry

Organic chemistry looks like endless reactions to memorise — until you learn the logic underneath. Almost everything follows from a few electronic effects and the stability of a handful of intermediates. Master why electrons flow where they do, and reactions become predictable rather than memorised. This foundation, plus the hydrocarbons built on it, is NEET's single largest organic block — a reliable 4–5 questions on nomenclature, isomerism, stability orders and reaction mechanisms. This chapter builds that logic from the ground up and applies it to alkanes, alkenes, alkynes and aromatics, reasoning through every mechanism.


Part A — General Organic Chemistry (the logic)

1. IUPAC nomenclature

A systematic name has three parts: substituent prefixes + parent chain (root + saturation) + principal functional-group suffix.

  • Root = longest carbon chain containing the principal functional group (meth-, eth-, prop-, but-, pent-…).
  • Suffix for saturation: -ane (single), -ene (double), -yne (triple).
  • Principal functional group gets the lowest locant and the characteristic suffix. Priority order (highest first): carboxylic acid > ester > amide > nitrile > aldehyde > ketone > alcohol > amine; others (halo, nitro, alkyl) are named as prefixes.
  • Number the chain to give the principal group the lowest locant.

Worked example 1.1. Name CH₃–CH(OH)–CH₂–CHO. The principal group is the aldehyde (higher priority than OH), so it is C-1: a 4-carbon chain → butanal, with OH as a "hydroxy" prefix at C-3 → 3-hydroxybutanal.


2. Isomerism

Structural (constitutional) isomers — same formula, different connectivity:

  • Chain — different carbon skeleton (n-butane vs isobutane).
  • Position — same skeleton, group in a different place (1-propanol vs 2-propanol).
  • Functional — different functional group (ethanol C₂H₆O vs dimethyl ether).
  • Metamerism — different alkyl groups either side of a functional group (diethyl ether vs methyl propyl ether).
  • Tautomerism — a dynamic equilibrium by proton shift (keto ⇌ enol).

Stereoisomers — same connectivity, different spatial arrangement:

  • Geometrical (cis–trans / E–Z) — restricted rotation about a C=C double bond (needs two different groups on each carbon).
  • Optical — non-superimposable mirror images (enantiomers) around a chiral centre (a carbon with four different groups); they rotate plane-polarised light oppositely. A 50:50 mix is a racemic mixture (optically inactive).

Worked example 2.1. Does 2-butene show geometrical isomerism? Does butan-2-ol show optical isomerism? 2-butene: yes — the C=C carbons each carry an H and a CH₃, so cis and trans forms exist. Butan-2-ol: yes — C-2 bears four different groups (H, OH, CH₃, C₂H₅), so it is chiral and optically active.


3. Electronic effects — why electrons flow

Inductive effect (I) — permanent polarisation of σ bonds by an electronegative atom, transmitted along the chain and weakening with distance.

  • −I (electron-withdrawing): –NO₂, –CN, –COOH, halogens.
  • +I (electron-donating): alkyl groups (–CH₃).

Resonance / mesomeric effect (M) — delocalisation of π/lone-pair electrons through conjugation; stronger and further-reaching than induction. +M groups (–OH, –NH₂, –OR, halogens) donate electron density into the ring; −M groups (–NO₂, –C=O, –CN) withdraw it.

Hyperconjugation — delocalisation of σ(C–H) electrons into an adjacent empty p orbital or π system ("no-bond resonance"). More α-hydrogens → more hyperconjugation → more stability. It explains alkene and carbocation stability trends.

Electromeric effect — a temporary, complete shift of a π electron pair in the presence of an attacking reagent.

Worked example 3.1. Why is a tertiary carbocation more stable than a primary one? A tertiary carbocation has three alkyl groups that donate electron density by +I and, crucially, provide many α C–H bonds for hyperconjugation, spreading and stabilising the positive charge. A primary carbocation has few such stabilising groups.


4. Reaction intermediates, reagents and reaction types

Bond cleavage: homolytic (each atom keeps one electron → free radicals) or heterolytic (one atom keeps both → ions).

Three intermediates and their stability:

  • Carbocation (positive C): stability 3° > 2° > 1° > methyl (stabilised by +I and hyperconjugation; benzyl/allyl extra-stable by resonance).
  • Carbanion (negative C): stability methyl > 1° > 2° > 3° (the reverse — alkyl groups destabilise the negative charge).
  • Free radical (unpaired electron): stability 3° > 2° > 1° (like carbocations, but less pronounced).

Reagents: electrophiles (electron-pair seekers, e.g. H⁺, NO₂⁺, carbocations) and nucleophiles (electron-pair donors, e.g. OH⁻, CN⁻, NH₃).

Reaction types: substitution, addition, elimination, and rearrangement.

Worked example 4.1. Arrange these carbocations in order of stability: CH₃⁺, (CH₃)₂CH⁺, (CH₃)₃C⁺, C₆H₅CH₂⁺. Benzyl (resonance-stabilised) ≈ most stable, then tertiary, then secondary, then methyl: C₆H₅CH₂⁺ > (CH₃)₃C⁺ > (CH₃)₂CH⁺ > CH₃⁺.


Part B — Hydrocarbons

5. Alkanes

Alkanes () are saturated, largely unreactive ("paraffins"), with tetrahedral carbons.

  • Preparation: hydrogenation of alkenes (H₂/Ni), Wurtz reaction (2R–X + 2Na → R–R), decarboxylation of sodium salts (soda-lime).
  • Halogenation proceeds by a free-radical chain mechanism (initiation → propagation → termination), needing UV light:

  • Conformations (from C–C rotation): staggered (lowest energy, anti) vs eclipsed (highest) in ethane; NEET tests which is more stable.

Worked example 5.1. Why does methane react with chlorine only in sunlight (or UV)? Halogenation is a free-radical reaction; the initiation step needs energy (UV) to homolytically split Cl₂ into chlorine radicals. In the dark, no radicals form and no reaction occurs.


6. Alkenes

Alkenes () have a C=C (one σ + one π); the π bond is the reactive site for electrophilic addition.

Markovnikov's rule: in adding HX to an unsymmetrical alkene, H adds to the carbon with more hydrogens (so the halogen adds to the more substituted carbon) — because the reaction goes through the more stable carbocation.

Anti-Markovnikov (peroxide/Kharasch effect): with HBr in the presence of peroxides, addition reverses (free-radical mechanism), putting Br on the less substituted carbon. This works only for HBr, not HCl or HI.

Other key additions:

  • H₂ / Ni → alkane; X₂ (Br₂ water) → vicinal dihalide (decolourises bromine water — a test for unsaturation).
  • Hydration (H₂O/H⁺) → alcohol (Markovnikov).
  • Ozonolysis (O₃ then Zn/H₂O) cleaves C=C into two carbonyls — used to locate the double bond.

Worked example 6.1. Product of HBr addition to propene (CH₃–CH=CH₂), with and without peroxide? Without peroxide (Markovnikov): H to the terminal CH₂ (more H's), Br to the middle carbon → 2-bromopropane (via the more stable secondary carbocation). With peroxide (anti-Markovnikov): Br to the terminal carbon → 1-bromopropane.


7. Alkynes

Alkynes () have a C≡C (one σ + two π), with carbons.

  • Terminal alkynes are weakly acidic — the C–H (50% s-character) holds its electrons tightly, so the H is acidic enough to be removed by strong bases and to form metal acetylides (test: white ppt with ammoniacal AgNO₃, red with Cu₂Cl₂). Acidity: HC≡CH > H₂C=CH₂ > H₃C–CH₃ (s-character order ).
  • Addition of H₂O (dilute H₂SO₄/HgSO₄) gives, via an enol, an aldehyde (from ethyne) or ketone (Markovnikov).

Worked example 7.1. Why is ethyne (acetylene) acidic but ethane is not? In ethyne the C–H bond is on an carbon (50% s-character), which holds the bonding electrons closer to carbon, making the H more easily lost as H⁺. Ethane's C–H (25% s-character) holds its H far more tightly — hence non-acidic.


8. Aromatic hydrocarbons

Aromaticity (Hückel's rule): a ring is aromatic if it is cyclic, planar, fully conjugated, and has π electrons (). Benzene (6 π electrons, ) is the archetype — unusually stable, with all C–C bonds equal (resonance hybrid).

Electrophilic aromatic substitution (EAS) is benzene's signature reaction — it substitutes rather than adds, to preserve aromaticity. Five standard reactions, all via an electrophile attacking the π cloud:

ReactionElectrophileReagents
NitrationNO₂⁺conc. HNO₃ + conc. H₂SO₄
SulphonationSO₃fuming H₂SO₄
HalogenationX⁺X₂ + Lewis acid (FeCl₃)
Friedel–Crafts alkylationR⁺R–X + AlCl₃
Friedel–Crafts acylationRCO⁺RCOCl + AlCl₃

Directing effects — a group already on the ring steers the next one:

  • Ortho/para directors (activating): –OH, –NH₂, –OR, –CH₃, halogens (halogens are o/p-directing but deactivating). They donate electron density (+M/+I).
  • Meta directors (deactivating): –NO₂, –COOH, –CN, –C=O, –SO₃H. They withdraw electron density (−M/−I).

Worked example 8.1. Where does nitration of nitrobenzene occur, and why? The –NO₂ group is a meta director (electron-withdrawing, deactivating), so a second –NO₂ enters the meta position, giving 1,3-dinitrobenzene. The ring also reacts more slowly (deactivated).

Worked example 8.2. Is phenol more or less reactive than benzene toward EAS, and where does substitution occur? More reactive — the –OH group donates electron density (+M), activating the ring — and it is an ortho/para director, so substitution occurs at those positions.


9. Common traps NEET sets here

  • Carbocation stability 3° > 2° > 1°; carbanion stability is the reverse (methyl > 1° > 2° > 3°).
  • Markovnikov (more stable carbocation) vs peroxide/anti-Markovnikov (HBr only).
  • Halogens are o/p-directing but deactivating — the exception to the "activating = o/p" pattern.
  • Aromaticity needs 4n+2 π electrons, planar and fully conjugated — count carefully.
  • Alkyne acidity from character — HC≡CH is acidic; alkanes are not.
  • Bromine-water decolourisation = test for unsaturation (alkene/alkyne).
  • Benzene substitutes, not adds, to keep aromaticity.
  • IUPAC priority: –COOH > –CHO > >C=O > –OH > –NH₂ for the principal suffix.

10. Memory aids

  • "3° cation wins, 3° anion loses" — opposite stability orders.
  • "Markovnikov: rich get richer" — H to the H-rich carbon; peroxide flips it (HBr only).
  • "Halogens: o/p but deactivating" — the directing exception.
  • "4n+2 makes it aromatic" — Hückel's rule.
  • "More s-character, more acidic" > > C–H.
  • "Activators send ortho/para, deactivators send meta" — EAS directing.
  • "Benzene swaps, it never adds" — electrophilic substitution.

11. Exam protocol

  1. Name by IUPAC: longest chain with the principal group, lowest locants, priority suffix.
  2. Classify isomerism (chain/position/functional/tautomer; geometrical/optical) — spot chiral centres and C=C restriction.
  3. Predict reactivity from electronic effects (I, M, hyperconjugation) and intermediate stability (3° cation, methyl anion).
  4. Alkanes: free-radical halogenation (needs UV); staggered > eclipsed.
  5. Alkenes: electrophilic addition by Markovnikov (stable carbocation), peroxide reverses HBr; bromine-water test.
  6. Alkynes: terminal-H acidity from character; hydration to carbonyls.
  7. Aromatics: check 4n+2; EAS reactions and o/p vs meta directing by the substituent already present.

Key formulas & results

Everything to memorise for the exam hall, in one card. Screenshot this for revision.

Carbocation stability
Stabilised by +I, hyperconjugation and resonance; carbanions follow the reverse order.
Markovnikov's rule
Addition goes via the more stable carbocation; peroxides reverse it for HBr only.
Alkyne acidity (s-character)
More s-character holds C–H electrons tighter, making the proton more acidic.
Hückel's rule
Cyclic, planar, fully conjugated ring with 4n+2 π electrons is aromatic (benzene n=1).
Functional-group priority
-COOH > -CHO > {>}C{=}O > -OH > -NH_2
The highest-priority group gets the suffix and the lowest locant.
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Traps NEET UG sets — and how to dodge them

These are the exact option-traps and misreads that cost marks under negative marking.

WATCH OUT
Using the same stability order for carbocations and carbanions.
Carbocation stability is 3° > 2° > 1° > methyl (alkyl groups donate electrons to the positive centre). Carbanion stability is the reverse — methyl > 1° > 2° > 3° — because alkyl groups destabilise the negative charge.
WATCH OUT
Applying the peroxide effect to HCl or HI.
Anti-Markovnikov (peroxide/Kharasch) addition happens only with HBr. HCl and HI always add by the Markovnikov rule, with or without peroxide.
WATCH OUT
Assuming all activating groups and halogens direct the same way.
Most activating groups are ortho/para directors, but halogens are ortho/para directing yet deactivating (they withdraw by −I but donate by +M). This exception is a favourite NEET trap.
WATCH OUT
Miscounting π electrons when testing aromaticity.
Aromaticity needs a cyclic, planar, fully conjugated ring with exactly (4n+2) π electrons. Benzene has 6 (n=1). Count only the delocalised π electrons in the ring.
WATCH OUT
Thinking benzene undergoes addition like an alkene.
Benzene undergoes electrophilic substitution, not addition, because substituting preserves the aromatic sextet and its large resonance stabilisation. Addition would destroy aromaticity and is strongly disfavoured.
WATCH OUT
Choosing the parent chain without the principal functional group.
The parent chain must contain the principal (highest-priority) functional group, which then gets the suffix and lowest locant. –COOH outranks –CHO, which outranks ketone, then –OH, then –NH₂.

Exam-pattern practice

PYQ-style questions with full solutions. Work through them as a readiness check — mark yourself honestly and get your gap report at the end.

Readiness check

Are you exam-ready for Basic Organic Chemistry and Hydrocarbons?

15 problems from this chapter. Try each one, reveal the worked solution, mark yourself honestly — get your gap report at the end.

15 questions~11 min

5-minute revision

The whole chapter, distilled. Read this the night before the exam.

  • IUPAC: longest chain with principal group; priority –COOH > –CHO > C=O > –OH > –NH₂; lowest locants
  • Isomerism: chain, position, functional, metamerism, tautomerism (structural); geometrical, optical (stereo)
  • Electronic effects: inductive (I, distance-decaying), resonance (M, conjugation), hyperconjugation (σ C–H)
  • Carbocation 3°>2°>1°>methyl (allyl/benzyl top); carbanion reverse; radical 3°>2°>1°
  • Electrophiles seek electrons (H⁺, NO₂⁺); nucleophiles donate (OH⁻, CN⁻)
  • Alkanes: free-radical halogenation (UV, chain); staggered > eclipsed
  • Alkenes: Markovnikov (stable carbocation); peroxide reverses HBr only; Br₂ water test; ozonolysis → carbonyls
  • Alkynes: terminal-H acidity from sp character (sp>sp²>sp³); hydration → carbonyl
  • Aromatic: Hückel 4n+2; EAS (nitration, sulphonation, halogenation, Friedel–Crafts); o/p activators vs meta deactivators; halogens o/p but deactivating

NEET UG question blueprint

How this topic is asked, tier by tier — so you can prep to the pattern.

Typical weightage: 20

Question styleMarks eachTypical countWhat it tests
Nomenclature & isomerism~1 Q
Electronic effects & intermediate stability~1–2 Q
Hydrocarbon reactions & aromatic substitution~2 Q
Prep strategy
  • Master IUPAC naming and identify every isomerism type, especially chirality
  • Learn the carbocation/carbanion/radical stability orders and their reasons
  • Drill Markovnikov versus peroxide addition and the bromine-water test
  • Fix aromaticity (4n+2) and the ortho/para-versus-meta directing rules, including the halogen exception

Exam-hall strategy

Battle-tested tips from mentors and toppers for this topic under the sectional clock.

  1. Name by IUPAC: longest chain with the principal group, lowest locants, priority suffix.
  2. Classify isomerism; spot chiral centres and C=C restriction.
  3. Predict reactivity from electronic effects and intermediate stability (3° cation, methyl anion).
  4. Alkanes: free-radical halogenation (UV); alkenes: Markovnikov, peroxide reverses HBr, bromine-water test.
  5. Alkynes: terminal-H acidity from sp character; hydration to carbonyls.
  6. Aromatics: check 4n+2; apply EAS reactions and o/p-versus-meta directing rules.

Beyond the exam

Where this skill shows up in the job you're competing for — and in life.

Drug design and metabolism

Functional groups, chirality and electronic effects determine how a drug molecule binds its target and is metabolised.

Petrochemicals and polymers

Alkanes, alkenes and aromatics from petroleum are the feedstock for plastics, fuels and synthetic materials.

Enantiomers in pharmacology

Optical isomers can differ drastically in biological effect, so chirality is central to safe drug manufacture.

Biochemical reactivity

Nucleophiles, electrophiles and reaction intermediates underlie enzyme mechanisms and metabolic transformations.

Where else this topic is tested

Prepare once, score in every exam that asks it.

JEE MainGOC & hydrocarbon reactions
JEE AdvancedMechanisms, stereochemistry & EAS
CUET (Science)Organic basics & hydrocarbons
State medical/engg CETsIsomerism & reaction MCQs

Questions aspirants ask

Pulled from the Q&A community and mentor sessions.

It comes down to what alkyl groups do to charge. Alkyl groups are electron-donating (+I) and provide C–H bonds for hyperconjugation. For a carbocation, which is electron-deficient, this donated electron density stabilises the positive charge — so more alkyl groups mean more stability, giving 3° > 2° > 1° > methyl. For a carbanion, which is already electron-rich, extra electron donation is destabilising, so the order reverses to methyl > 1° > 2° > 3°. The same alkyl effect helps one intermediate and hurts the other.

When an unsymmetrical reagent like HX adds to an unsymmetrical alkene, Markovnikov's rule says the hydrogen goes to the double-bond carbon that already has more hydrogens, so the halogen ends up on the more substituted carbon. The reason is that this route passes through the more stable carbocation. The rule reverses — anti-Markovnikov addition — only when HBr adds in the presence of peroxides (the Kharasch effect), because the mechanism switches to a free-radical one. This peroxide effect works exclusively for HBr, not HCl or HI.

Acidity of a C–H bond depends on how tightly the carbon holds the bonding electrons, which increases with the s-character of the hybrid orbital. A terminal alkyne's C–H is on an sp carbon (50% s-character), so the electrons are held close to carbon and the hydrogen is released relatively easily as H⁺ — acidic enough to react with strong bases and form metal acetylides. An alkane's C–H is on an sp³ carbon (25% s-character), which holds its electrons loosely from the proton's viewpoint, so it is essentially non-acidic. The order is sp > sp² > sp³.

Benzene's six π electrons are delocalised over the ring, giving a large resonance (aromatic) stabilisation. An addition reaction would break up this aromatic sextet and lose that stabilisation, which is strongly unfavourable. Electrophilic substitution, by contrast, lets an electrophile attack the ring and then restores aromaticity when a proton is lost, keeping the stable sextet intact. That is why benzene reacts by nitration, sulphonation, halogenation and Friedel–Crafts substitution rather than by addition like an alkene.

A group already on the ring changes the electron density at the ortho, meta and para positions. Electron-donating groups (–OH, –NH₂, –CH₃) activate the ring and direct new electrophiles to the ortho and para positions; electron-withdrawing groups (–NO₂, –COOH, –CN) deactivate the ring and direct to the meta position. Halogens are the special case: they withdraw electron density through their strong −I effect (deactivating the ring), but they also donate a lone pair by resonance (+M), which happens to favour the ortho and para positions. So halogens are ortho/para directing yet deactivating.
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