By the end of this chapter you'll be able to…

  • 1Plot points and identify quadrants
  • 2Apply the distance formula
  • 3Use the mid-point and section formulas
  • 4Find points of trisection
  • 5Calculate the centroid of a triangle
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Why this chapter matters
Coordinate Geometry links algebra with the plane. The distance, mid-point, section and centroid formulas give reliable, formula-driven marks in the TN Class 9 exam and prepare students for Class 10 coordinate geometry.

Before you start — revise these

A 5-minute refresher here will save you 30 minutes of confusion below.

Coordinate Geometry — Class 9 Maths (Samacheer Kalvi)

TN State Board (Samacheer Kalvi) Class 9 Mathematics, Chapter 5. Locating points and measuring distances in the plane.


1. About this chapter

This chapter covers the Cartesian system, the distance formula, the mid-point and section formulas, points of trisection, and the centroid.

2. The Cartesian system

  • Two perpendicular axes (x and y) meet at the origin (0, 0), dividing the plane into four quadrants.
  • A point is written as an ordered pair (x, y).

3. Distance and mid-point

  • Distance formula: between A(x₁, y₁) and B(x₂, y₂): d = √[(x₂ − x₁)² + (y₂ − y₁)²].
  • Mid-point formula: mid-point of AB = ((x₁ + x₂)/2, (y₁ + y₂)/2).

4. Section formula and centroid

  • Section formula (point dividing AB in ratio m : n internally): ((m x₂ + n x₁)/(m + n), (m y₂ + n y₁)/(m + n)).
  • Points of trisection divide a segment into three equal parts (ratios 1 : 2 and 2 : 1).
  • Centroid of a triangle with vertices (x₁,y₁), (x₂,y₂), (x₃,y₃): ((x₁ + x₂ + x₃)/3, (y₁ + y₂ + y₃)/3).

5. Worked examples

Example 1. Find the distance between (1, 2) and (4, 6). d = √[(4 − 1)² + (6 − 2)²] = √(9 + 16) = √25 = 5.

Example 2. Find the mid-point of (2, 3) and (6, 7). = ((2 + 6)/2, (3 + 7)/2) = (4, 5).

Example 3. Find the centroid of the triangle with vertices (0,0), (6,0), (0,9). = ((0+6+0)/3, (0+0+9)/3) = (2, 3).

6. Common mistakes

  • Mistake: Forgetting to square inside the distance formula. Fix: d = √[(x₂ − x₁)² + (y₂ − y₁)²].
  • Mistake: Swapping m and n in the section formula. Fix: The ratio m : n multiplies the far then near coordinate carefully — write the formula before substituting.
  • Mistake: Dividing the centroid by 2 instead of 3. Fix: The centroid uses the average of three vertices (÷ 3).

7. Practice (book-back style)

  1. Write the distance formula.
  2. Find the distance between (0, 0) and (3, 4).
  3. Find the mid-point of (−2, 5) and (4, 1).
  4. Find the centroid of (1, 2), (3, 4), (5, 0).
  5. State the section formula.

8. Answer key

  1. d = √[(x₂ − x₁)² + (y₂ − y₁)²].
  2. √(9 + 16) = 5.
  3. ((−2 + 4)/2, (5 + 1)/2) = (1, 3).
  4. ((1+3+5)/3, (2+4+0)/3) = (3, 2).
  5. ((m x₂ + n x₁)/(m + n), (m y₂ + n y₁)/(m + n)).

9. Quick revision

  • Chapter 5 · distance, mid-point, section, centroid.
  • Distance d = √[(x₂−x₁)² + (y₂−y₁)²].
  • Mid-point = ((x₁+x₂)/2, (y₁+y₂)/2).
  • Section (m:n) = ((mx₂+nx₁)/(m+n), (my₂+ny₁)/(m+n)).
  • Centroid = ((x₁+x₂+x₃)/3, (y₁+y₂+y₃)/3).

Key formulas & results

Everything you need to memorise, in one card. Screenshot this for revision.

Distance formula
d = √[(x₂ − x₁)² + (y₂ − y₁)²]
Between two points.
Mid-point formula
((x₁ + x₂)/2, (y₁ + y₂)/2)
Average of the coordinates.
Section formula
((m x₂ + n x₁)/(m + n), (m y₂ + n y₁)/(m + n))
Internal division m : n.
Centroid
((x₁ + x₂ + x₃)/3, (y₁ + y₂ + y₃)/3)
Average of three vertices.
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Common mistakes & fixes

These are the exact errors that cost students marks in board exams. Read them once, save yourself the trouble.

WATCH OUT
Forgetting to square inside the distance formula
d = √[(x₂ − x₁)² + (y₂ − y₁)²].
WATCH OUT
Swapping m and n in the section formula
Write the formula before substituting and keep the ratio order.
WATCH OUT
Dividing the centroid by 2 instead of 3
The centroid averages three vertices (÷ 3).

Practice problems

Try each one yourself before tapping "Show solution". Active recall > rereading.

Q1EASY· Recall
Write the distance formula.
Show solution
d = √[(x₂ − x₁)² + (y₂ − y₁)²].
Q2EASY· Numerical
Find the distance between (0, 0) and (3, 4).
Show solution
√(9 + 16) = 5.
Q3EASY· Numerical
Find the mid-point of (−2, 5) and (4, 1).
Show solution
((−2 + 4)/2, (5 + 1)/2) = (1, 3).
Q4MEDIUM· Numerical
Find the centroid of (1, 2), (3, 4), (5, 0).
Show solution
((1+3+5)/3, (2+4+0)/3) = (3, 2).
Q5EASY· Recall
State the section formula.
Show solution
((m x₂ + n x₁)/(m + n), (m y₂ + n y₁)/(m + n)).
Q6MEDIUM· Numerical
Find the distance between (1, 2) and (4, 6).
Show solution
√[(4−1)² + (6−2)²] = √25 = 5.

5-minute revision

The whole chapter, distilled. Read this the night before the exam.

  • Chapter 5 of Samacheer Kalvi Class 9 Mathematics.
  • Distance d = √[(x₂−x₁)² + (y₂−y₁)²].
  • Mid-point = ((x₁+x₂)/2, (y₁+y₂)/2).
  • Section (m:n) = ((mx₂+nx₁)/(m+n), (my₂+ny₁)/(m+n)).
  • Centroid = ((x₁+x₂+x₃)/3, (y₁+y₂+y₃)/3).
  • Mid-point is the section formula with m = n = 1.

Tamil Nadu (TNBSE) marks blueprint

Where the marks come from in this chapter — so you can plan your prep.

Typical chapter weightage: 6-10 marks across MCQ, distance and centroid problems

Question typeMarks eachTypical countWhat it tests
MCQ11-2Quadrants and formulas
Short Answer2-31-2Distance, mid-point, section
Centroid / Trisection2-31Centroid and trisection points
Prep strategy
  • Memorise the four formulas
  • Practise distance and mid-point sums
  • Use the section formula carefully
  • Average three vertices for the centroid

Where this shows up in the real world

This chapter isn't just an exam topic — it lives in the world around you.

Mapping

Distances and mid-points locate places on coordinate maps.

Computer graphics

Points and centroids position and balance shapes.

Navigation

Coordinates describe routes and positions.

Exam strategy

Battle-tested tips from teachers and toppers for this chapter.

  1. Write the formula before substituting
  2. Square the differences in the distance formula
  3. Keep the ratio order in the section formula
  4. Divide by 3 for the centroid

Going beyond the textbook

For olympiad aspirants and curious learners — topics that build on this chapter.

  • Show that the diagonals of a parallelogram bisect each other using mid-points.
  • Find a point dividing a segment externally in a given ratio.

Where else this chapter is tested

CBSE board isn't the only one — other exams test this chapter too.

TN Class 9 Annual ExamHigh
Foundation / NTSE MathematicsMedium
School unit testsHigh

Questions students ask

The real ones — pulled from the Q&A community and tutor sessions.

When the ratio is 1 : 1, the section formula reduces to the average of the coordinates, which is exactly the mid-point.

It is the point where the three medians meet — the triangle's balancing point — found by averaging the vertices' coordinates.
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Last reviewed on 3 June 2026. Written and reviewed by subject-matter experts — read about our process.
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