By the end of this chapter you'll be able to…

  • 1Define SHM and write its displacement, velocity, and acceleration equations
  • 2Analyse energy interconversion in SHM
  • 3Derive the time period of spring-mass and pendulum systems
  • 4Combine springs in series and parallel
  • 5Explain damped and forced oscillations and resonance
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Why this chapter matters
Oscillations are everywhere -- from a guitar string to a swaying building. Simple harmonic motion is the foundational model for small vibrations in any system, and resonance is critical both for technology (radio tuning, MRI) and for avoiding disasters (bridge collapse).

Before you start — revise these

A 5-minute refresher here will save you 30 minutes of confusion below.

Oscillations

'There is geometry in the humming of the strings... there is music in the spacing of the spheres.' — Pythagoras

1. Chapter Overview

OSCILLATORY motion is REPETITIVE motion back and forth about a MEAN position. This chapter focuses on SIMPLE HARMONIC MOTION (SHM) — the simplest form of oscillation — and its applications in SPRING-MASS systems and the SIMPLE PENDULUM. You will also study DAMPED oscillations, FORCED oscillations, and the IMPORTANT phenomenon of RESONANCE.


2. Periodic and Oscillatory Motion

  • Periodic Motion: Motion that REPEATS itself at regular intervals
  • Oscillatory Motion: To-and-fro motion about a MEAN position
  • Period (T): Time for ONE complete oscillation
  • Frequency (f): Number of oscillations per second (f = 1/T)
  • SI unit: hertz (Hz), 1 Hz = 1 s⁻¹

Amplitude and Phase

  • Amplitude (A): Maximum displacement from mean position
  • Phase (φ): Describes the STATE of the oscillator (position + direction)
  • Phase Constant (φ₀): Initial phase at t = 0

3. Simple Harmonic Motion (SHM)

Definition

A particle is in SHM if its acceleration is DIRECTLY proportional to its displacement from the mean position and ALWAYS directed TOWARD the mean position.

  • a = -ω²x (where ω = angular frequency)

Equation of SHM

  • x(t) = Acos(ωt + φ₀) or x(t) = Asin(ωt + φ₀)
  • ω = 2π/T = 2πf

Velocity and Acceleration in SHM

  • v = dx/dt = -Aω sin(ωt + φ₀)
  • a = d²x/dt² = -Aω² cos(ωt + φ₀) = -ω²x

Important Relations

  • |v_max| = Aω (at mean position, x = 0)
  • |a_max| = Aω² (at extreme positions, x = ±A)
  • v = ω√(A² — x²) (velocity in terms of displacement)

Worked Problem

Q: A particle in SHM has amplitude 5 cm and time period 2 s. Find maximum velocity and acceleration. A: ω = 2π/T = π rad/s. v_max = Aω = 0.05π = 0.157 m/s. a_max = Aω² = 0.05×π² = 0.493 m/s².


4. Energy in SHM

Kinetic Energy

  • K = ½mω²(A² — x²)
  • K_max = ½mω²A² (at x = 0)

Potential Energy (Spring-type force)

  • U = ½mω²x²
  • U_max = ½mω²A² (at x = ±A)

Total Energy

  • E = K + U = ½mω²A² = CONSTANT
  • Energy interconversion: KE ↔ PE, but total remains CONSTANT

Worked Problem

Q: A 0.2 kg mass oscillates with A = 10 cm and T = 0.5 s. Find total energy. A: ω = 2π/0.5 = 4π rad/s. E = ½mω²A² = ½×0.2×(4π)²×(0.1)² = 0.1×16π²×0.01 = 0.016π² = 0.158 J.


5. Spring-Mass System

Horizontal Spring

  • Restoring force: F = -kx (Hooke's law)
  • Angular frequency: ω = √(k/m)
  • Time period: T = 2π√(m/k)

Vertical Spring

  • Same ω = √(k/m)
  • The Mean position shifts due to gravity (extension x₀ = mg/k)

Series and Parallel Combinations

CombinationEffective Spring Constant
Series (same force, different extensions)1/k_eff = 1/k₁ + 1/k₂
Parallel (same extension, different forces)k_eff = k₁ + k₂

6. Simple Pendulum

  • Restoring torque: τ = -mgLθ (for small θ)
  • Angular frequency: ω = √(g/L)
  • Time period: T = 2π√(L/g)

Key Points

  • Period is INDEPENDENT of MASS (Galileo's discovery)
  • Period is INDEPENDENT of AMPLITUDE (for small angles, θ < 10°)
  • T ∝ √L: longer pendulum → longer period
  • T ∝ 1/√g: weaker gravity → longer period

Worked Problem

Q: A simple pendulum has length 1 m. Find its period at Earth's surface (g = 9.8 m/s²). A: T = 2π√(L/g) = 2π√(1/9.8) = 2π×0.319 = 2.006 s.


7. Damped and Forced Oscillations

Damped Oscillations

  • Real oscillations have FRICTION or DRAG → amplitude DECREASES with time
  • x(t) = Ae^(-bt/2m)cos(ω't + φ₀) (exponentially decaying amplitude)
  • b = damping constant
  • Underdamped (b² < 4mk): Oscillations with decreasing amplitude
  • Critically damped (b² = 4mk): Fastest return to equilibrium (NO oscillation)
  • Overdamped (b² > 4mk): Slow return without oscillation

Forced Oscillations and Resonance

  • Periodic DRIVING force applied to an oscillator
  • Amplitude is MAXIMUM when driving frequency = NATURAL frequency of the system
  • This is RESONANCE

Examples of Resonance

  • Mechanical: Soldier breaking step while crossing a bridge
  • Sound: Opera singer shattering a glass
  • Electrical: Tuning a radio to a specific station (LC circuit)
  • Tacoma Narrows Bridge: Wind-induced resonance caused collapse (1940)

8. Common Mistakes

  1. SHM acceleration is NOT constant: a = -ω²x, which depends on x. It is maximum at extremes, zero at mean
  2. Pendulum T is independent of mass: Many students think heavier pendulums swing slower
  3. T = 2π√(m/k) for spring, T = 2π√(L/g) for pendulum: Don't confuse the formulas
  4. v_max = Aω, not ω²: Acceleration maximum has ω², velocity maximum has ω
  5. Resonance amplitude is NOT infinite: In real systems, damping limits the maximum amplitude

9. CBSE Exam Focus

  1. SHM definition — acceleration proportional to -displacement (1-mark)
  2. Derivation of velocity and acceleration in SHM (3-mark)
  3. Energy in SHM — KE, PE, total energy (5-mark)
  4. Spring-mass system — time period derivation (3-mark)
  5. Simple pendulum — time period (3/5-mark)
  6. Graphs of x, v, a versus time in SHM
  7. Resonance — definition and examples (1/3-mark)

10. Key Formulas

  • x = Acos(ωt + φ₀)
  • v = -Aω sin(ωt + φ₀), v = ω√(A² — x²)
  • a = -Aω² cos(ωt + φ₀) = -ω²x
  • K = ½mω²(A² — x²), U = ½mω²x²
  • E = ½mω²A² (constant)
  • T_spring = 2π√(m/k)
  • T_pendulum = 2π√(L/g)

11. Self-Test (5+ Q&A)

Q1: A particle in SHM has amplitude 10 cm and frequency 2 Hz. Write the equation of motion assuming it starts from the mean position moving positively. A: ω = 2πf = 4π rad/s. At t = 0, x = 0 moving positive → use x = Asin(ωt). x = 0.1sin(4πt) m.

Q2: At what displacement is the kinetic energy equal to potential energy in SHM? A: K = U → ½mω²(A² — x²) = ½mω²x² → A² — x² = x² → 2x² = A² → x = ±A/√2.

Q3: A spring of constant k = 100 N/m has a 4 kg mass attached. Find period. A: T = 2π√(m/k) = 2π√(4/100) = 2π×0.2 = 1.257 s.

Q4: A pendulum clock runs slow. Should the pendulum length be increased or decreased? A: T = 2π√(L/g). If the clock runs slow, T is too large. Decrease L to decrease T.

Q5: What is the difference between damped and forced oscillations? A: Damped oscillations have amplitude decreasing due to energy loss (friction). Forced oscillations are driven by an external periodic force, and their amplitude depends on the driving frequency.


12. Conclusion

Oscillations are EVERYWHERE — from the vibrating string of a guitar to the swaying of a building in an earthquake. SHM is the FOUNDATIONAL model because its mathematics (sine/cosine functions) describes small oscillations around equilibrium in ALL physical systems. The spring-mass system and pendulum are the CLASSIC examples. Understanding resonance is CRITICAL for both avoiding disasters (bridge collapse) and enabling technology (radio tuning, MRI).

Key formulas & results

Everything you need to memorise, in one card. Screenshot this for revision.

SHM equations
x = A cos(omega t + phi); a = -omega^2 x; v = omega sqrt(A^2 - x^2)
Acceleration is proportional to and opposite the displacement.
Maxima
v_max = A omega; a_max = A omega^2
v_max at the mean position, a_max at the extremes.
Energy in SHM
E = (1/2) m omega^2 A^2 = K + U (constant)
K = (1/2)m omega^2 (A^2 - x^2); U = (1/2)m omega^2 x^2.
Time periods
T_spring = 2 pi sqrt(m/k); T_pendulum = 2 pi sqrt(L/g)
Pendulum period is independent of mass and amplitude (small angles).
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Common mistakes & fixes

These are the exact errors that cost students marks in board exams. Read them once, save yourself the trouble.

WATCH OUT
Thinking SHM acceleration is constant
a = -omega^2 x varies with position: maximum at the extremes and zero at the mean position.
WATCH OUT
Believing a heavier pendulum bob swings slower
The pendulum period T = 2 pi sqrt(L/g) is independent of the bob's mass.
WATCH OUT
Confusing the spring and pendulum period formulae
Use T = 2 pi sqrt(m/k) for a spring and T = 2 pi sqrt(L/g) for a pendulum.
WATCH OUT
Assuming resonance gives infinite amplitude
Real systems have damping, which limits the maximum amplitude at resonance.

Practice problems

Try each one yourself before tapping "Show solution". Active recall > rereading.

Q1MEDIUM· SHM
A particle in SHM has amplitude 5 cm and period 2 s. Find the maximum velocity and acceleration.
Show solution
omega = 2 pi/T = pi rad/s. v_max = A omega = 0.05 pi = 0.157 m/s. a_max = A omega^2 = 0.05 pi^2 = 0.493 m/s^2.
Q2MEDIUM· Energy
At what displacement is the kinetic energy equal to the potential energy in SHM?
Show solution
K = U gives (A^2 - x^2) = x^2, so 2x^2 = A^2 and x = +/- A/sqrt(2).
Q3MEDIUM· Spring
A spring of constant 100 N/m carries a 4 kg mass. Find the period.
Show solution
T = 2 pi sqrt(m/k) = 2 pi sqrt(4/100) = 2 pi x 0.2 = 1.257 s.
Q4EASY· Pendulum
A pendulum clock runs slow. Should the pendulum be lengthened or shortened?
Show solution
Running slow means the period is too long. Since T = 2 pi sqrt(L/g), shorten the pendulum to reduce the period.
Q5EASY· Concept
What is the difference between damped and forced oscillations?
Show solution
In damped oscillations the amplitude decreases over time due to energy loss (friction/drag). In forced oscillations an external periodic force drives the system, and the amplitude depends on the driving frequency, peaking at resonance.

5-minute revision

The whole chapter, distilled. Read this the night before the exam.

  • SHM: a = -omega^2 x, directed toward the mean position.
  • x = A cos(omega t + phi); v_max = A omega; a_max = A omega^2.
  • Energy E = (1/2)m omega^2 A^2 is constant; KE and PE interconvert.
  • Spring: T = 2 pi sqrt(m/k); series 1/k = 1/k1 + 1/k2; parallel k = k1 + k2.
  • Pendulum: T = 2 pi sqrt(L/g), independent of mass and (small) amplitude.
  • Damped oscillations decay exponentially; types: under-, critically, over-damped.
  • Resonance: amplitude peaks when driving frequency equals natural frequency.

CBSE marks blueprint

Where the marks come from in this chapter — so you can plan your prep.

Typical chapter weightage: 6-8 marks across the chapter

Question typeMarks eachTypical countWhat it tests
Energy in SHM3-51KE, PE, total energy and graphs
Spring / pendulum period31Time-period derivations and numericals
SHM kinematics / resonance2-31Equations of SHM and resonance
Prep strategy
  • Master x, v, a equations and their phase relationships
  • Practise energy-in-SHM problems
  • Memorise spring and pendulum period formulae
  • Learn resonance examples and its dangers/uses

Where this shows up in the real world

This chapter isn't just an exam topic — it lives in the world around you.

Clocks and timekeeping

Pendulums and quartz oscillators keep accurate time using their fixed period.

Music

Vibrating strings and air columns produce musical notes through harmonic oscillations.

Earthquake engineering

Understanding resonance helps design buildings that avoid catastrophic oscillation during quakes.

Exam strategy

Battle-tested tips from teachers and toppers for this chapter.

  1. State the SHM condition a = -omega^2 x clearly
  2. Use energy conservation to relate KE, PE, and total energy
  3. Pick the correct period formula for spring vs pendulum
  4. Explain resonance with a concrete example

Going beyond the textbook

For olympiad aspirants and curious learners — topics that build on this chapter.

  • Derive the period of physical pendulums and torsional oscillators.
  • Analyse the quality factor (Q) and the resonance curve of a damped driven oscillator.

Where else this chapter is tested

CBSE board isn't the only one — other exams test this chapter too.

CBSE Class 11 Physics examHigh
JEE Main and Advanced (Oscillations)High
NEET PhysicsMedium

Questions students ask

The real ones — pulled from the Q&A community and tutor sessions.

The restoring force on a pendulum bob is the component of gravity, mg sin(theta), which is proportional to the mass. The acceleration is this force divided by the mass, so the mass cancels out. The resulting period T = 2 pi sqrt(L/g) depends only on the length and gravity, not on the bob's mass -- the same reason all objects fall with the same acceleration.

Resonance occurs when a periodic driving force matches a system's natural frequency, causing the amplitude of oscillation to grow very large. It is useful in radios (tuning) and musical instruments, but dangerous in structures: marching soldiers, wind, or earthquakes can drive a bridge or building at its natural frequency and build up destructive oscillations, as in the 1940 Tacoma Narrows Bridge collapse.
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Last reviewed on 29 May 2026. Written and reviewed by subject-matter experts — read about our process.
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