By the end of this chapter you'll be able to…

  • 1Define an algebraic identity
  • 2Apply the standard identities to expand expressions
  • 3Use identities for quick computation
  • 4Expand (x + a)(x + b)
  • 5Solve and represent linear inequations
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Why this chapter matters
Algebraic identities make expansions and mental calculation fast, and inequations describe ranges of values. Both are directly tested in the TN Class 7 Term 3 exam and are essential for higher algebra.

Before you start — revise these

A 5-minute refresher here will save you 30 minutes of confusion below.

Algebra (Identities and Inequations) — Class 7 Maths (Samacheer Kalvi)

TN State Board (Samacheer Kalvi) Class 7 Mathematics, Term 3 — Chapter 3. Algebraic identities and linear inequalities.


1. About this chapter

This chapter covers algebraic identities and their expansions, the expansion of (x + a)(x + b), and linear inequations — solving them and showing them on a number line.

2. Algebraic identities

An identity is an equation true for all values of the variables. The standard identities are:

IdentityExpansion
(a + b)²a² + 2ab + b²
(a − b)²a² − 2ab + b²
(a + b)(a − b)a² − b²
(x + a)(x + b)x² + (a + b)x + ab

3. Using identities

  • They give a quick way to expand or compute. Example: 102² = (100 + 2)² = 100² + 2·100·2 + 2² = 10000 + 400 + 4 = 10404.
  • Example: 99 × 101 = (100 − 1)(100 + 1) = 100² − 1² = 9999.

4. Linear inequations

  • An inequation uses <, >, ≤ or ≥ instead of "=" (e.g. x + 3 > 7).
  • Solve like an equation by doing the same operation on both sides, but if you multiply or divide by a negative number, reverse the inequality sign.
  • Example: x + 3 > 7 → x > 4. On the number line, show all points to the right of 4 (open circle at 4).

5. Worked examples

Example 1. Expand (x + 5)². x² + 2·x·5 + 5² = x² + 10x + 25.

Example 2. Expand (y − 3)(y − 3) using an identity. (y − 3)² = y² − 6y + 9.

Example 3. Solve 2x − 1 < 9. 2x < 10 → x < 5.

6. Exercises (Samacheer Kalvi)

  1. Expand: (a) (a + 7)² (b) (m − 4)².
  2. Expand using an identity: (x + 6)(x − 6).
  3. Find 103² using an identity.
  4. Expand (x + 2)(x + 5).
  5. Solve and show on a number line: (a) x − 2 ≥ 3 (b) 3x ≤ 12.

7. Common mistakes

  • Mistake: Writing (a + b)² = a² + b². Fix: (a + b)² = a² + 2ab + b² — don't forget the middle term 2ab.
  • Mistake: Forgetting to reverse the sign when dividing by a negative. Fix: Multiplying/dividing an inequation by a negative flips < to >.
  • Mistake: Mixing up (a − b)² and (a + b)(a − b). Fix: (a − b)² = a² − 2ab + b²; (a + b)(a − b) = a² − b².

8. Quick revision

  • Term 3 · Ch 3 · identities and inequations.
  • (a + b)² = a² + 2ab + b²; (a − b)² = a² − 2ab + b²; (a + b)(a − b) = a² − b²; (x + a)(x + b) = x² + (a + b)x + ab.
  • Use identities to expand and compute quickly (e.g. 99 × 101 = 9999).
  • Solve inequations like equations; reverse the sign when multiplying/dividing by a negative; show the solution on a number line.

Key formulas & results

Everything you need to memorise, in one card. Screenshot this for revision.

(a + b)²
a² + 2ab + b²
Square of a sum.
(a − b)²
a² − 2ab + b²
Square of a difference.
(a + b)(a − b)
a² − b²
Difference of squares.
(x + a)(x + b)
x² + (a + b)x + ab
Product of two binomials.
⚠️

Common mistakes & fixes

These are the exact errors that cost students marks in board exams. Read them once, save yourself the trouble.

WATCH OUT
Writing (a + b)² = a² + b²
(a + b)² = a² + 2ab + b² — don't forget the middle term 2ab.
WATCH OUT
Forgetting to reverse the sign when dividing an inequation by a negative
Multiplying or dividing an inequation by a negative flips < to > (and ≤ to ≥).
WATCH OUT
Mixing up (a − b)² and (a + b)(a − b)
(a − b)² = a² − 2ab + b²; (a + b)(a − b) = a² − b².

Practice problems

Try each one yourself before tapping "Show solution". Active recall > rereading.

Q1EASY· Expand
Expand (x + 5)².
Show solution
x² + 10x + 25.
Q2EASY· Expand
Expand (m − 4)².
Show solution
m² − 8m + 16.
Q3EASY· Identity
Expand (x + 6)(x − 6).
Show solution
x² − 36.
Q4MEDIUM· Compute
Find 103² using an identity.
Show solution
(100 + 3)² = 10000 + 600 + 9 = 10609.
Q5MEDIUM· Expand
Expand (x + 2)(x + 5).
Show solution
x² + 7x + 10.
Q6MEDIUM· Inequation
Solve 2x − 1 < 9 and describe the solution.
Show solution
2x < 10 → x < 5; all values less than 5 (open circle at 5 on the number line).

5-minute revision

The whole chapter, distilled. Read this the night before the exam.

  • Term 3 Chapter 3 of Samacheer Kalvi Class 7 Maths.
  • An identity is true for all values of the variables.
  • (a + b)² = a² + 2ab + b²; (a − b)² = a² − 2ab + b².
  • (a + b)(a − b) = a² − b²; (x + a)(x + b) = x² + (a + b)x + ab.
  • Identities speed up expansions and mental computation.
  • Solve inequations like equations but reverse the sign when multiplying/dividing by a negative; show on a number line.

Tamil Nadu (TNBSE) marks blueprint

Where the marks come from in this chapter — so you can plan your prep.

Typical chapter weightage: 6-10 marks across expansions and inequations

Question typeMarks eachTypical countWhat it tests
Expand1-23Standard identities
Compute21Using identities on numbers
Inequation21-2Solving and representing
Prep strategy
  • Memorise the four identities
  • Always include the middle term 2ab
  • Use identities to shortcut number squares
  • Reverse the sign when dividing by a negative

Where this shows up in the real world

This chapter isn't just an exam topic — it lives in the world around you.

Mental maths

Identities let you square and multiply numbers quickly.

Algebra ahead

Identities are used in factorisation and higher algebra.

Constraints

Inequations describe limits like budgets and capacities.

Exam strategy

Battle-tested tips from teachers and toppers for this chapter.

  1. Quote the identity before expanding
  2. Always write the 2ab middle term
  3. Rewrite numbers as (100 ± a) for quick squares
  4. Mark the inequality solution on a number line

Going beyond the textbook

For olympiad aspirants and curious learners — topics that build on this chapter.

  • Use identities to evaluate 97 × 103 mentally.
  • Solve −2x + 5 ≥ 1 and explain the sign reversal.

Where else this chapter is tested

CBSE board isn't the only one — other exams test this chapter too.

TN Class 7 Term 3 ExamHigh
NMMS / Foundation MathsMedium
School unit testsHigh

Questions students ask

The real ones — pulled from the Q&A community and tutor sessions.

Because squaring a sum multiplies (a + b) by itself, which produces the cross terms ab + ab = 2ab in the middle, giving a² + 2ab + b².

Only when you multiply or divide both sides of an inequation by a negative number; adding, subtracting or multiplying/dividing by a positive keeps the sign the same.
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Last reviewed on 3 June 2026. Written and reviewed by subject-matter experts — read about our process.
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