By the end of this chapter you'll be able to…

  • 1Apply the distributive property to algebraic expressions
  • 2Multiply binomials using FOIL method
  • 3Apply identities (a±b)² and a²−b²
  • 4Factorise expressions by various methods
  • 5Use identities for mental computation
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Why this chapter matters
Bridges arithmetic and algebra. Master distributive property, polynomial multiplication, algebraic identities, and factorisation — tools used in every later math chapter.

Before you start — revise these

A 5-minute refresher here will save you 30 minutes of confusion below.

We Distribute Yet Things Multiply — Class 8 Mathematics (Ganita Prakash)

"When we multiply two binomials, we are not just doing arithmetic — we are revealing the deep structure of all algebra."

1. About the Chapter

This chapter's playful title captures a paradox: when we DISTRIBUTE one expression across another, the answer still MULTIPLIES to something larger. We are doing two opposite-sounding things at once.

The chapter teaches:

  • Algebraic expressions and their parts
  • Distributive property in algebra
  • Multiplying polynomials (binomials and beyond)
  • Visual reasoning with area diagrams
  • Algebraic identities — (a+b)², (a−b)², a²−b²
  • Factorisation (the reverse of multiplication)

2. Algebraic Expressions — Quick Review

Terms

  • A term is a single number or variable, or a product like 3xy or −5x².
  • Variable: a letter (x, y, z) standing for a number.
  • Constant: a fixed number (like 5).
  • Coefficient: the number multiplied by a variable (in 7x, the coefficient is 7).

Types

  • Monomial: one term (e.g., 5x, −3y², 7)
  • Binomial: two terms (e.g., x + 5, 3a − 2b)
  • Trinomial: three terms (e.g., a² + 2a + 1)
  • Polynomial: general term for any algebraic expression with multiple terms

Degree

The degree of a polynomial is the highest power of any single variable.

  • 3x² + 5x − 7 has degree 2 (a quadratic)
  • x³ + 2x has degree 3 (a cubic)

3. The Distributive Property (Heart of the Chapter)

Statement

a × (b + c) = a × b + a × c

This says: to multiply a by (b + c), multiply a by each term separately and add.

Visual Proof (Rectangle Method)

Think of a rectangle of dimensions a × (b + c):

  • Total area = a × (b + c)
  • Same rectangle = a × b plus a × c (two smaller rectangles)
  • So a × (b + c) = a × b + a × c

Examples

  • 3 × (5 + 2) = 3 × 5 + 3 × 2 = 15 + 6 = 21 ✓
  • 4 × (x + 7) = 4x + 28
  • 2x × (3y + 5) = 6xy + 10x

Extending to Subtraction

a × (b − c) = a × b − a × c

Extending to More Terms

a × (b + c + d) = ab + ac + ad


4. Multiplying Two Binomials

The Distributive Property Applied Twice

(a + b) × (c + d) = a × (c + d) + b × (c + d) = ac + ad + bc + bd

FOIL Method

A mnemonic for binomial multiplication:

  • First terms: a × c
  • Outer terms: a × d
  • Inner terms: b × c
  • Last terms: b × d

Add them all.

Examples

Example 1: (x + 2)(x + 3)

  • F: x × x = x²
  • O: x × 3 = 3x
  • I: 2 × x = 2x
  • L: 2 × 3 = 6
  • Sum: x² + 5x + 6

Example 2: (2a + 5)(3a − 4)

  • F: 2a × 3a = 6a²
  • O: 2a × (−4) = −8a
  • I: 5 × 3a = 15a
  • L: 5 × (−4) = −20
  • Sum: 6a² + 7a − 20

Visual Proof: Area of Rectangle

A rectangle of (a+b) × (c+d) is divided into 4 sub-rectangles:

  • ac, ad, bc, bd The total area = sum of these four.

5. Famous Algebraic Identities (MASTER ALL)

These appear repeatedly in algebra. Memorise them.

Identity 1: (a + b)²

(a + b)² = a² + 2ab + b²

Three terms: a², 2ab, b².

Examples:

  • (x + 5)² = x² + 10x + 25
  • (2y + 3)² = 4y² + 12y + 9

Identity 2: (a − b)²

(a − b)² = a² − 2ab + b²

Same as identity 1, but middle term is negative.

Examples:

  • (x − 4)² = x² − 8x + 16
  • (3p − 2q)² = 9p² − 12pq + 4q²

Identity 3: a² − b² (Difference of Squares)

a² − b² = (a + b)(a − b)

Examples:

  • x² − 25 = (x + 5)(x − 5)
  • 16y² − 9 = (4y + 3)(4y − 3)

Identity 4: (a + b)(a − b) = a² − b²

Same as Identity 3, written differently.

Identity 5: (x + a)(x + b)

(x + a)(x + b) = x² + (a + b)x + ab

Useful for quadratic factorisation.


6. Worked Examples

Example 1: Distribute

Simplify: 3x × (2x − 5y + 4)

  • = 3x × 2x − 3x × 5y + 3x × 4
  • = 6x² − 15xy + 12x

Example 2: Multiply Binomials

Multiply: (3x − 7)(2x + 5)

  • F: 3x × 2x = 6x²
  • O: 3x × 5 = 15x
  • I: −7 × 2x = −14x
  • L: −7 × 5 = −35
  • Sum: 6x² + x − 35

Example 3: Apply (a+b)² Identity

Expand (4x + 7)².

  • (a + b)² = a² + 2ab + b², where a = 4x, b = 7
  • = (4x)² + 2(4x)(7) + 7²
  • = 16x² + 56x + 49

Example 4: Apply (a−b)² Identity

Expand (5p − 3q)².

  • = (5p)² − 2(5p)(3q) + (3q)²
  • = 25p² − 30pq + 9q²

Example 5: Apply Difference of Squares

Factorise: x² − 64

  • = x² − 8² = (x + 8)(x − 8)

Example 6: Apply x² + (a+b)x + ab

Factorise: x² + 7x + 12

  • We need two numbers whose product is 12 and sum is 7. Try 3 and 4: 3 × 4 = 12 ✓, 3 + 4 = 7 ✓
  • So x² + 7x + 12 = (x + 3)(x + 4)

Example 7: Compute Using Identity

Compute 102² using identity.

  • 102² = (100 + 2)² = 100² + 2(100)(2) + 2² = 10000 + 400 + 4 = 10404

Example 8: Compute Using Identity

Compute 998² using identity.

  • 998² = (1000 − 2)² = 1000² − 2(1000)(2) + 2² = 1000000 − 4000 + 4 = 996004

Example 9: Difference of Squares for Computation

Compute 105 × 95.

  • = (100 + 5)(100 − 5) = 100² − 5² = 10000 − 25 = 9975

7. Introduction to Factorisation

What is Factorisation?

Factorisation is the reverse of multiplication. We express a polynomial as a product of simpler polynomials.

Method 1: Common Factor

  • 6x + 9y = 3(2x + 3y) (3 is common)
  • 4xy + 2x = 2x(2y + 1) (2x common)

Method 2: Identity-based

  • a² + 2ab + b² = (a + b)²
  • a² − 2ab + b² = (a − b)²
  • a² − b² = (a + b)(a − b)

Method 3: Splitting the Middle Term (for x² + bx + c)

Find p, q such that p + q = b and p × q = c.

  • x² + 7x + 12 → p + q = 7, p × q = 12 → p = 3, q = 4
  • x² + 7x + 12 = (x + 3)(x + 4)

Method 4: Grouping

Sometimes terms can be grouped to find a common factor.

  • 2x² + 4x + 3x + 6 = 2x(x + 2) + 3(x + 2) = (x + 2)(2x + 3)

8. Common Mistakes

  1. Sign errors in (a − b)²

    • (a − b)² = a² − 2ab + b² (the middle term is NEGATIVE)
    • NOT a² − 2ab − b² (wrong sign on b²!)
    • NOT a² + 2ab − b²
    • Triple-check signs.
  2. Forgetting middle term

    • (x + 3)² ≠ x² + 9 ❌
    • (x + 3)² = x² + 6x + 9 ✓
  3. (a + b)² ≠ a² + b²

    • This is a classic error.
    • Always remember the middle term 2ab.
  4. Distributing wrong

    • x(y + z) = xy + xz (correct)
    • x(y + z) = xy + z ❌
  5. Factorising backwards

    • x² − 9 = (x − 3)(x + 3) (not (x + 9)(x − 1))

9. Mental-Math Power of Identities

Compute 51 × 49

  • = (50 + 1)(50 − 1)
  • = 50² − 1²
  • = 2500 − 1 = 2499

Compute 47²

  • = (50 − 3)²
  • = 50² − 2(50)(3) + 3²
  • = 2500 − 300 + 9 = 2209

Compute 102 × 98

  • = (100 + 2)(100 − 2)
  • = 100² − 4 = 9996

These algebraic identities turn into mental-math shortcuts!


10. Real-World Applications

Area Calculation

A square plot of side (x + 5) m has area (x + 5)² = x² + 10x + 25 m². Useful in real-estate planning.

Physics

Kinematic equations use the identity (a + b)²:

  • s = ut + ½at² uses these expansions implicitly.

Engineering

  • Stress and strain calculations
  • Structural design uses polynomial expansions
  • Signal processing decomposes signals using identities

Computing

  • Fast multiplication algorithms use the identity (a+b)(a−b) = a² − b²
  • Karatsuba's algorithm (used in libraries) is based on similar tricks

11. Historical Context

Brahmagupta's Identity

The Indian mathematician Brahmagupta (7th century CE) developed identities for products of binomials. His 'Brahma-Sphuta-Siddhanta' contained many algebraic results.

Lilavati

Bhaskara II's 'Lilavati' (12th c. CE) had numerous problems involving binomial multiplication, often disguised as poems and stories.

Modern Influence

European mathematicians (15th-17th c.) learnt algebraic identities through Arabic translations of Indian texts. Al-Khwarizmi's work (9th c.) propagated these to Europe.

The identities you learn today are part of an unbroken chain of mathematical heritage stretching back over 1,500 years.


12. Tips for Mastery

For Identities

  • Write each identity 10 times until you can reproduce them from memory
  • Practise applying each identity to 5 examples
  • Practise BACKWARDS: given x² + 6x + 9, factorise to (x + 3)²

For Computation

  • Whenever you see a number near a multiple of 10 or 100, try identities:
    • 102 = 100 + 2
    • 97 = 100 − 3
    • 51 × 49 = (50 + 1)(50 − 1)

For Factorisation

  • First, find common factors
  • Second, check if it's a perfect square trinomial
  • Third, check if it's a difference of squares
  • Fourth, try splitting the middle term

13. Conclusion

'We Distribute Yet Things Multiply' bridges arithmetic and algebra. The distributive property and the algebraic identities are tools you'll use in:

  • Quadratic equations (Class 10)
  • Polynomial calculus (Class 11+)
  • Coordinate geometry (Class 9+)
  • Physics and engineering problems

Master these identities now, and the rest of algebra becomes much easier. The visual area-method (rectangle decomposition) gives you a geometric intuition for what algebra is doing — never forget that algebra and geometry are two sides of the same coin.

Key formulas & results

Everything you need to memorise, in one card. Screenshot this for revision.

Distributive (sum)
a(b + c) = ab + ac
Distributive (difference)
a(b − c) = ab − ac
Two binomials
(a + b)(c + d) = ac + ad + bc + bd
FOIL method
Identity 1
(a + b)² = a² + 2ab + b²
Three terms
Identity 2
(a − b)² = a² − 2ab + b²
Middle term negative
Identity 3
a² − b² = (a + b)(a − b)
Difference of squares
Identity 5
(x + a)(x + b) = x² + (a+b)x + ab
Useful for splitting middle term
⚠️

Common mistakes & fixes

These are the exact errors that cost students marks in board exams. Read them once, save yourself the trouble.

WATCH OUT
(a+b)² = a² + b²
WRONG. (a+b)² = a² + 2ab + b². The MIDDLE TERM 2ab is essential.
WATCH OUT
(a−b)² = a² − b²
WRONG. (a−b)² = a² − 2ab + b². The middle term is −2ab, but b² is POSITIVE.
WATCH OUT
Sign error in middle term
(a+b)² has +2ab; (a−b)² has −2ab. Triple-check.
WATCH OUT
Distributing wrong
x(y+z) = xy + xz, NOT xy + z.
WATCH OUT
Wrong factorisation
x² − 9 = (x−3)(x+3), NOT (x−9)(x+1) or (x−3)².

Practice problems

Try each one yourself before tapping "Show solution". Active recall > rereading.

Q1EASY· Distribute
Simplify: 3x(2x + 5)
Show solution
✦ Answer: 3x × 2x + 3x × 5 = 6x² + 15x.
Q2EASY· Identity
Expand (x + 4)².
Show solution
✦ Answer: (a+b)² = a² + 2ab + b². Here a=x, b=4. So (x+4)² = x² + 2(x)(4) + 4² = x² + 8x + 16.
Q3MEDIUM· Binomial multiplication
Multiply (3x − 2)(2x + 5).
Show solution
Step 1 — Apply FOIL. F: 3x × 2x = 6x² O: 3x × 5 = 15x I: −2 × 2x = −4x L: −2 × 5 = −10 Step 2 — Combine like terms. 6x² + (15x − 4x) − 10 = 6x² + 11x − 10 Step 3 — Verify with substitution. Let x = 1: (3−2)(2+5) = 1 × 7 = 7 6(1) + 11(1) − 10 = 6 + 11 − 10 = 7 ✓ ✦ Answer: 6x² + 11x − 10.
Q4MEDIUM· Identity
Compute 97² using algebraic identity.
Show solution
Step 1 — Express 97 as 100 − 3. 97 = 100 − 3 Step 2 — Apply (a − b)² identity. 97² = (100 − 3)² = 100² − 2(100)(3) + 3² Step 3 — Compute. = 10000 − 600 + 9 = 9409 Step 4 — Verify by direct multiplication. 97 × 97 = 9409 ✓ ✦ Answer: 97² = 9409. This is much faster than direct multiplication.
Q5HARD· Factorisation
Factorise: (a) x² + 9x + 20 (b) 25y² − 49 (c) 4p² + 12p + 9
Show solution
Part (a) — Split the middle term. Look for two numbers with: sum = 9, product = 20. Try 4 and 5: 4+5 = 9 ✓; 4×5 = 20 ✓. x² + 9x + 20 = (x + 4)(x + 5). Part (b) — Difference of squares. 25y² − 49 = (5y)² − 7² = (5y + 7)(5y − 7). Part (c) — Perfect square trinomial. Recognise: 4p² = (2p)², 9 = 3², 12p = 2(2p)(3). Matches a² + 2ab + b² = (a+b)². 4p² + 12p + 9 = (2p + 3)². Step — Verify each. (a) (x+4)(x+5) = x² + 5x + 4x + 20 = x² + 9x + 20 ✓ (b) (5y+7)(5y−7) = 25y² − 49 ✓ (c) (2p+3)² = 4p² + 12p + 9 ✓ ✦ Answer: (a) (x+4)(x+5). (b) (5y+7)(5y−7). (c) (2p+3)².

5-minute revision

The whole chapter, distilled. Read this the night before the exam.

  • Distributive: a(b+c) = ab + ac
  • Two binomials: (a+b)(c+d) = ac + ad + bc + bd (FOIL)
  • (a+b)² = a² + 2ab + b²
  • (a−b)² = a² − 2ab + b²
  • a² − b² = (a+b)(a−b)
  • (x+a)(x+b) = x² + (a+b)x + ab
  • Factorisation methods: common factor, identity, splitting middle term, grouping
  • Useful for mental computation: 51² = (50+1)², 97 × 103 = 100² − 9 = 9991, etc.
  • Indian heritage: Brahmagupta and Bhaskara's work on identities
  • Visual proof: rectangle area method for distributive property

CBSE marks blueprint

Where the marks come from in this chapter — so you can plan your prep.

Typical chapter weightage: 10-12 marks per chapter

Question typeMarks eachTypical countWhat it tests
MCQ / Very Short12-3Identity recognition; quick expansion
Short Answer32Binomial multiplication; identity application
Long Answer51Multi-step factorisation; identity computation
Prep strategy
  • Memorise the 5 algebraic identities COLD
  • Practise FOIL on 20+ binomials
  • Master factorisation methods (common factor → identity → middle term)
  • Use identities for fast computation (51², 97², 102 × 98)
  • Verify all answers by re-multiplying

Where this shows up in the real world

This chapter isn't just an exam topic — it lives in the world around you.

Area calculation

If a square plot is being expanded by 'x' meters on each side, its new area is (s+x)² = s² + 2sx + x². Real-estate uses this often.

Karatsuba multiplication

Fast algorithm for multiplying huge numbers (used in cryptography). Based on identities like (a+b)(a−b) = a² − b².

Computer graphics

Pixel coordinates use polynomial expansions for transformations and zoom operations.

Indian heritage (Brahmagupta, Bhaskara)

Algebraic identities have a 1500+ year Indian tradition. Modern algebra builds on this foundation.

Exam strategy

Battle-tested tips from teachers and toppers for this chapter.

  1. Write down 5 key identities at start of exam
  2. Identify which identity applies — recognise patterns
  3. Use identities for mental shortcuts when possible
  4. For factorisation, always check common factor FIRST
  5. Verify factorisation by expanding back
  6. Show all steps clearly for partial credit

Going beyond the textbook

For olympiad aspirants and curious learners — topics that build on this chapter.

  • Identity (a+b)³ and (a−b)³ — expand fully
  • Trinomial expansion (a+b+c)²
  • Difference and sum of cubes: a³ ± b³
  • Brahmagupta's identity for product of sums of squares
  • Sophie Germain's identity: a⁴ + 4b⁴
  • Read about polynomial identities in number theory

Where else this chapter is tested

CBSE board isn't the only one — other exams test this chapter too.

CBSE Class 8 School ExamVery High
Class 8 Maths OlympiadVery High
NTSE Mental AbilityHigh
Class 9 PolynomialsVery High — direct prerequisite
Class 10 Quadratic EquationsVery High

Questions students ask

The real ones — pulled from the Q&A community and tutor sessions.

Think geometrically: (a+b)² is the area of a SQUARE of side (a+b). When you draw it and split into smaller rectangles, you get FOUR pieces: a×a, a×b, b×a, b×b — that is, a² + 2ab + b². The two 'a×b' rectangles are often forgotten — that's the 2ab. Students who write 'a² + b²' are forgetting the MIDDLE rectangles. Always remember: squaring a sum has THREE terms, not two.

PRIORITY ORDER: (1) FIRST check for common factor — pull it out. (2) THEN check if it matches an identity: a²+2ab+b² → (a+b)²; a²−b² → (a+b)(a−b). (3) For x² + bx + c, try splitting middle term — find two numbers with product c and sum b. (4) For 4-term polynomials, try grouping in pairs.

Engineering: stress-strain calculations use polynomial expansion. Computer science: fast multiplication algorithms (Karatsuba's) use (a+b)(a−b) = a²−b² to multiply huge numbers efficiently. Cryptography: RSA encryption uses identity-based techniques. Physics: many formulas (kinetic energy, projectile motion) use squared terms.
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