By the end of this chapter you'll be able to…

  • 1Draw Lewis structures and assign formal charges
  • 2Predict molecular shapes using VSEPR theory
  • 3Determine the hybridisation of central atoms
  • 4Calculate bond order and predict magnetic behaviour using MO theory
  • 5Explain hydrogen bonding and its effect on physical properties
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Why this chapter matters
Chemical bonding explains why compounds form and what shapes they take. Lewis structures, VSEPR theory, hybridisation, molecular orbital theory, and hydrogen bonding let you predict molecular geometry, polarity, bond order, and magnetic behaviour -- the basis for all of organic and inorganic chemistry.

Chemical Bonding and Molecular Structure

'Atoms are held together by the desire to achieve the noble gas configuration.' — Kossel and Lewis

1. Chapter Overview

Why do atoms BOND? And what DETERMINES the shape of molecules? This chapter answers these questions. It covers the LEWIS theory of bonding, IONIC and COVALENT bonds, VSEPR THEORY (for predicting molecular shapes), HYBRIDISATION (mixing of orbitals), MOLECULAR ORBITAL THEORY (MO), and HYDROGEN BONDING. Understanding bonding is ESSENTIAL for predicting chemical reactivity.


2. Kossel-Lewis Approach to Chemical Bonding

  • Octet Rule: Atoms combine to achieve an OUTER SHELL of 8 electrons (noble gas configuration)
  • Lewis Symbols: Represent valence electrons as dots around the element symbol
  • Lewis Structures: Show HOW atoms are bonded and where LONE PAIRS are

Formal Charge

  • Formal Charge = Valence e⁻ — [Lone pairs + ½(Bonding e⁻)]
  • The MOST STABLE Lewis structure has formal charges CLOSEST to zero

Limitations of Octet Rule

  • Incomplete octet (H, Be, B, Al) — BeCl₂, BF₃
  • Expanded octet (P, S, Cl, Xe) — PCl₅, SF₆, XeF₄
  • Odd-electron molecules — NO₂, NO

3. Ionic (Electrovalent) Bond

  • Formation: COMPLETE transfer of electrons from one atom to another
  • Conditions: Low IE (metal) + High EG (non-metal) + High lattice energy
  • Properties: High melting point, soluble in water, conduct electricity in molten state

Factors Affecting Ionic Bond Strength

  • Lattice Energy ∝ (Charge₁ × Charge₂)/(r₁ + r₂)
  • Higher charge → Stronger bond (MgO > NaCl)
  • Smaller ions → Stronger bond (LiF > CsI)

4. Covalent Bond

  • Formation: SHARING of electrons between atoms
  • Types:
    • Single bond (σ bond): 1 shared pair
    • Double bond (σ + π): 2 shared pairs
    • Triple bond (σ + 2π): 3 shared pairs

Bond Parameters

ParameterDefinitionUnits
Bond LengthDistance between bonded nucleipm or Å
Bond AngleAngle between two bondsdegrees
Bond EnthalpyEnergy required to break 1 mole of bondskJ/mol
Bond Order½(Bonding e⁻ — Antibonding e⁻)Unitless

Polarity of Bonds

  • Non-polar covalent: Equal sharing (H₂, Cl₂, N₂)
  • Polar covalent: Unequal sharing (HCl, H₂O)
  • Ionic: Complete transfer (NaCl)
  • Electronegativity difference determines bond type:
    • ΔEN < 0.4: Non-polar covalent
    • 0.4 < ΔEN < 1.7: Polar covalent
    • ΔEN > 1.7: Ionic

5. VSEPR Theory (Valence Shell Electron Pair Repulsion)

Basic Principle

  • Electron pairs (bonded AND lone pairs) arrange themselves to MINIMISE repulsion
  • Lone pair — Lone pair > Lone pair — Bond pair > Bond pair — Bond pair

Molecular Shapes

Total e⁻ PairsLone PairsGeometryShapeExample
20LinearLinearBeCl₂, CO₂
30Trigonal planarTrigonal planarBF₃
31Trigonal planarBentSO₂, O₃
40TetrahedralTetrahedralCH₄
41TetrahedralTrigonal pyramidalNH₃
42TetrahedralBentH₂O
50Trigonal bipyramidalTrigonal bipyramidalPCl₅
51Trigonal bipyramidalSeesawSF₄
60OctahedralOctahedralSF₆

6. Hybridisation

  • Definition: Mixing of ATOMIC ORBITALS to form EQUIVALENT HYBRID ORBITALS

Types of Hybridisation

TypeOrbitals MixedGeometryBond AngleExamples
sp1s + 1pLinear180°BeCl₂, C₂H₂
sp²1s + 2pTrigonal planar120°BF₃, C₂H₄
sp³1s + 3pTetrahedral109.5°CH₄, NH₃, H₂O
dsp²1d + 1s + 2pSquare planar90°[Ni(CN)₄]²⁻
sp³d1s + 3p + 1dTrigonal bipyramidal90°, 120°PCl₅
sp³d²1s + 3p + 2dOctahedral90°SF₆

Worked Problem

Q: Determine hybridisation and shape of NH₃. A: N has 5 valence e⁻, 3 bond pairs (H) + 1 lone pair = 4 electron pairs → sp³ hybridisation. Shape: TRIGONAL PYRAMIDAL (lone pair pushes bonds in).


7. Molecular Orbital (MO) Theory

Key Concepts

  • Atomic orbitals combine to form MOLECULAR ORBITALS (bonding σ/π and antibonding σ*/π*)
  • Number of MOs = Number of atomic orbitals combined
  • Bond Order = (N_b — N_a)/2
  • MOs are filled following Aufbau, Pauli, and Hund's rules

Electronic Configuration of Homonuclear Diatomics

  • For molecules up to N₂ (2p orbitals): σ1s < σ1s < σ2s < σ2s < π2p_x = π2p_y < σ2p_z < π2p_x = π2p_y < σ*2p_z
  • For O₂, F₂: Order of σ2p_z and π2p_x/y SWAPS

Magnetic Behaviour

  • All e⁻ paired → DIAMAGNETIC (repelled by magnetic field)
  • Unpaired e⁻ → PARAMAGNETIC (attracted by magnetic field)
  • O₂ is PARAMAGNETIC (2 unpaired electrons in π* orbitals) — MO theory explains this!

Worked Problem

Q: Calculate bond order of O₂ and N₂. A: N₂ (14 e⁻): σ1s² σ1s² σ2s² σ2s² π2p⁴ σ2p². BO = (10 — 4)/2 = 3. O₂ (16 e⁻): σ1s² σ1s² σ2s² σ2s² σ2p² π2p⁴ π*2p². BO = (10 — 6)/2 = 2.


8. Hydrogen Bonding

  • Definition: ATTRACTIVE force between H atom (bonded to high EN atom: F, O, N) and a LONE PAIR on another EN atom
  • Intermolecular H-bonding: Between DIFFERENT molecules (H₂O, HF, NH₃)
  • Intramolecular H-bonding: Within the SAME molecule (o-nitrophenol)

Effects of H-Bonding

  • Higher boiling points (H₂O > H₂S despite same group)
  • Ice is LESS dense than water (open structure due to H-bonds)
  • Proteins and DNA structure (alpha helices, double helix)

9. Common Mistakes

  1. Molecules with lone pairs are NOT the same shape as the electron pair geometry: NH₃ is trigonal PYRAMIDAL (not tetrahedral), H₂O is BENT (not tetrahedral)
  2. Bond order ≠ number of bonds: For O₂, bond order = 2, but O₂ has a DOUBLE bond with 2 unpaired electrons
  3. Odd-electron species cannot be represented by Lewis structures properly: NO, NO₂
  4. Intramolecular H-bonding LOWERS boiling point (no inter-molecular association)
  5. d-orbitals participate in hybridisation ONLY for heavier elements (n ≥ 3)

10. CBSE Exam Focus

  1. Lewis dot structures of molecules (3-mark)
  2. VSEPR theory — predicting shapes (5-mark)
  3. Hybridisation of central atom in molecules (3/5-mark)
  4. Molecular orbital theory — bond order calculations (5-mark)
  5. Magnetic behaviour using MO theory (3-mark)
  6. Hydrogen bonding — types and effects (3-mark)

11. Key Formulas

  • Bond Order = (N_b — N_a)/2
  • Dipole Moment μ = q × d (Debye units)
  • % Ionic character = (μ_observed / μ_calculated) × 100%
  • Formal Charge = V — (L + B/2)

12. Self-Test (5+ Q&A)

Q1: Determine hybridisation and shape of SF₄. A: S has 6 valence e⁻, 4 bond pairs + 1 lone pair = 5 pairs → sp³d hybridisation. Shape: SEE-SAW (not trigonal bipyramidal!).

Q2: Calculate bond order and predict magnetic behaviour of O₂²⁻ (peroxide ion). A: O₂²⁻ has 18 e⁻. BO = (10 — 8)/2 = 1. All e⁻ paired → DIAMAGNETIC.

Q3: Why is H₂O bent but CO₂ linear? A: H₂O: O has 2 bond pairs + 2 lone pairs → sp³ → BENT. CO₂: C has 2 double bonds, NO lone pairs → sp → LINEAR.

Q4: What is hydrogen bond strength compared to covalent bond? A: H-bonds (10-40 kJ/mol) are MUCH WEAKER than covalent bonds (200-400 kJ/mol) but STRONGER than van der Waals forces.

Q5: Explain why O₂ is paramagnetic using MO theory. A: O₂ has 16 e⁻. The π*2p orbitals contain 2 e⁻ in DIFFERENT orbitals with PARALLEL SPINS (Hund's rule). These unpaired electrons cause paramagnetism.


13. Conclusion

Chemical bonding EXPLAINS why compounds form and what shapes they take. Lewis theory provides a STARTING POINT. VSEPR predicts molecular shapes from electron pair repulsion. Hybridisation explains EQUIVALENT bonds in molecules like CH₄. MO theory gives the MOST COMPLETE picture — explaining bond order, magnetic behaviour, and spectroscopy. Hydrogen bonding, while WEAK, has enormous consequences for water's properties and biological molecules. Bonding concepts are ESSENTIAL for understanding organic chemistry and chemical reactions.

Key formulas & results

Everything you need to memorise, in one card. Screenshot this for revision.

Bond order (MO theory)
BO = (N_b - N_a)/2
N_b = bonding electrons, N_a = antibonding electrons.
Formal charge
FC = V - (L + B/2)
V = valence electrons, L = lone-pair electrons, B = bonding electrons.
Dipole moment
mu = q x d (in Debye)
Vector quantity; net mu = 0 for symmetric molecules like CO2.
Percent ionic character
% ionic = (mu_observed / mu_calculated) x 100
Measures how polar a covalent bond is.
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Common mistakes & fixes

These are the exact errors that cost students marks in board exams. Read them once, save yourself the trouble.

WATCH OUT
Equating molecular shape with electron-pair geometry
Lone pairs change the shape: NH3 is trigonal pyramidal (not tetrahedral) and H2O is bent (not tetrahedral).
WATCH OUT
Confusing bond order with the number of bonds drawn
O2 has bond order 2 but, by MO theory, it also has 2 unpaired electrons making it paramagnetic.
WATCH OUT
Thinking intramolecular H-bonding raises boiling point
Intramolecular H-bonding (e.g. o-nitrophenol) lowers boiling point because it prevents intermolecular association.
WATCH OUT
Using d-orbital hybridisation for second-period elements
d-orbitals participate only for elements with n >= 3 (P, S, Cl, Xe); C, N, O cannot expand their octet.

Practice problems

Try each one yourself before tapping "Show solution". Active recall > rereading.

Q1MEDIUM· VSEPR
Determine the hybridisation and shape of SF4.
Show solution
S has 6 valence electrons: 4 bond pairs + 1 lone pair = 5 electron pairs, so sp3d hybridisation. The lone pair occupies an equatorial position, giving a see-saw shape (not trigonal bipyramidal).
Q2HARD· MO Theory
Calculate the bond order of O2 2- (peroxide ion) and predict its magnetic behaviour.
Show solution
O2 2- has 18 electrons. Bond order = (10 - 8)/2 = 1. All electrons are paired, so it is diamagnetic.
Q3MEDIUM· Shape
Why is H2O bent but CO2 linear?
Show solution
In H2O, oxygen has 2 bond pairs and 2 lone pairs (sp3), and the lone pairs push the bonds together giving a bent shape. In CO2, carbon has 2 double bonds and no lone pairs (sp), giving a linear shape.
Q4HARD· MO Theory
Explain why O2 is paramagnetic using molecular orbital theory.
Show solution
O2 has 16 electrons. The last two occupy the two degenerate pi*2p antibonding orbitals singly with parallel spins (Hund's rule). These two unpaired electrons make O2 paramagnetic -- a result that Lewis structures cannot explain but MO theory predicts.
Q5MEDIUM· H-bonding
Why does water have a higher boiling point than H2S?
Show solution
Water forms strong intermolecular hydrogen bonds (O-H...O) because oxygen is small and highly electronegative. H2S cannot form effective hydrogen bonds, so it has a much lower boiling point despite being in the same group.

5-minute revision

The whole chapter, distilled. Read this the night before the exam.

  • Octet rule: atoms bond to achieve a noble-gas configuration; exceptions are incomplete, expanded, and odd-electron species.
  • Ionic bond strength rises with higher ionic charge and smaller ionic size (lattice energy).
  • VSEPR: electron pairs arrange to minimise repulsion; lone pairs distort the shape.
  • Hybridisation: sp (linear), sp2 (trigonal planar), sp3 (tetrahedral), sp3d, sp3d2.
  • MO theory: bond order = (N_b - N_a)/2; explains O2's paramagnetism.
  • Hydrogen bonding (F, O, N) raises boiling points and makes ice less dense than water.
  • Bond breaking is endothermic; bond formation is exothermic.

CBSE marks blueprint

Where the marks come from in this chapter — so you can plan your prep.

Typical chapter weightage: 8-10 marks across the chapter

Question typeMarks eachTypical countWhat it tests
VSEPR / hybridisation3-51-2Predicting shape and hybridisation of central atoms
MO theory3-51Bond order and magnetic behaviour
Lewis / H-bonding2-31Lewis structures, formal charge, hydrogen bonding
Prep strategy
  • Memorise the VSEPR shape table with examples
  • Learn hybridisation from the count of sigma bonds plus lone pairs
  • Practise MO diagrams for N2, O2, and their ions
  • Distinguish inter- and intramolecular hydrogen bonding

Where this shows up in the real world

This chapter isn't just an exam topic — it lives in the world around you.

Drug design

Molecular shape and hydrogen bonding determine how drug molecules fit into biological receptors.

Materials and polymers

Bonding and intermolecular forces control the strength, flexibility, and melting points of plastics and fibres.

Life's molecules

Hydrogen bonds hold together the DNA double helix and protein structures that make life possible.

Exam strategy

Battle-tested tips from teachers and toppers for this chapter.

  1. State hybridisation and shape together, noting the effect of lone pairs
  2. Write the MO electron configuration before computing bond order
  3. Justify magnetic behaviour from unpaired electrons
  4. Quote bond enthalpy and dipole moment formulas where relevant

Going beyond the textbook

For olympiad aspirants and curious learners — topics that build on this chapter.

  • Construct MO diagrams for heteronuclear diatomics like CO and NO and interpret their bond orders.
  • Explore Bent's rule and the relationship between hybridisation, s-character, and bond angles.

Where else this chapter is tested

CBSE board isn't the only one — other exams test this chapter too.

CBSE Class 11 Chemistry examVery High
JEE Main and Advanced (Chemical Bonding)Very High
NEET ChemistryVery High

Questions students ask

The real ones — pulled from the Q&A community and tutor sessions.

Count the number of sigma bonds plus the number of lone pairs on the central atom. A total of 2 = sp, 3 = sp2, 4 = sp3, 5 = sp3d, and 6 = sp3d2. For example, in NH3 nitrogen has 3 sigma bonds and 1 lone pair = 4, so it is sp3.

Lewis structures and VSEPR cannot explain the paramagnetism of O2 or the existence of species like He2+ with fractional bond order. MO theory treats electrons as occupying molecular orbitals spread over the whole molecule, so it correctly predicts bond order, magnetic behaviour, and the relative stability of molecules and ions.
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Last reviewed on 29 May 2026. Written and reviewed by subject-matter experts — read about our process.
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