By the end of this chapter you'll be able to…

  • 1Distinguish transverse from longitudinal waves and explain why gases carry only longitudinal waves
  • 2Interpret the progressive wave equation y(x,t) = a sin(kx - omega t + phi), including direction of travel from its sign
  • 3Derive and apply the wave speed formulas for a stretched string and for sound in a gas, solid, and Laplace-corrected air
  • 4Apply the principle of superposition to find resultant amplitude for constructive and destructive interference
  • 5Explain the phase change on reflection at rigid and free boundaries
  • 6Derive the normal-mode frequencies of a stretched string and of pipes open or closed at one end
  • 7Derive the beat frequency from the superposition of two close frequencies
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Why this chapter matters
Every mechanism behind sound, music, and vibration in the syllabus traces back to this chapter: why instruments only play certain notes, why the speed of sound in air took a genuine scientific correction to get right, and why two nearly-identical frequencies produce an audible throb neither one makes alone. It is also the direct bridge to electromagnetic waves and optics in Class 12.

Waves

1. What this chapter covers

Textbook sectionTopic
14.1Introduction
14.2Transverse and longitudinal waves
14.3Displacement relation in a progressive wave
14.4The speed of a travelling wave
14.5The principle of superposition of waves
14.6Reflection of waves
14.7Beats

Chapter 13 studied a single oscillator in isolation. A material medium is a vast collection of them, coupled together by elastic forces — displace one, and its neighbours feel it too. That coupling is what makes a wave possible, and everything in this chapter follows from taking Chapter 13's oscillator equations and asking what happens when they are chained together.


2. A wave moves; the medium mostly doesn't

Watch cork pieces floating on a pond after a pebble drop: they bob up and down but never drift outward with the expanding ripple. The disturbance travels; the water, on average, stays put. This is the definition of a wave — a pattern that propagates through a medium without net transport of the medium itself. A wind (air moving as a whole) is not a sound wave (a pressure disturbance propagating through air that stays put).

Picture a chain of springs, each connected to the next. Pull one end and release: the disturbance travels down the chain, but each spring only oscillates about its own equilibrium length — nothing travels bodily from one end to the other, the same way a shove at the front of a coupled train of railway bogies passes backward through the couplings without the whole train lurching forward as one block.

Sound in air works the same way: a compressed region pushes its neighbour, which compresses in turn and leaves the original region rarefied, and the compression-rarefaction pattern walks forward through air that never travels far from where it started.


3. Transverse and longitudinal waves — and why gases can't do both

If the medium's constituents oscillate perpendicular to the direction the wave travels, the wave is transverse (a jerk on a string). If they oscillate along the direction of travel, the wave is longitudinal (sound in a pipe, driven by a piston pushing and pulling).

This distinction is not just descriptive — it decides which media can carry which wave at all. A transverse wave shears each element of the medium sideways, so it needs a medium that can sustain shear stress: solids can, fluids cannot (a fluid just flows instead of springing back).

A longitudinal wave only ever compresses or stretches the medium along its own direction, which needs only a bulk or compressive modulus — present in solids, liquids, and gases. That is the entire reason steel can carry both wave types while air carries only longitudinal ones.


4. The displacement relation: one equation, read two different ways

A sinusoidal travelling wave moving in the positive x-direction is:

  • amplitude, the maximum displacement.
  • — the phase.
  • — the initial phase angle (phase at ); origin and clock start can always be chosen to make without loss of generality.
  • angular wave number, radians per metre.
  • angular frequency.

This single function answers two different questions depending on which variable you freeze. Fix time : the equation becomes a function of alone, giving the wave's shape in space at that instant. Fix position : it becomes a function of alone, showing that every constituent of the medium executes SHM — this is the direct link back to Chapter 13.

A wave written as — with a plus sign between the terms — travels in the negative x-direction instead. The sign between and is the entire direction indicator; nothing else in the equation needs to change.

Worked example. For m: gives cm; gives s and Hz.


5. Speed of a wave: a property of the medium, not of the wave itself

Track a fixed point on the wave — a crest, say — and ask how fast it moves. The condition "same phase" means , and differentiating gives the wave speed directly:

The genuinely important fact hiding in this simple relation: wave speed is set entirely by the medium's own inertial and elastic properties — tension and mass density for a string, bulk modulus and density for sound — never by the wavelength or frequency of the wave passing through. A source picks the frequency; the medium's speed then fixes the wavelength via , not the other way around.

Speed on a stretched string

Dimensional analysis alone can narrow the formula down but never fix its numerical constant — tension has dimension , linear mass density has dimension , and only combines to the dimension of speed . A full derivation from Newton's laws (outside this book's scope) shows the missing constant is exactly 1:

Speed of sound: Newton got it wrong, and the fix is worth knowing

For a longitudinal wave, dimensional analysis on bulk modulus and density gives . For a solid bar under longitudinal strain, the relevant modulus is Young's modulus instead: .

Newton assumed sound propagates through air isothermally, which makes (from the ideal gas law at constant ), giving . Applied to air at STP, this predicts about 280 m/s — roughly 15% below the measured 331 m/s.

Laplace identified the error: pressure changes in a sound wave happen far too fast for heat to flow and keep temperature constant, so the process is adiabatic, not isothermal. For an adiabatic ideal gas, instead of just , giving the corrected formula:

With for air, this predicts 331.3 m/s — matching experiment. The lesson is as much about scientific method as physics: dimensional analysis got the form right immediately, but only identifying the correct physical assumption (adiabatic, not isothermal) got the number right.


6. Superposition: waves pass through each other unchanged

When two wave pulses meet, the net displacement at every point is simply the algebraic sum of what each pulse would have produced alone — the principle of superposition. After they cross, each pulse continues on exactly as if the other had never been there.

For two waves of equal amplitude , same and , differing only by phase constant :

still a travelling wave at the same frequency, but now with amplitude — a function of the phase difference alone. At (in phase), amplitude is the maximum possible, : constructive interference. At (exactly out of phase), amplitude is zero everywhere, for all time: destructive interference. Nothing about the individual waves' energy is destroyed — it is redistributed to wherever the interference is constructive elsewhere.


7. Reflection: a phase flip at a wall, none at a free end

At a rigid boundary, the medium there is physically forced to stay at zero displacement always — the only way superposition can guarantee that is if the reflected wave is exactly out of phase with the incident one, cancelling it at that point at every instant. Equivalently: the incident pulse pushes on the wall, and by Newton's third law the wall pushes back, generating a reflected pulse inverted relative to the original.

At a free (open) boundary — like a string end tied to a ring that slides freely — nothing constrains the displacement there, so the reflected wave keeps the same phase as the incident one, and the two add constructively at that point, reaching twice the single-pulse amplitude momentarily.

BoundaryPhase change on reflection
Rigid (fixed end, closed pipe end)
Free (open end)

8. Standing waves: when reflection happens at both ends

A wave travelling right, , and its reflection travelling left, , superpose to:

Notice and no longer appear in the combination — they appear separately. This pattern does not travel in either direction; it is a standing (stationary) wave. Every point oscillates with the same angular frequency , but the amplitude depends on position: zero at nodes (), maximum at antinodes (). Adjacent nodes (or adjacent antinodes) are always separated by .

Boundary conditions — where the physical setup forces a node or antinode — restrict a standing-wave system to a discrete set of allowed frequencies, unlike a travelling wave which can have any frequency at all.

SystemBoundary patternAllowed frequenciesFundamental
String, both ends fixednode — node (all harmonics)
Pipe, one end closednode — antinode (odd harmonics only)
Pipe, both ends openantinode — antinode (all harmonics)

Worked example. A pipe 30 cm long, open at both ends, needs to resonate with a 1.1 kHz source ( m/s). Its harmonics are Hz, so gives exactly 1100 Hz — the source excites the second harmonic.

Close one end of the same pipe: only odd harmonics survive, at Hz — 275, 825, 1375 Hz, and so on. Since 1100 Hz never appears in that list, no resonance occurs once the end is closed.

A string or air column rarely vibrates in a single pure mode — real vibration is usually a superposition of several harmonics at once, with the relative strength of each depending on how and where the string is plucked or bowed.

This is why a sitar and a violin playing the identical fundamental note still sound distinguishably different: the note's pitch is set by the fundamental frequency, but its timbre — the mix of overtones riding on top of it — is what your ear actually uses to tell the two instruments apart.


9. Beats: the audible throb of two close frequencies

Superpose two waves of nearly equal (not identical) frequency and :

where is the fast average frequency you actually hear as pitch, and is a slow envelope modulating the amplitude of that fast oscillation. Because intensity depends on amplitude squared, the loudness waxes and wanes twice per cycle of the envelope, giving a beat frequency of:

Musicians use this directly: two strings are in tune exactly when the beats — that audible throbbing — disappear entirely.

Worked example. Two sitar strings A and B, both playing the same note, produce 5 beats per second. Tightening string B (which raises its frequency) makes the beat frequency drop to 3 beats per second.

Since raising B's frequency reduced the gap, B's frequency must already have been below A's — if it had been above, raising it further would only have widened the gap. With Hz and , string B's original frequency was Hz.


Summary

  • A wave transports a disturbance and energy through a medium without net transport of the medium itself — the water under a ripple, or the air carrying a sound, mostly stays where it started.
  • Transverse waves (perpendicular oscillation) need a shear modulus, so only solids carry them. Longitudinal waves (parallel oscillation) only need a bulk modulus, so solids, liquids, and gases all carry them.
  • describes a wave moving in the direction; a sign between and reverses the direction.
  • Wave speed is fixed by the medium's own properties — never by the wave's own frequency or wavelength.
  • for a string; (or for a solid bar) for longitudinal waves; for a gas, Laplace's adiabatic correction fixes Newton's isothermal formula's 15% error.
  • Superposition: two waves overlapping add algebraically; equal-amplitude waves interfere constructively at (amplitude ) and destructively at (amplitude ).
  • Reflection flips phase by at a rigid boundary, and leaves phase unchanged at a free boundary.
  • Standing waves form when reflection happens at both ends, restricting the system to a discrete ladder of allowed frequencies — every harmonic for a string or open-open pipe, only odd harmonics for a pipe closed at one end.
  • Beats arise from superposing two close-but-different frequencies; the beat frequency is simply their difference, .

Key formulas & results

Everything you need to memorise, in one card. Screenshot this for revision.

Progressive wave displacement
y(x,t) = a sin(kx - omega t + phi)
Plus sign between kx and omega t reverses the direction of travel to -x.
Angular wave number
k = 2 pi / lambda
SI unit radian per metre.
Angular frequency and period
omega = 2 pi / T = 2 pi nu
Same relation as in SHM, since every point in the wave executes SHM.
Wave speed
v = omega / k = lambda nu
Fixed by the medium; frequency is set by the source, wavelength follows from v = lambda nu.
Speed on a stretched string
v = sqrt(T / mu)
T = tension, mu = linear mass density (mass per unit length).
Speed of a longitudinal wave (general)
v = sqrt(B / rho)
B = bulk modulus, rho = density. Applies to any fluid or solid.
Speed of sound in a solid bar
v = sqrt(Y / rho)
Y = Young's modulus, for a thin bar under longitudinal strain.
Speed of sound in a gas (Laplace's correction)
v = sqrt(gamma P / rho)
Adiabatic, not isothermal — fixes Newton's formula v = sqrt(P/rho), which understates speed by about 15%.
Superposition amplitude
A(phi) = 2a cos(phi/2)
phi = 0 gives constructive interference (A = 2a); phi = pi gives destructive (A = 0).
Standing wave
y(x,t) = 2a sin(kx) cos(omega t)
x and t appear separately, not combined — the pattern does not travel.
String fixed at both ends
nu_n = n v / (2L), n = 1, 2, 3, ...
All harmonics present. Fundamental (first harmonic) is v/2L.
Pipe closed at one end
nu_n = (2n - 1) v / (4L), n = 1, 2, 3, ...
Only odd harmonics present. Fundamental is v/4L.
Pipe open at both ends
nu_n = n v / (2L), n = 1, 2, 3, ...
All harmonics present, same formula as a string fixed at both ends.
Beat frequency
nu_beat = |nu_1 - nu_2|
Heard pitch is close to the average of the two frequencies; loudness throbs at the difference frequency.
Node/antinode spacing
spacing = lambda / 2
Distance between two consecutive nodes, or two consecutive antinodes, in any standing wave.
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Common mistakes & fixes

These are the exact errors that cost students marks in board exams. Read them once, save yourself the trouble.

WATCH OUT
Getting the direction of travel backwards from the equation's sign
y = a sin(kx - omega t) travels in +x; y = a sin(kx + omega t) travels in -x. Check the sign between the two terms, not just their presence.
WATCH OUT
Believing wave speed depends on the wave's own frequency or wavelength
Speed is fixed entirely by the medium's properties (T and mu for a string; B and rho for sound). The source's frequency then determines wavelength via v = lambda nu, not the reverse.
WATCH OUT
Using Newton's formula v = sqrt(P/rho) for the speed of sound in a gas
This assumes isothermal compression and understates the speed by about 15%. Sound compressions happen too fast for heat exchange, so the process is adiabatic: use v = sqrt(gamma P/rho).
WATCH OUT
Assuming wavelength stays the same when a wave crosses into a new medium
Frequency stays fixed (set by the source); speed changes with the medium, so wavelength must change too, via lambda = v/nu.
WATCH OUT
Assuming transverse waves can propagate through a gas or liquid
Transverse waves need a shear modulus, which only solids have. Gases and liquids can only carry longitudinal waves.
WATCH OUT
Mixing up which boundary causes a phase reversal
Rigid/fixed boundary: pi phase change. Free/open boundary: no phase change. This is often remembered backwards.
WATCH OUT
Using the string/open-pipe formula (all harmonics) for a pipe closed at one end
A pipe closed at one end supports only ODD harmonics: nu_n = (2n-1)v/4L. Using nu_n = nv/4L for all n silently invents harmonics that don't exist.
WATCH OUT
Confusing node/antinode spacing (lambda/2) with the wavelength itself
Wavelength is the distance between two points of the SAME phase (like two nodes two positions over); adjacent node-to-node or antinode-to-antinode spacing is only half of that.
WATCH OUT
Assuming every point on a standing wave shares the same phase
All points share the same period, but points in adjacent segments (separated by a node) oscillate exactly pi out of phase with each other, even though they share the same frequency.
WATCH OUT
Confusing beat frequency with the pitch actually heard
The heard pitch is close to the average of the two frequencies; the beat frequency (their difference) is heard as a separate, slower throbbing in loudness, not as the pitch itself.
WATCH OUT
Ignoring end correction in resonance-tube or organ-pipe problems
The antinode at an open pipe end actually forms slightly beyond the physical opening, so measured resonance lengths are always a little shorter than the idealised quarter/half-wavelength position predicts.
WATCH OUT
Treating a superposition of two different frequencies as a simple standing wave
A standing wave needs two waves of the SAME frequency travelling in opposite directions. Two different frequencies superposing instead produce beats, a completely different phenomenon.

Practice problems

Work through this chapter's problems as a readiness check — reveal each solution, mark yourself honestly, and get your gap report at the end.

Readiness check

Are you exam-ready for Waves?

10 problems from this chapter. Try each one, reveal the worked solution, mark yourself honestly — get your gap report at the end.

10 questions~7 min worth ~10 marks in IGCSE exams

5-minute revision

The whole chapter, distilled. Read this the night before the exam.

  • A wave transports a disturbance and energy without net transport of the medium itself.
  • Transverse waves need a shear modulus (solids only); longitudinal waves need only a bulk modulus (solids, liquids, and gases).
  • y(x,t) = a sin(kx - omega t + phi) travels in +x; a + sign between kx and omega t means -x instead.
  • v = omega/k = lambda nu is fixed by the medium; frequency comes from the source, wavelength follows.
  • v = sqrt(T/mu) for a string; v = sqrt(gamma P/rho) for sound in a gas (Laplace's adiabatic correction to Newton's isothermal formula, which understates speed by about 15%).
  • Superposition: A(phi) = 2a cos(phi/2); phi=0 gives constructive interference (2a), phi=pi gives destructive (0).
  • Reflection: pi phase change at a rigid boundary, no phase change at a free boundary.
  • Standing waves: y(x,t) = 2a sin(kx) cos(omega t); nodes and antinodes alternate every lambda/2.
  • String fixed both ends and pipe open both ends: all harmonics, nu_n = nv/2L. Pipe closed one end: only odd harmonics, nu_n = (2n-1)v/4L.
  • Beats: nu_beat = |nu_1 - nu_2|, from superposing two close-but-different frequencies.

IGCSE marks blueprint

Where the marks come from in this chapter — so you can plan your prep.

Typical chapter weightage: 10 marks shared between this chapter and Chapter 13 (Oscillations); no official per-chapter split is published

Question typeMarks eachTypical countWhat it tests
Wave equation, speed and displacement relation2-31Reading amplitude/wavelength/frequency/direction from y(x,t), applying v = sqrt(T/mu) and Laplace's speed-of-sound formula
Superposition, reflection and standing waves3-51Constructive/destructive interference amplitude, phase change on reflection, node/antinode positions
Normal modes, organ pipes and beats3-51String and pipe harmonic formulas, resonance-tube speed of sound, beat frequency reasoning
Prep strategy
  • Practise reading amplitude, k, omega, and direction of travel directly off a given wave equation without needing to re-derive them
  • Keep the three normal-mode formula rows (string, closed pipe, open pipe) straight — closed pipe is the one exception carrying only odd harmonics
  • Be able to state why Laplace's correction is needed, not just quote the corrected formula
  • Practise beats problems that require reasoning about which frequency is higher from how the beat frequency changes
  • For resonance-tube problems, remember successive resonance lengths differ by lambda/2, not lambda

Where this shows up in the real world

This chapter isn't just an exam topic — it lives in the world around you.

Musical instruments

Every stringed and wind instrument is an application of normal modes — string length and tension, or pipe length and whether it is open or closed, together fix which notes an instrument can play.

Tuning by ear

Musicians tune instruments by listening for beats between two notes and adjusting tension or length until the beats slow to zero, a direct practical use of the beat-frequency formula.

Ultrasound imaging

Medical ultrasound scanners rely on the wavelength-speed-frequency relation to interpret how sound reflects off tissue boundaries of different density, turning wave physics into a diagnostic image.

Echolocation

Bats and sonar systems both use reflected wave timing and frequency shifts to determine distance, direction, and the nature of an obstacle without ever seeing it directly.

Exam strategy

Battle-tested tips from teachers and toppers for this chapter.

1
Identify k and omega directly from the given wave equation before doing anything else — nearly every numerical in this chapter starts there
2
For speed-of-sound problems in a gas, default to Laplace's corrected formula unless the question explicitly asks about Newton's (incorrect) assumption
3
For pipe problems, first decide open-both-ends, closed-one-end, or a string — each has a different allowed-harmonics rule
4
For beats problems that involve changing tension or loading, reason through whether the changing frequency increases or decreases the gap before assigning which frequency is higher
5
For resonance-tube problems, use the LENGTH DIFFERENCE between successive resonances (equal to lambda/2), not either individual length alone, to find wavelength

Going beyond the textbook

For olympiad aspirants and curious learners — topics that build on this chapter.

STRETCH
Derive the Doppler effect formulas for a moving source, moving observer, and both moving simultaneously, and analyse the discontinuity that produces a sonic boom.
STRETCH
Investigate dispersive media, where wave speed depends on frequency, and derive the distinction between phase velocity and group velocity for a wave packet.
STRETCH
Analyse two-dimensional standing waves on a circular membrane (like a tabla), and find the pattern of nodal lines for low-order modes.
STRETCH
Study the intensity and energy density carried by a travelling wave, and derive how intensity falls off with distance from a point source in three dimensions.
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JEE Main & Advanced practice

Competitive-level problems on this chapter, above the board pattern. Try each one on paper before opening the solution.

JEE MainInterference intensityFormula application

Two coherent waves of equal amplitude, each of intensity , superpose with a phase difference of . Find the resultant intensity in terms of .

Stuck? Show the approach

Find the resultant amplitude using , then use that intensity is proportional to amplitude squared to convert back to intensity.

Show the full solution

Since and :

Answer: The resultant intensity is 3 I0.
The trap

A common error is adding intensities directly (I0 + I0 = 2I0) as if the waves were incoherent — coherent superposition must go through amplitude first using A(phi) = 2a cos(phi/2), then square, which gives a different and phase-dependent answer.

JEE MainFundamental frequency from consecutive harmonicsReasoning with formula

A string fixed at both ends resonates at 300 Hz and 400 Hz, with no resonant frequency of the string lying between them. Find the fundamental frequency of the string.

Stuck? Show the approach

For a string fixed at both ends, every harmonic is an integer multiple of the fundamental, so consecutive harmonics always differ by exactly one fundamental frequency.

Show the full solution

If 300 Hz and 400 Hz are consecutive harmonics and :

Check: and , both integers, confirming they are indeed the 3rd and 4th harmonics.

Answer: The fundamental frequency is 100 Hz.
The trap

This only works because the two given frequencies are stated to be CONSECUTIVE harmonics with nothing in between — without that condition, the difference between two arbitrary harmonics is not necessarily the fundamental itself, only some integer multiple of it.

JEE MainReflection and echo timingNumeric, two-part

A person standing between two vertical cliffs claps once and hears two distinct echoes, one after 1.5 s and the other after 3.5 s. Taking the speed of sound as 340 m/s, find the distance between the two cliffs.

Stuck? Show the approach

Each echo time corresponds to sound travelling to a cliff AND back, so divide each time by 2 before multiplying by speed to get the one-way distance to each cliff.

Show the full solution

Total distance between the cliffs (person is between them, cliffs on opposite sides):

Answer: The two cliffs are 850 m apart.
The trap

Forgetting to halve each echo time is the single most common error here — the given times are round-trip times (to the cliff and back), not one-way travel times.

JEE AdvancedStanding wave — full characterisationMulti-part numeric

A standing wave on a string is m, with in metres. (a) Find the wavelength, frequency, and speed of the two component travelling waves. (b) Find the amplitude of oscillation of a particle at m. (c) Find the positions of the nodes between and m.

Stuck? Show the approach

Compare the given equation to the standard standing-wave form to read off and directly, then use the amplitude formula for part (b), and set for part (c).

Show the full solution

(a) m. Hz. m/s.

(b) Amplitude at : . At : m.

(c) Nodes where : . Within m: m and m.

Answer: (a) Wavelength 4 m, frequency 50 Hz, speed 200 m/s. (b) Amplitude at x=0.5 m is about 0.0283 m. (c) Nodes at x=0 m and x=2 m.
The trap

Reading off k and omega from the equation is only the first step — plugging the SPECIFIC x value into the full amplitude function 2a sin(kx), rather than using the coefficient 0.04 alone as if it were a constant amplitude, is what part (b) actually tests.

JEE AdvancedMatching harmonics across an open and a closed pipeConceptual with derivation

An open organ pipe of length has its fundamental frequency equal to the SECOND OVERTONE of a closed organ pipe of length m. Find .

Stuck? Show the approach

A closed pipe supports only odd harmonics, so its overtones are not simply the next integers after the fundamental — the first overtone is the 3rd harmonic, and the second overtone is the 5th harmonic. Identify the correct harmonic number before equating frequencies.

Show the full solution

Closed pipe harmonics: fundamental (1st harmonic, ) ; first overtone (3rd harmonic) ; second overtone (5th harmonic) .

Open pipe fundamental: . Setting them equal:

Answer: L1 = 0.2 m.
The trap

The second overtone of a CLOSED pipe is the 5th harmonic, not the 3rd — closed-pipe overtone numbering skips the even harmonics entirely, and treating 'second overtone' as simply 'third harmonic' (as you would for an open pipe or a string) gives a wrong answer.

Where else this chapter is tested

CBSE board isn't the only one — other exams test this chapter too.

CBSE Class 11 Physics examHigh
JEE Main and Advanced (Waves)High
NEET PhysicsMedium

Questions students ask

The real ones — pulled from the Q&A community and tutor sessions.

Newton assumed the pressure changes during sound propagation happen slowly enough for the gas to stay at constant temperature (isothermal), which gives v = sqrt(P/rho). In reality, compressions and rarefactions in a sound wave happen far too fast for heat to flow and equalise temperature, so the process is adiabatic instead. Laplace corrected this to v = sqrt(gamma P/rho), which matches the measured speed almost exactly — Newton's version understates it by about 15%.

A transverse wave requires the medium to resist being sheared sideways and spring back — a property measured by shear modulus, which only solids possess. Gases (and liquids) simply flow when sheared instead of springing back, so they have no shear modulus at all. They can still carry longitudinal waves because compressing a gas does generate a restoring pressure, governed by its bulk modulus, which every state of matter has.

The difference comes from the boundary conditions. A string fixed at both ends needs a node at both ends, which fits any integer number of half-wavelengths, allowing every harmonic. A pipe closed at one end needs a node at the closed end but an ANTINODE at the open end — this asymmetric requirement only fits an odd number of quarter-wavelengths in the pipe, which is exactly what restricts it to odd harmonics only.

It depends on whether you mean displacement or pressure, and the two are opposite. A displacement node (where air molecules barely move) is exactly where pressure varies the MOST, since neighbouring layers are being compressed together maximally there. A displacement antinode (where molecules swing most freely) is where pressure barely changes, since nearby layers are moving together in the same direction with little relative compression.

The superposition principle covered earlier assumes the SAME frequency for both waves, producing a fixed pattern of constructive or destructive interference that does not change with time. Beats arise specifically when the two frequencies are close but NOT equal — the interference pattern itself now slowly changes with time, which is heard as a periodic waxing and waning of loudness at the difference frequency, rather than a fixed louder-or-quieter result.

No — the rationalised 2026-27 edition does not include Doppler effect anywhere in this chapter, and CBSE's own Unit X syllabus line does not list it either. It reappears later in the physics curriculum, but for this chapter and this exam, it is not examinable content.
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Last reviewed on 7 August 2026. Written and reviewed by subject-matter experts — read about our process.
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