Motion in One Dimension

Introduction

Motion is a fundamental concept in physics. When an object moves along a straight line, it is said to be in one-dimensional motion. ICSE Class 9 covers the basic parameters of motion and the equations that describe uniformly accelerated motion.

Basic Concepts

Distance and Displacement

ParameterDistanceDisplacement
DefinitionTotal path lengthShortest straight-line distance from start to end
Scalar/VectorScalarVector
ValueAlways positivePositive, negative, or zero
DependenceDepends on pathIndependent of path

Speed and Velocity

ParameterSpeedVelocity
DefinitionDistance/timeDisplacement/time
Scalar/VectorScalarVector
FormulaSpeed = Distance/TimeVelocity = Displacement/Time

Acceleration

Acceleration = Change in velocity / Time taken = (v - u)/t

Unit: m/s²

  • Positive acceleration: velocity increases with time
  • Negative acceleration (retardation/deceleration): velocity decreases with time
  • Zero acceleration: uniform velocity

Distance-Time and Speed-Time Graphs

Distance-Time Graph

  • Straight line through origin: Uniform speed
  • Horizontal line: Object at rest
  • Curved line: Non-uniform speed
  • Slope = speed

Speed-Time Graph

  • Horizontal line: Uniform acceleration
  • Straight line through origin: Uniform acceleration starting from rest
  • Area under graph: Distance travelled
  • Slope = acceleration
<ICSEExample title="Interpret Speed-Time Graph"> A car accelerates uniformly from rest to 20 m/s in 10 s and then travels at constant speed for 20 s. Draw the speed-time graph and find total distance. <Solution> Distance = Area under graph = Area of triangle + Area of rectangle = 1/2 × 10 × 20 + 20 × 20 = 100 + 400 = 500 m </Solution> </ICSEExample>

Equations of Motion

For uniformly accelerated motion:

  1. v = u + at
  2. s = ut + 1/2 × at²
  3. v² = u² + 2as

Where:

  • u = initial velocity (m/s)
  • v = final velocity (m/s)
  • a = acceleration (m/s²)
  • t = time (s)
  • s = displacement (m)
<ICSEExample title="Using Equations of Motion"> A car starts from rest and accelerates at 2 m/s² for 5 seconds. Find its velocity and distance travelled. <Solution> u = 0 m/s, a = 2 m/s², t = 5 s v = u + at = 0 + 2×5 = 10 m/s s = ut + 1/2 × at² = 0 + 1/2 × 2×25 = 25 m </Solution> </ICSEExample> <ICSEExample title="Finding Deceleration"> A car moving at 20 m/s comes to rest after travelling 50 m. Find the deceleration. <Solution> u = 20 m/s, v = 0 m/s, s = 50 m v² = u² + 2as 0 = 400 + 2×a×50 100a = -400 a = -4 m/s² (deceleration of 4 m/s²) </Solution> </ICSEExample>

Free Fall

Free fall is the motion of an object under the influence of gravity only.

For free fall:

  • a = g = 9.8 m/s² (downward)
  • u = 0 (if dropped from rest)
<ICSEExample title="Free Fall"> A stone is dropped from a height of 80 m. Find the time taken to reach the ground and the velocity on impact. (g = 10 m/s²) <Solution> u = 0, s = 80 m, a = 10 m/s² s = ut + 1/2 × at² 80 = 0 + 1/2 × 10 × t² 80 = 5t² t² = 16 t = 4 s

v = u + at = 0 + 10×4 = 40 m/s </Solution> </ICSEExample>

Common Mistakes With Fixes

MistakeCorrection
Confusing distance and displacementDistance is total path length; displacement is straight-line
Using equations of motion for non-uniform accelerationEquations of motion apply ONLY for uniform acceleration
Wrong sign convention for free fallDownward direction is usually positive for free fall
Forgetting units in calculationsAlways include units (m, s, m/s, m/s²)

ICSE Exam Focus

TopicMarks (approx.)Frequency
Equations of motion numerical4-5 marksVery common
Distance-time and speed-time graphs4 marksCommon
Free fall problems3-4 marksVery common
Distinguishing scalar and vector quantities2-3 marksCommon

Self-Test

Q1: A car accelerates from 10 m/s to 25 m/s in 5 s. Find the acceleration and distance covered.

Q2: A ball is thrown vertically upwards with a velocity of 30 m/s. Find the maximum height reached. (g = 10 m/s²)

Q3: Distinguish between speed and velocity.

Q4: A train travelling at 72 km/h comes to rest in 10 s. Find the retardation.

Q5: From the speed-time graph of a body, the area under the curve gives what physical quantity?

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