Algebra — Class 9 Maths (Samacheer Kalvi)
TN State Board (Samacheer Kalvi) Class 9 Mathematics, Chapter 3. Polynomials, identities, theorems and equations.
1. About this chapter
This chapter covers polynomials, algebraic identities, factorisation, the remainder and factor theorems, GCD/LCM of polynomials, simultaneous linear equations, and linear inequations in two variables.
2. Polynomials and identities
- A polynomial in x is an expression like aₙxⁿ + … + a₁x + a₀; its degree is the highest power.
- Key identities:
- (a + b)² = a² + 2ab + b²
- (a − b)² = a² − 2ab + b²
- (a + b)(a − b) = a² − b²
- (a + b)³ = a³ + 3a²b + 3ab² + b³
- (a + b + c)² = a² + b² + c² + 2ab + 2bc + 2ca
3. Remainder and factor theorems
- Remainder theorem: when p(x) is divided by (x − a), the remainder is p(a).
- Factor theorem: (x − a) is a factor of p(x) iff p(a) = 0.
- GCD–LCM: for polynomials, GCD × LCM = product of the polynomials.
4. Equations and inequations
- Simultaneous linear equations in two variables: solve by substitution, elimination, or cross-multiplication.
- Linear inequations (e.g., ax + by ≤ c) are represented by a half-plane on the graph.
5. Worked examples
Example 1. Expand (2x + 3)². = (2x)² + 2(2x)(3) + 3² = 4x² + 12x + 9.
Example 2. Find the remainder when p(x) = x³ − 2x + 4 is divided by (x − 1). p(1) = 1 − 2 + 4 = 3.
Example 3. Is (x − 2) a factor of p(x) = x² − 5x + 6? p(2) = 4 − 10 + 6 = 0 → yes, it is a factor.
6. Common mistakes
- Mistake: Forgetting the middle term in (a + b)². Fix: (a + b)² = a² + 2ab + b².
- Mistake: Using p(−a) in the remainder theorem for (x − a). Fix: For (x − a) use p(a); for (x + a) use p(−a).
- Mistake: Treating an inequation like an equation when graphing. Fix: An inequation gives a region (half-plane), not just a line.
7. Practice (book-back style)
- Expand (x − 4)².
- Find the remainder when x³ + 3x² − 4 is divided by (x + 1).
- Is (x + 3) a factor of x² + x − 6?
- Factorise x² − 9.
- State the factor theorem.
8. Answer key
- x² − 8x + 16.
- p(−1) = −1 + 3 − 4 = −2.
- p(−3) = 9 − 3 − 6 = 0 → yes.
- (x + 3)(x − 3).
- (x − a) is a factor of p(x) if and only if p(a) = 0.
9. Quick revision
- Chapter 3 · polynomials, identities, theorems, equations.
- (a + b)² = a² + 2ab + b²; (a + b)(a − b) = a² − b².
- Remainder theorem: remainder of p(x) ÷ (x − a) is p(a).
- Factor theorem: (x − a) is a factor iff p(a) = 0; GCD × LCM = product.
- Solve simultaneous equations by substitution/elimination/cross-multiplication.
