Probability

1. Basic Terms

TermDefinitionExample
ExperimentAn action with UNCERTAIN outcomesTossing a coin
OutcomeA POSSIBLE result of an experimentHeads or Tails
EventA set of OUTCOMES we are interested inGetting Heads
Sample Space (S)ALL possible outcomes{H, T}
TrialONE performance of the experimentOne coin toss

'Probability measures HOW LIKELY an event is to occur. It ranges from 0 (impossible) to 1 (certain).'


2. Theoretical Probability

P(Event) = Number of FAVOURABLE outcomes / Total number of POSSIBLE outcomes

P(E) = n(E) / n(S)

Formula: P(E) = Favourable outcomes / Total outcomes

Properties:

  • 0 ≤ P(E) ≤ 1 (probability is always between 0 and 1)
  • P(E) + P(not E) = 1
  • If P(E) = 0, the event is IMPOSSIBLE
  • If P(E) = 1, the event is CERTAIN

3. Experimental (Empirical) Probability

Based on ACTUAL experiments and observations.

P(E) = Number of times event OCCURRED / Total number of TRIALS

Law of Large Numbers: As the number of trials INCREASES, experimental probability APPROACHES theoretical probability.


4. Coin Problems

A coin has TWO outcomes: {Head, Tail}

EventProbability
Getting Heads1/2
Getting Tails1/2
Getting Heads or Tails1 (CERTAIN)
Getting NEITHER Heads nor Tails0 (IMPOSSIBLE)

Worked Example: Two coins are tossed simultaneously. Find the probability of: (a) Two Heads (b) Exactly one Head (c) At least one Head

Sample Space S = {HH, HT, TH, TT}, n(S) = 4

(a) P(Two Heads) = {HH} = 1/4 (b) P(Exactly one Head) = {HT, TH} = 2/4 = 1/2 (c) P(At least one Head) = {HH, HT, TH} = 3/4


5. Dice Problems

A die has SIX outcomes: {1, 2, 3, 4, 5, 6}

EventProbability
Getting an EVEN number3/6 = 1/2
Getting an ODD number3/6 = 1/2
Getting a number > 42/6 = 1/3
Getting a PRIME number3/6 = 1/2 (2, 3, 5 are prime)
Getting a number 11/6
Getting a COMPOSITE number2/6 = 1/3 (4, 6 are composite)

Worked Example: Two dice are thrown simultaneously. Find the probability of: (a) Sum = 7 (b) Sum > 9 (c) Doublet (same number on both)

n(S) = 6 × 6 = 36

(a) Sum = 7: {(1,6), (2,5), (3,4), (4,3), (5,2), (6,1)} = 6 outcomes P(Sum = 7) = 6/36 = 1/6

(b) Sum > 9: {(4,6), (5,5), (5,6), (6,4), (6,5), (6,6)} = 6 outcomes P(Sum > 9) = 6/36 = 1/6

(c) Doublets: {(1,1), (2,2), (3,3), (4,4), (5,5), (6,6)} = 6 outcomes P(Doublet) = 6/36 = 1/6


6. Card Problems

A standard deck has 52 cards: 4 SUITS (Spades ♠, Hearts ♥, Diamonds ♦, Clubs ♣).

Each suit has 13 cards: A, 2, 3, 4, 5, 6, 7, 8, 9, 10, J, Q, K.

EventNumber of FavourableProbability
Drawing a Heart1313/52 = 1/4
Drawing a King44/52 = 1/13
Drawing a RED card2626/52 = 1/2
Drawing a FACE card (J, Q, K)1212/52 = 3/13
Drawing an ACE44/52 = 1/13
Drawing a BLACK QUEEN22/52 = 1/26

Worked Example: A card is drawn from a well-shuffled deck. Find the probability of: (a) Getting a Spade (b) Not getting a Spade

(a) P(Spade) = 13/52 = 1/4 (b) P(Not Spade) = 1 — 1/4 = 3/4


7. Probability of 'Not' an Event

P(not E) = 1 — P(E)

Worked Example: If the probability of rain tomorrow is 0.35, what is the probability of NO rain?

P(No rain) = 1 — 0.35 = 0.65


Common Mistakes and Fixes

MistakeFix
'Probability can be greater than 1'Probability is ALWAYS between 0 and 1 (inclusive)
'Heads is more likely than Tails'Both are EQUALLY likely — P(H) = P(T) = 1/2
'If I got 3 Heads in a row, Tails is more likely next'Each toss is INDEPENDENT. P(Tails) is STILL 1/2. The coin has no memory
'P(Even on a die) = number of evens / number of odds = 3/3 = 1'Use TOTAL outcomes: P(Even) = 3/6 = 1/2

ICSE Exam Focus (4–6 marks)

  • 2-mark questions: Probability of simple events (coin, die)
  • 3-mark questions: One coin/die/card problem
  • 4-mark questions: Two dice or two coins problems
  • 6-mark questions: Card problems or combined events

Self-Test

Q1. A coin is tossed once. Find the probability of getting Heads. A1. P(Heads) = 1/2.

Q2. A die is thrown once. Find the probability of getting a number greater than 4. A2. Favourable: {5, 6}. P = 2/6 = 1/3.

Q3. Two coins are tossed. Find the probability of getting exactly one Tail. A3. Favourable: {HT, TH}. P = 2/4 = 1/2.

Q4. A card is drawn from a standard deck. Find the probability of drawing a Queen. A4. There are 4 Queens. P = 4/52 = 1/13.

Q5. A bag contains 4 red, 3 blue, and 5 green marbles. One marble is drawn at random. Find the probability it is blue. A5. Total = 4 + 3 + 5 = 12. Blue = 3. P(Blue) = 3/12 = 1/4.

Q6. The probability of winning a game is 0.25. Find the probability of losing. A6. P(Losing) = 1 — P(Winning) = 1 — 0.25 = 0.75.

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