Reflection of Light — Class 10 Physical Science
"Light travels in straight lines. When it hits a surface, it BOUNCES. This simple fact — reflection — is why you can see yourself in a mirror, why car headlights work, and why dentists can see the back of your teeth."
1. Laws of Reflection
- Angle of incidence (i) = Angle of reflection (r). Measured from the NORMAL (perpendicular to the surface).
- The INCIDENT ray, REFLECTED ray, and NORMAL all lie in the SAME PLANE.
2. Plane Mirror
Image characteristics: VIRTUAL (cannot be caught on a screen). ERECT (upright). Same SIZE as the object. LATERALLY INVERTED (left ↔ right swapped). As far BEHIND the mirror as the object is in FRONT. 'Your reflection raises its LEFT hand when you raise your RIGHT. Ambulances have "ECNALUBMA" written on the front — so drivers see "AMBULANCE" in their rear-view mirror!'
3. Spherical Mirrors
| Concave Mirror | Convex Mirror | |
|---|---|---|
| Shape | Curved INWARD (like a bowl) | Curved OUTWARD (bulging) |
| Effect on parallel rays | CONVERGES to a point (FOCUS) | DIVERGES (appears to come from focus BEHIND mirror) |
| Uses | Torches, shaving mirrors, dentist mirrors, solar furnaces | Rear-view mirrors (cars, bikes). Shop security mirrors. |
| Image types | REAL or VIRTUAL. Magnified or diminished. | ALWAYS virtual, diminished, erect. |
Key Definitions
Pole (P) : Centre of the mirror's surface. Centre of Curvature (C) : Centre of the sphere. Radius of Curvature (R) : Distance PC. Focus (F) : Midpoint of PC. Focal Length (f) = R/2.
Ray Diagrams — Rules for Drawing
- Ray PARALLEL to principal axis → after reflection, passes through FOCUS (concave) or APPEARS to come from focus (convex).
- Ray passing through FOCUS → after reflection, becomes parallel to principal axis.
- Ray passing through CENTRE OF CURVATURE → retraces its path (strikes mirror normally).
- Ray incident at the POLE → reflected at EQUAL angle.
Mirror Formula: 1/f = 1/u + 1/v
f = focal length (negative for concave, positive for convex). u = object distance (ALWAYS negative — object is in front of mirror). v = image distance (positive for real images, negative for virtual).
Magnification: m = −v/u = h'/h (h' = image height, h = object height).
m > 0 → ERECT (virtual). m < 0 → INVERTED (real). |m| > 1 → MAGNIFIED. |m| < 1 → DIMINISHED.
Sign Convention (Cartesian)
All distances measured from POLE. Distances in direction of incident light → NEGATIVE (u is always negative). Opposite direction → POSITIVE. Heights above principal axis → POSITIVE. Below → NEGATIVE.
4. Concave Mirror — Image Cases
| Object Position | Image Position | Size | Nature |
|---|---|---|---|
| At infinity | At F | Highly diminished | REAL, inverted |
| Beyond C | Between F and C | Diminished | REAL, inverted |
| At C | At C | Same size | REAL, inverted |
| Between C and F | Beyond C | Magnified | REAL, inverted |
| At F | At infinity | Highly magnified | REAL, inverted |
| Between P and F | BEHIND mirror | Magnified | VIRTUAL, erect |
'Only the LAST case (object between P and F) produces a VIRTUAL, MAGNIFIED image — this is why concave mirrors are used as shaving mirrors and dentist mirrors.'
5. Convex Mirror — Always the Same
Image is ALWAYS: Virtual. Erect. Diminished. Behind the mirror (between P and F). 'Convex mirrors give a WIDER field of view — but images are SMALLER. This is why they're used as rear-view mirrors: "Objects in the mirror are closer than they appear."'
6. Common Mistakes
- Sign convention errors: 'u is ALWAYS negative. f is negative for concave, positive for convex. v is negative for virtual images.'
- 'Centre of curvature = focus' — C is at distance R from pole. F is at R/2.
- Drawing the wrong ray: 'A ray through FOCUS becomes parallel. A ray through CENTRE bounces back. These are DIFFERENT.'
7. AP SSC Exam Focus
| Topic | Marks |
|---|---|
| Mirror formula problems | 3-4 |
| Ray diagrams (concave) | 4-5 |
| Image characteristics | 3-4 |
| Uses of mirrors | 2-3 |
8. Worked Numerical Problems — Mirror Formula and Magnification
Example 1: An object is placed 15 cm in front of a concave mirror of focal length 10 cm. Find the image position and nature. Solution: u = −15 cm, f = −10 cm (concave → f negative). 1/f = 1/u + 1/v → 1/v = 1/f − 1/u = 1/(−10) − 1/(−15) = −1/10 + 1/15 = (−3+2)/30 = −1/30. v = −30 cm. m = −v/u = −(−30)/(−15) = −2. 'v is NEGATIVE — image is REAL (in front of mirror). m = −2 — image is INVERTED and MAGNIFIED (2×).'
Example 2: An object is placed 20 cm in front of a concave mirror of focal length 15 cm. Find the image position, nature, and magnification. Solution: u = −20 cm, f = −15 cm. 1/v = 1/f − 1/u = 1/(−15) − 1/(−20) = −1/15 + 1/20 = (−4+3)/60 = −1/60. v = −60 cm. m = −v/u = −(−60)/(−20) = −3. 'Image is REAL, INVERTED, MAGNIFIED (3×), at 60 cm in front of mirror. Object is between C and F.'
Example 3: A convex mirror has focal length 20 cm. An object is placed 30 cm in front. Find the image position and magnification. Solution: u = −30 cm, f = +20 cm (convex → f positive). 1/v = 1/f − 1/u = 1/20 − 1/(−30) = 1/20 + 1/30 = (3+2)/60 = 5/60 = 1/12. v = +12 cm. m = −v/u = −12/(−30) = +0.4. 'v is POSITIVE — image is VIRTUAL (behind mirror). m = +0.4 — image is ERECT and DIMINISHED. Exactly what a convex mirror always produces.'
Example 4: A concave mirror forms a real, inverted image of the same size as the object. Where is the object placed? Solution: For SAME SIZE, real, inverted image → object must be at CENTRE OF CURVATURE (C). u = R = 2f. 'Object at C: image at C. Same size. Real. Inverted.'
9. Uses of Mirrors — Detailed
Concave Mirror Uses:
- Shaving mirror / Make-up mirror: Object placed BETWEEN P and F → VIRTUAL, ERECT, MAGNIFIED image. You see an enlarged view of your face.
- Dentist's mirror: Concave mirror on a handle — gives MAGNIFIED view of teeth.
- Torch / Headlight: Bulb placed at FOCUS → reflected rays become PARALLEL → narrow, powerful beam.
- Solar Furnace: Large concave reflector CONCENTRATES sunlight at the FOCUS → very HIGH TEMPERATURE (used to heat water, cook food, or generate steam).
- Reflecting Telescopes: Concave mirror as the PRIMARY MIRROR to collect light from distant stars.
Convex Mirror Uses:
- Rear-view mirror in vehicles: Gives a WIDER field of view — driver can see more of the traffic behind. Images are VIRTUAL, ERECT, and DIMINISHED — so "objects in mirror are closer than they appear."
- Security mirrors in shops: Wide field of view — one mirror can monitor a large area.
10. Magnification — Special Cases
m > 1: Image is MAGNIFIED (larger than object). Example: shaving mirror (object between P and F). m = 1: Same size. Example: concave mirror with object at C. m < 1: DIMINISHED (smaller). Example: convex mirror (always). Concave mirror with object beyond C. m > 0: ERECT image (virtual). Example: convex mirror. Concave mirror with object between P and F. m < 0: INVERTED image (real). Example: concave mirror with object beyond F.
'When solving numerical problems: start by writing u = −(given distance). Decide f = −R/2 (concave) or +R/2 (convex). Then use the mirror formula. Check the sign of v to determine real/virtual. Calculate m to find magnification and orientation.'
11. Self-Test
Q1: A concave mirror has focal length 10 cm. Where should an object be placed to get a REAL, INVERTED, SAME-SIZE image? A1: At the CENTRE OF CURVATURE (C). R = 2f = 20 cm. Object distance u = 20 cm (in front of mirror).
Q2: Why do convex mirrors give a wider field of view? A2: Convex mirrors curve OUTWARD. They diverge incoming light rays. This allows them to COLLECT light from a WIDER angle and present a MINIATURE view of the entire scene. 'The curved surface acts like a wide-angle lens.'
Q3: A concave mirror produces a virtual image. Where is the object placed? A3: Between POLE (P) and FOCUS (F). Only this case gives a VIRTUAL, ERECT, MAGNIFIED image.
Q4: An object is placed 10 cm from a convex mirror of focal length 15 cm. Find the image distance. A4: u = −10 cm, f = +15 cm. 1/v = 1/f − 1/u = 1/15 − 1/(−10) = 1/15 + 1/10 = (2+3)/30 = 5/30 = 1/6. v = +6 cm. Image is 6 cm BEHIND the mirror.
Q5: Calculate the magnification when the image distance is −30 cm and object distance is −15 cm. Describe the image. A5: m = −v/u = −(−30)/(−15) = 30/(−15) = −2. m = −2 — Image is REAL, INVERTED, MAGNIFIED (2×).
Q6: A dentist uses a concave mirror of focal length 2 cm. At what distance should the tooth be placed from the mirror to get a magnified image? A6: To get a MAGNIFIED, VIRTUAL image: object must be BETWEEN P and F. So tooth should be placed LESS THAN 2 cm from the mirror (u < f).
Q7: The radius of curvature of a convex mirror used as a rear-view mirror is 3 m. A car is 5 m behind the mirror. Find the position of the image. A7: R = +3 m → f = +1.5 m. u = −5 m. 1/v = 1/f − 1/u = 1/1.5 − 1/(−5) = 1/1.5 + 1/5 = 0.667 + 0.2 = 0.867. v = +1.15 m. Image is 1.15 m BEHIND the mirror — VIRTUAL, ERECT, DIMINISHED.
