By the end of this chapter you'll be able to…

  • 1Describe galvanic cells, cell notation, and the role of the salt bridge
  • 2Use standard electrode potentials and the electrochemical series
  • 3Apply the Nernst equation to find cell potential at any concentration
  • 4Calculate molar conductivity and apply Kohlrausch's law
  • 5Compare primary/secondary batteries and explain corrosion and its prevention
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Why this chapter matters
Electrochemistry bridges chemical and electrical energy. Understanding galvanic and electrolytic cells, the Nernst equation, conductance, batteries, fuel cells, and corrosion explains how batteries power devices, how metals corrode, and the basis of many industrial processes.

Before you start — revise these

A 5-minute refresher here will save you 30 minutes of confusion below.

Electrochemistry

'Electricity can drive non-spontaneous reactions — and spontaneous reactions can produce electricity. Electrochemistry is the bridge between CHEMICAL and ELECTRICAL energy.'

1. Chapter Overview

Electrochemistry explores the relationship between CHEMICAL REACTIONS and ELECTRICITY. Topics include: ELECTROCHEMICAL CELLS (voltaic and electrolytic — devices that convert chemical energy ⇌ electrical energy), the NERNST EQUATION (relating cell potential to concentration), the STANDARD ELECTRODE POTENTIAL (E°), the ELECTROCHEMICAL SERIES, CONDUCTANCE (molar and equivalent conductivity, Kohlrausch's law), BATTERIES (primary and secondary), FUEL CELLS, and CORROSION.


2. Electrochemical Cells

Galvanic (Voltaic) Cell

  • A device that converts CHEMICAL energy into ELECTRICAL energy through spontaneous redox reactions.
  • Daniel cell: Zn (anode, oxidation) | ZnSO₄ || CuSO₄ | Cu (cathode, reduction).
  • Anode (−): Zn → Zn²⁺ + 2e⁻ (oxidation). Cathode (+): Cu²⁺ + 2e⁻ → Cu (reduction).
  • Salt bridge: Completes the circuit, maintains electrical neutrality, prevents mixing of solutions.

Cell Representation

  • Anode on LEFT, Cathode on RIGHT. Single line = phase boundary. Double line = salt bridge.
  • Zn(s) | Zn²⁺(aq, 1M) || Cu²⁺(aq, 1M) | Cu(s).

3. Standard Electrode Potential

  • Standard Hydrogen Electrode (SHE) : Reference electrode with E° = 0 V. H⁺(1M) | H₂(1 atm) | Pt.
  • Standard cell potential: E°_cell = E°_cathode − E°_anode.
  • Positive E°_cell: Spontaneous reaction (ΔG° = −nFE°_cell < 0). Negative: Non-spontaneous.

Electrochemical Series

  • Metals with MORE NEGATIVE E° are STRONGER REDUCING AGENTS (more reactive).
  • 'Li has the most negative E° (−3.04 V) — it is the STRONGEST reducing agent. F₂ has the most positive E° (+2.87 V) — it is the STRONGEST oxidising agent.'
High Reactivity (Negative E°)MedLow Reactivity (Positive E°)
Li, K, Ca, Na, Mg, Al, Zn, FeNi, Sn, PbCu, Ag, Hg, Pt, Au

4. Nernst Equation

For a General Reaction: aA + bB → cC + dD

  • E_cell = E°_cell − (0.0591/n) log Q (at 25°C, in volts).
  • E_cell = E°_cell − (RT/nF) ln Q (general form).

For a Single Electrode

  • Mⁿ⁺ + ne⁻ → M: E = E° − (0.0591/n) log(1/[Mⁿ⁺]) = E° + (0.0591/n) log[Mⁿ⁺].

Worked Example 1

Problem: Calculate E_cell for the Daniel cell when [Cu²⁺] = 0.01 M and [Zn²⁺] = 1 M. E°_cell = 1.1 V. Solution: Zn + Cu²⁺ → Zn²⁺ + Cu, n = 2. E_cell = 1.1 − (0.0591/2) log(1/0.01) = 1.1 − (0.02955) log(100) = 1.1 − 0.02955×2 = 1.1 − 0.0591 = 1.041 V.


5. Conductance

PropertySymbolFormulaUnit
ResistanceRR = ρ·l/AΩ
Conductivityκκ = 1/ρS/m (or Ω⁻¹m⁻¹)
Cell constantG*G* = l/Am⁻¹
Molar conductivityΛ_mΛ_m = κ/cS·m²/mol

Variation of Molar Conductivity

  • Strong electrolytes: Λ_m DECREASES SLOWLY as concentration increases (due to ion-ion interactions). Λ° = limiting molar conductivity (at infinite dilution).
  • Weak electrolytes: Λ_m INCREASES SHARPLY as concentration decreases (due to increased dissociation). Λ° is found using Kohlrausch's law.

Kohlrausch's Law

  • Λ° = λ°(+) + λ°(−). 'The molar conductivity at infinite dilution is the SUM of the INDEPENDENT contributions of the cation and anion.'
  • Application: Finding Λ° for weak electrolytes. Example: Λ°(CH₃COOH) = λ°(H⁺) + λ°(CH₃COO⁻).

6. Batteries

TypeCharacteristicsExamples
PrimaryNON-RECHARGEABLE — irreversible reactionDry cell (Leclanche), Mercury cell
SecondaryRECHARGEABLE — reversible reactionLead-acid battery (car battery), Ni-Cd, Li-ion
Fuel cellContinuous supply of reactantsH₂-O₂ fuel cell (produces electricity + water)

Lead-Acid Battery

  • Anode: Pb + SO₄²⁻ → PbSO₄ + 2e⁻. Cathode: PbO₂ + 4H⁺ + SO₄²⁻ + 2e⁻ → PbSO₄ + 2H₂O.
  • Overall: Pb + PbO₂ + 2H₂SO₄ → 2PbSO₄ + 2H₂O.
  • Voltage: ~2 V per cell. Six cells connected in series = 12 V car battery.

H₂-O₂ Fuel Cell

  • Anode: 2H₂ + 4OH⁻ → 4H₂O + 4e⁻. Cathode: O₂ + 2H₂O + 4e⁻ → 4OH⁻.
  • Overall: 2H₂ + O₂ → 2H₂O + Electrical energy. 'The only product is WATER — clean and efficient.'

7. Corrosion

  • 'The GRADUAL DESTRUCTION of metals by chemical or electrochemical reaction with the environment.'
  • Rusting of iron: Fe → Fe²⁺ (oxidation at ANODIC region). O₂ + 2H₂O + 4e⁻ → 4OH⁻ (reduction at CATHODIC region).
  • Prevention: Painting, galvanisation (coating with Zn), tinning, cathodic protection (sacrificial anode — Mg or Zn connected to iron).

8. Comparison Table: Electrolytic Cell vs Galvanic Cell

FeatureElectrolytic CellGalvanic Cell
Energy conversionElectrical → ChemicalChemical → Electrical
ReactionNON-spontaneous (driven by electricity)SPONTANEOUS
Electrode chargesAnode (+)Cathode (−)
Electron flowFrom external supplyFrom anode to cathode (external circuit)
ApplicationsElectroplating, electrolysisBatteries

9. Common Mistakes

  1. Anode vs Cathode in different cells: In a GALVANIC cell, anode is NEGATIVE. In an ELECTROLYTIC cell, anode is POSITIVE. 'In galvanic, oxidation happens at the negative electrode. In electrolytic, oxidation happens at the positive electrode.'
  2. Nernst equation sign: E = E° − (0.0591/n) log Q. It is MINUS, not plus. A large Q (products > reactants) REDUCES cell potential.
  3. Units of conductivity: κ is in S/m (or Ω⁻¹m⁻¹). Λ_m is in S·m²/mol. They differ by concentration: Λ_m = κ/c.
  4. Fuel cells are NOT batteries: Batteries store energy chemically and have a limited capacity. Fuel cells CONVERT fuel continuously as long as reactants are supplied.

10. CBSE Exam Focus

  1. Electrochemical cells — Daniel cell, cell notation, salt bridge
  2. Standard electrode potential — EMF of cell, electrochemical series
  3. Nernst equation — numerical problems (E_cell = E°_cell − 0.0591/n log Q)
  4. Conductance — molar conductivity, Kohlrausch's law
  5. Batteries — primary vs secondary, lead-acid, fuel cells
  6. Corrosion — mechanism, prevention methods

11. Self-Test

Q1: Calculate E°_cell for Zn|Zn²⁺||Ag⁺|Ag. Given: E°(Zn²⁺/Zn) = −0.76 V, E°(Ag⁺/Ag) = +0.80 V. A1: E°_cell = E°_cathode − E°_anode = 0.80 − (−0.76) = 1.56 V.

Q2: Calculate Λ° for CH₃COOH given λ°(H⁺) = 349.8 and λ°(CH₃COO⁻) = 40.9 S·cm²/mol. A2: Λ°(CH₃COOH) = λ°(H⁺) + λ°(CH₃COO⁻) = 349.8 + 40.9 = 390.7 S·cm²/mol.

Q3: For the reaction 2Al + 3Cu²⁺ → 2Al³⁺ + 3Cu, E° = 2.0 V. Calculate ΔG°. A3: n = 6 (Al → Al³⁺ loses 3e⁻, 2Al atoms = 6e⁻). ΔG° = −nFE° = −6×96500×2 = −1,158,000 J = −1158 kJ.

Q4: A copper electrode is placed in 0.001 M CuSO₄ solution at 25°C. Calculate its reduction potential. (E° = +0.34 V) A4: Cu²⁺ + 2e⁻ → Cu. E = E° + (0.0591/2) log[Cu²⁺] = 0.34 + 0.02955×log(0.001) = 0.34 + 0.02955×(−3) = 0.34 − 0.0887 = 0.251 V.

Q5: A solution of 0.05 M KCl has conductivity 0.007 S/m at 25°C. Find the molar conductivity. A5: Λ_m = κ/c = 0.007/(0.05×1000) = 0.007/50 = 1.4×10⁻⁴ S·m²/mol (Note: c is converted to mol/m³: 0.05 M = 50 mol/m³).


12. Conclusion

Electrochemistry is the SCIENCE of ENERGY CONVERSION:

  • CELLS: 'Galvanic cells produce electricity from spontaneous reactions. Electrolytic cells use electricity to drive non-spontaneous reactions.'
  • NERNST: 'Cell potential depends on concentration — dilute the reactants and the voltage changes.'
  • CONDUCTANCE: 'How well a solution conducts electricity depends on the number and mobility of ions.'
  • BATTERIES and CORROSION: 'The practical faces of electrochemistry — one we USE, the other we FIGHT.'

'Electrochemistry powers our devices, protects our structures, and drives essential industrial processes — it is chemistry in ACTION.'

Key formulas & results

Everything you need to memorise, in one card. Screenshot this for revision.

Standard cell potential
E_cell = E_cathode - E_anode; delta-G = -nF E_cell
Positive E_cell means a spontaneous cell reaction.
Nernst equation
E_cell = E_cell° - (0.0591/n) log Q (at 25 C)
Relates potential to reaction quotient/concentration.
Molar conductivity
Lambda_m = kappa/c; cell constant G* = l/A
kappa in S/m, Lambda_m in S m^2/mol.
Kohlrausch's law
Lambda° = lambda°(+) + lambda°(-)
Used to find Lambda° of weak electrolytes.
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Common mistakes & fixes

These are the exact errors that cost students marks in board exams. Read them once, save yourself the trouble.

WATCH OUT
Mixing up anode polarity between cell types
In a galvanic cell the anode is negative; in an electrolytic cell the anode is positive. Oxidation always occurs at the anode.
WATCH OUT
Getting the Nernst equation sign wrong
It is E = E° - (0.0591/n) log Q; a large Q (more products) lowers the cell potential.
WATCH OUT
Confusing conductivity and molar conductivity units
kappa is in S/m; molar conductivity Lambda_m = kappa/c is in S m^2/mol.
WATCH OUT
Calling a fuel cell a battery
A fuel cell continuously converts externally supplied fuel; a battery stores a fixed amount of chemical energy.

Practice problems

Try each one yourself before tapping "Show solution". Active recall > rereading.

Q1EASY· EMF
Calculate E_cell for Zn|Zn2+||Ag+|Ag (E(Zn2+/Zn) = -0.76 V, E(Ag+/Ag) = +0.80 V).
Show solution
E_cell = E_cathode - E_anode = 0.80 - (-0.76) = 1.56 V.
Q2EASY· Kohlrausch
Find Lambda° for CH3COOH given lambda°(H+) = 349.8 and lambda°(CH3COO-) = 40.9 S cm^2/mol.
Show solution
Lambda°(CH3COOH) = 349.8 + 40.9 = 390.7 S cm^2/mol.
Q3MEDIUM· Thermodynamics
For 2Al + 3Cu2+ -> 2Al3+ + 3Cu, E° = 2.0 V. Calculate delta-G°.
Show solution
n = 6. delta-G° = -nF E° = -6 x 96500 x 2 = -1,158,000 J = -1158 kJ.
Q4MEDIUM· Nernst
Find the reduction potential of a Cu electrode in 0.001 M CuSO4 at 25 C (E° = +0.34 V).
Show solution
E = E° + (0.0591/2) log[Cu2+] = 0.34 + 0.02955 x (-3) = 0.34 - 0.0887 = 0.251 V.
Q5MEDIUM· Conductance
A 0.05 M KCl solution has conductivity 0.007 S/m at 25 C. Find the molar conductivity.
Show solution
Convert c = 0.05 M = 50 mol/m^3. Lambda_m = kappa/c = 0.007/50 = 1.4e-4 S m^2/mol.

5-minute revision

The whole chapter, distilled. Read this the night before the exam.

  • Galvanic cell: chemical to electrical (spontaneous); electrolytic: electrical to chemical (non-spontaneous).
  • E_cell = E_cathode - E_anode; positive means spontaneous; delta-G = -nF E_cell.
  • Electrochemical series: more negative E means stronger reducing agent.
  • Nernst: E = E° - (0.0591/n) log Q at 25 C.
  • Conductivity kappa = 1/rho; molar conductivity Lambda_m = kappa/c.
  • Kohlrausch's law: Lambda° = lambda°(+) + lambda°(-).
  • Primary (non-rechargeable) vs secondary (rechargeable) batteries; corrosion prevented by galvanising and cathodic protection.

CBSE marks blueprint

Where the marks come from in this chapter — so you can plan your prep.

Typical chapter weightage: 7-9 marks across the chapter

Question typeMarks eachTypical countWhat it tests
Nernst equation3-51Cell potential at non-standard concentrations
Conductance / Kohlrausch31Molar conductivity and weak-electrolyte Lambda°
Cells / batteries / corrosion2-31Cell notation, batteries, corrosion prevention
Prep strategy
  • Practise the Nernst equation with correct sign
  • Memorise E_cell = E_cathode - E_anode and delta-G = -nF E
  • Learn conductivity units and Kohlrausch's law
  • Know battery reactions and corrosion prevention

Where this shows up in the real world

This chapter isn't just an exam topic — it lives in the world around you.

Batteries

Galvanic cells power phones, vehicles, and devices; lead-acid and Li-ion are everyday examples.

Electroplating and extraction

Electrolytic cells are used in electroplating, metal refining, and producing chlorine and aluminium.

Corrosion control

Cathodic protection and galvanising save billions by preventing rusting of pipelines and structures.

Exam strategy

Battle-tested tips from teachers and toppers for this chapter.

  1. Write cell notation with anode left, cathode right
  2. Apply the Nernst equation carefully with the minus sign
  3. Convert concentration units before computing Lambda_m
  4. Know electrode reactions for the standard batteries

Going beyond the textbook

For olympiad aspirants and curious learners — topics that build on this chapter.

  • Relate E_cell° to the equilibrium constant via delta-G° = -RT ln K = -nF E°.
  • Analyse concentration cells and overpotential in electrolysis.

Where else this chapter is tested

CBSE board isn't the only one — other exams test this chapter too.

CBSE Class 12 Chemistry examHigh
JEE Main and Advanced (Electrochemistry)High
NEET ChemistryHigh

Questions students ask

The real ones — pulled from the Q&A community and tutor sessions.

As a galvanic cell operates, reactants are consumed and products accumulate, so the reaction quotient Q increases. In the Nernst equation E = E° - (0.0591/n) log Q, a larger Q makes the subtracted term bigger, lowering E_cell. When the reaction reaches equilibrium, Q equals the equilibrium constant, E_cell becomes zero, and the cell is 'dead'.

In an H2-O2 fuel cell, hydrogen is oxidised and oxygen reduced, and the only product is water (2H2 + O2 -> 2H2O), with no carbon dioxide or pollutants. Fuel cells convert chemical energy directly into electrical energy without combustion, so they avoid the thermodynamic losses of heat engines and achieve high efficiency, making them attractive for clean power generation.
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Last reviewed on 30 May 2026. Written and reviewed by subject-matter experts — read about our process.
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