Light - Reflection

Introduction

Light is a form of energy that enables us to see objects. Reflection is the phenomenon where light bounces back from a surface. ICSE Class 9 covers reflection from plane mirrors and spherical mirrors.

Laws of Reflection

  1. The incident ray, reflected ray, and the normal at the point of incidence all lie in the same plane.
  2. The angle of incidence (i) equals the angle of reflection (r).

Terms:

  • Incident ray: Light ray approaching the surface
  • Reflected ray: Light ray leaving the surface
  • Normal: Perpendicular line at the point of incidence
  • Angle of incidence (i): Angle between incident ray and normal
  • Angle of reflection (r): Angle between reflected ray and normal

Plane Mirror - Image Properties

PropertyCharacteristic
NatureVirtual and erect
SizeSame size as object
DistanceImage distance = Object distance
Lateral inversionLeft appears right and vice versa
PositionBehind the mirror

Spherical Mirrors

A spherical mirror is a mirror with a curved reflecting surface that is part of a sphere.

Types

TypeReflecting SurfaceFocal LengthImage Nature
Concave mirrorInward (caves in)Positive (f = R/2)Real and virtual depending on distance
Convex mirrorOutward (bulges out)NegativeAlways virtual, diminished, erect

Key Terms

  • Pole (P): Centre of the mirror surface
  • Centre of curvature (C): Centre of the sphere
  • Radius of curvature (R): Distance from P to C
  • Principal axis: Line joining P and C
  • Focus (F): Point where parallel rays converge/diverges
  • Focal length (f): Distance from P to F = R/2

Ray Diagrams

Concave Mirror (6 Cases)

Object PositionImage PositionNatureSize
At infinityAt FReal, invertedHighly diminished
Beyond CBetween C and FReal, invertedDiminished
At CAt CReal, invertedSame size
Between C and FBeyond CReal, invertedEnlarged
At FAt infinityReal, invertedHighly enlarged
Between P and FBehind mirrorVirtual, erectEnlarged

Convex Mirror (Always)

Image is always virtual, erect, and diminished, located between P and F behind the mirror.

Mirror Formula

1/f = 1/u + 1/v

Where:

  • f = focal length
  • u = object distance (always negative for real objects)
  • v = image distance

Sign Convention:

  • Distances measured from the pole
  • Distances in front of mirror: negative
  • Distances behind mirror: positive
  • Heights above principal axis: positive
  • Heights below principal axis: negative

Magnification

m = -v/u = h₁/h₀

Where m = magnification, h₁ = image height, h₀ = object height

m valueInterpretation
m > 0Image is virtual and erect
m < 0Image is real and inverted
m
m
m
<ICSEExample title="Concave Mirror Problem"> An object is placed 30 cm in front of a concave mirror with focal length 15 cm. Find the position and nature of the image. <Solution> u = -30 cm, f = -15 cm (concave mirror, sign convention) 1/u + 1/v = 1/f 1/(-30) + 1/v = 1/(-15) 1/v = -1/15 + 1/30 = -1/30 v = -30 cm

Image is at 30 cm in front of mirror. m = -v/u = -(-30)/(-30) = -1 Image is real, inverted, and same size as object. </Solution> </ICSEExample>

Uses of Spherical Mirrors

Mirror TypeUses
ConcaveShaving mirrors, headlights, dental mirrors, solar furnaces, telescopes
ConvexRear-view mirrors in vehicles, security mirrors in shops

Common Mistakes With Fixes

MistakeCorrection
Confusing concave and convexConcave: caves in (converging), Convex: bulges out (diverging)
Wrong sign conventionAll distances from pole; in front = negative, behind = positive
f = R/2 formula signf = R/2 for concave; f = -R/2 for convex
Virtual images can be seenVirtual images cannot be projected on a screen

ICSE Exam Focus

TopicMarks (approx.)Frequency
Ray diagrams for spherical mirrors4-5 marksVery common
Mirror formula numericals4-5 marksVery common
Plane mirror properties2-3 marksCommon
Uses of mirrors2-3 marksFrequently asked

Self-Test

Q1: State the two laws of reflection.

Q2: An object is placed 20 cm from a concave mirror of focal length 10 cm. Find the image position and magnification.

Q3: Why is a convex mirror used as a rear-view mirror in vehicles?

Q4: Define focal length and radius of curvature. What is the relationship between them?

Q5: An object 5 cm tall is placed 15 cm from a convex mirror of focal length 20 cm. Find the height of the image.

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