Operations on Numbers

1. Addition — Combining Numbers

Addition of Large Numbers

Align digits by place value. Add column by column from the RIGHT. Carry when sum exceeds 9.

   2 3 4 5 6 7 8
 + 1 9 8 7 6 5 4
 ----------------
   4 3 3 3 3 3 2

'Start from the ones place. If the sum is 10 or more, CARRY the extra digit to the next column on the LEFT.'

Properties of Addition

PropertyExplanationExample
CommutativeChanging order does NOT change sum25 + 30 = 30 + 25
AssociativeChanging grouping does NOT change sum(5 + 9) + 6 = 5 + (9 + 6)
IdentityZero added to a number gives the same number437 + 0 = 437
Property of 10Adding 10 increases the tens digit by 1456 + 10 = 466

Estimation in Addition

Round each number to the nearest thousand, then add.

4,279 + 3,612 ≈ 4,000 + 4,000 = 8,000 (Actual sum = 7,891 — close!)

2. Subtraction — Finding the Difference

Subtraction of Large Numbers

Align digits by place value. Subtract column by column from the RIGHT. Borrow when needed.

   7 8 9 3 4 5
 − 4 5 6 7 8 9
 -------------
   3 3 2 5 5 6

'When you borrow from the next column, that column's digit decreases by ONE, and the current column gets TEN added to it.'

Properties of Subtraction

PropertyExplanationExample
NOT commutative7 − 5 ≠ 5 − 7Order matters!
Subtracting zeroAny number minus zero = itself834 − 0 = 834
Subtracting itselfAny number minus itself = zero834 − 834 = 0
Relation to additionDifference + subtrahend = minuend345 − 123 = 222, so 222 + 123 = 345

Checking Subtraction Using Addition

'Always check your subtraction by ADDING the answer to the number you subtracted. You should get the original number back.'

3. Multiplication — Repeated Addition

Multiplication of Large Numbers

2-digit × 2-digit:

     4 5
   × 3 6
   -----
   2 7 0  (45 × 6)
 1 3 5 0  (45 × 30)
 --------
 1 6 2 0

'Multiply by the ones digit first. Then multiply by the tens digit — remember to PLACE A ZERO in the ones column. Add the partial products.'

Properties of Multiplication

PropertyExplanationExample
Commutative5 × 7 = 7 × 5Order does not matter
Associative(2 × 3) × 4 = 2 × (3 × 4)Grouping does not matter
IdentityMultiplying by 1 gives the same number89 × 1 = 89
Zero propertyMultiplying by 0 gives 056 × 0 = 0
Distributivea × (b + c) = a × b + a × c4 × (10 + 2) = 4 × 10 + 4 × 2 = 48

Multiplying by 10, 100, 1000

Multiply ByHow ToExample
10Add ONE zero45 × 10 = 450
100Add TWO zeros45 × 100 = 4,500
1000Add THREE zeros45 × 1000 = 45,000

'To multiply by 10, 100, or 1000 — just COUNT the zeros and add them to the end of the number.'

4. Division — Sharing Equally

Terms of Division

Dividend ÷ Divisor = Quotient + Remainder

'Check: Dividend = Divisor × Quotient + Remainder. The remainder must ALWAYS be less than the divisor.'

Long Division

       3 4 2 R 1
     ───────────
 5 ) 1 7 1 1
    − 1 5  ↓
      ────
        2 1
      − 2 0
        ───
          1 1
        − 1 0
          ───
            1

'Bring down digits ONE at a time. Divide, multiply, subtract, bring down — repeat until no digits remain.'

Properties of Division

PropertyExplanationExample
NOT commutative10 ÷ 2 ≠ 2 ÷ 10Order matters
Dividing by 1Any number ÷ 1 = itself56 ÷ 1 = 56
Dividing by itselfAny number ÷ itself = 1 (except 0)25 ÷ 25 = 1
Dividing zero0 ÷ any number = 00 ÷ 7 = 0
Cannot divide by zeroDivision by zero is UNDEFINED8 ÷ 0 has no meaning

5. BODMAS — Order of Operations

When an expression has MULTIPLE operations, follow this order:

LetterStands ForExample
BBrackets (solve inside FIRST)(4 + 3) × 2 = 7 × 2 = 14
OOf (multiplication with 'of')Half of 20 = 10
DDivision (left to right)12 ÷ 3 × 2 = 4 × 2 = 8
MMultiplication (left to right)4 × 3 + 5 = 12 + 5 = 17
AAddition (left to right)10 + 5 − 3 = 12
SSubtraction (left to right)15 − 4 + 2 = 13

'BRACKETS FIRST — ALWAYS. If there are nested brackets, solve the INNERMOST bracket first.'

Example: 15 − [2 + (6 − 4) × 3]

Step 1: Solve innermost bracket (6 − 4) = 2 Step 2: Multiply 2 × 3 = 6 Step 3: Add 2 + 6 = 8 Step 4: Subtract 15 − 8 = 7

6. Word Problems — Step by Step

Strategy

StepAction
1Read the problem CAREFULLY — twice
2Identify what is GIVEN and what is ASKED
3Decide which OPERATION to use
4ESTIMATE the answer first
5SOLVE accurately
6CHECK if the answer makes sense

Example Problem

A school has 2,456 students. Each student needs 5 notebooks. How many notebooks are needed?

  • Given: 2,456 students. 5 notebooks each.
  • Operation: Multiplication.
  • Estimate: 2,500 × 5 = 12,500
  • Solve: 2,456 × 5 = 12,280 notebooks.
  • Check: 12,280 ÷ 2,456 = 5. Correct.

Key Facts to Remember

  • 'Addition and subtraction are INVERSE operations. Multiplication and division are INVERSE operations.'
  • The product of any number and ZERO is ZERO.
  • The quotient of any number divided by ONE is the number itself.
  • Always ESTIMATE before solving — it helps you catch big mistakes.
  • In BODMAS, division and multiplication have EQUAL priority (left to right).

Common Mistakes

MistakeWhy It Is WrongCorrect Approach
Subtracting a larger digit from a smaller without borrowing423 − 156: in tens column, 2 − 5 — you MUST borrowBorrow 1 hundred: 12 tens − 5 tens = 7 tens
Forgetting the zero in partial products45 × 36: while multiplying by 30, write 1350 NOT 135The zero represents the ones place of 30
BODMAS — adding before dividing12 ÷ 3 × 2 + 1 = ? Many solve 3 × 2 firstDivision and multiplication have equal priority — go LEFT to RIGHT
Remainder larger than divisor17 ÷ 5 = 3 R 2 (not 2 R 7)Remainder must ALWAYS be smaller than divisor

Exam Focus (ICSE Class 5)

TopicMarks (Typical)Question Type
Addition/Subtraction of large numbers4-5 marksDirect computation
Multiplication and division4-5 marksWord problems and computation
BODMAS3-4 marksSimplify expressions
Word problems (multi-step)4-5 marksApplication-based
Properties of operations2-3 marksFill in the blanks / True-False

Self-Test: 5 Questions

Q1. Simplify using BODMAS: 24 − [12 + (8 − 3) × 2] ÷ 6

Q2. A factory produces 1,245 toys per day. How many toys does it produce in 3 months (90 days)?

Q3. Find the product: 4,567 × 208

Q4. Divide and check: 8,945 ÷ 27

Q5. Riya has 500. She buys 3 books at 85 each and 2 pens at 12 each. How much money is left with her?

Answers

A1. 24 − [12 + (8 − 3) × 2] ÷ 6 = 24 − [12 + 5 × 2] ÷ 6 = 24 − [12 + 10] ÷ 6 = 24 − 22 ÷ 6 = 24 − 3.67 = 20.33

A2. 1,245 × 90 = 1,12,050 toys.

A3. 4,567 × 208 = 9,49,936.

A4. 8,945 ÷ 27 = 331 R 8. Check: 331 × 27 + 8 = 8,937 + 8 = 8,945.

A5. Spent = 3 × 85 + 2 × 12 = 255 + 24 = 279. Left = 500 − 279 = 221.

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