By the end of this chapter you'll be able to…

  • 1Define probability and sample space
  • 2Calculate P(event) for simple experiments
  • 3Use complementary events
  • 4Solve coin, dice, card problems
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Why this chapter matters
Foundation for statistics, machine learning, finance, sports analytics. Universal concept.

Before you start — revise these

A 5-minute refresher here will save you 30 minutes of confusion below.

Probability — Class 10 Mathematics

"Probability: the measure of how likely something is to happen — a number between 0 (impossible) and 1 (certain)."

1. About the Chapter

Probability quantifies UNCERTAINTY. It's used in:

  • Insurance (calculating risks)
  • Weather forecasting
  • Medicine (treatment effectiveness)
  • Sports analytics
  • Computer science (machine learning)
  • Cricket strike rates

Class 10 Focus

Mostly THEORETICAL probability (assuming equally likely outcomes).

Closes Class 10 Math

This is the final chapter of Class 10. Brief, but important foundation.


2. Basic Definitions

Random Experiment

An experiment whose outcome cannot be predicted with certainty.

  • Tossing a coin
  • Rolling a die
  • Drawing a card from deck

Outcome

A possible result of an experiment.

  • Tossing coin: Head (H) or Tail (T)
  • Rolling die: 1, 2, 3, 4, 5, or 6

Sample Space (S)

The set of ALL possible outcomes.

  • Tossing 1 coin: S = {H, T}
  • Rolling 1 die: S = {1, 2, 3, 4, 5, 6}

Event

A subset of the sample space.

  • 'Getting a head' = {H}
  • 'Getting an even number' = {2, 4, 6}

Favourable Outcomes

Outcomes in which the desired event occurs.


3. Probability Formula

Classical Probability

P(E) = (Number of favourable outcomes) / (Total number of outcomes)

= n(E) / n(S)

Range

0 ≤ P(E) ≤ 1

  • P(E) = 0: IMPOSSIBLE event
  • P(E) = 1: SURE/CERTAIN event
  • 0 < P(E) < 1: Possible

Sum of Probabilities

For all outcomes in sample space: SUM = 1.

For an event E and its complement E': P(E) + P(E') = 1

So: P(E') = 1 − P(E)


4. Common Examples

Coin Toss

  • 1 coin: S = {H, T}; P(H) = 1/2
  • 2 coins: S = {HH, HT, TH, TT}; P(at least one H) = 3/4

Dice

  • 1 die: S = {1, ..., 6}
  • P(prime) = 3/6 = 1/2 (primes: 2, 3, 5)
  • P(even) = 3/6 = 1/2
  • P(> 4) = 2/6 = 1/3

Two Dice

  • Total outcomes: 6 × 6 = 36
  • Possible sums: 2 to 12
  • P(sum = 7) = 6/36 = 1/6 (highest probability!)

Cards (52 in a deck)

  • 4 suits: Hearts, Diamonds (red); Clubs, Spades (black)
  • 13 cards per suit: A, 2, 3, ..., 10, J, Q, K
  • Face cards: J, Q, K (12 total: 3 × 4)
  • P(any specific card) = 1/52
  • P(ace) = 4/52 = 1/13
  • P(face card) = 12/52 = 3/13
  • P(red card) = 26/52 = 1/2
  • P(spade) = 13/52 = 1/4

5. Complementary Events

Definition

For event E, the complementary event E' (or NOT E) contains all outcomes NOT in E.

Formula

P(E) + P(NOT E) = 1

Example

If P(passing exam) = 0.8, then P(failing) = 1 − 0.8 = 0.2.

Useful When

  • Direct counting is hard
  • 'At least one' problems

6. Worked Examples

Example 1: Single Die

A die is rolled. Find P(getting a number < 4).

  • Favourable: 1, 2, 3 (three outcomes)
  • Total: 6
  • P = 3/6 = 1/2

Example 2: Card Draw

A card is drawn from 52-deck. Find: (a) P(red card) = 26/52 = 1/2 (b) P(king) = 4/52 = 1/13 (c) P(red king) = 2/52 = 1/26 (d) P(card with letter on it) = 16/52 = 4/13 (Ace + J + Q + K)

Example 3: Two Coins

Two coins are tossed. Find P(exactly one head).

  • Sample space: {HH, HT, TH, TT}
  • Favourable: {HT, TH}
  • P = 2/4 = 1/2

Example 4: Box of Balls

A box contains 3 red, 5 blue, 2 green balls. A ball is drawn at random. (a) P(red) = 3/10 (b) P(blue) = 5/10 = 1/2 (c) P(not red) = 7/10 (d) P(red or blue) = 8/10 = 4/5

Example 5: Two Dice — Sum

Two dice rolled. Find P(sum = 8).

  • Total outcomes: 36
  • Favourable: (2,6), (3,5), (4,4), (5,3), (6,2) — 5 outcomes
  • P = 5/36

Example 6: Birthday Problem

A class has 30 students. Probability that 2 have same birthday?

  • Very HIGH (≈ 70%) — famous birthday paradox
  • (Beyond Class 10 syllabus but interesting)

7. Geometric Probability (Brief)

When outcomes lie in a geometric region: P = (Favourable region area) / (Total region area)

Example

A point is chosen randomly inside a square of side 2. Probability it lies in inscribed circle?

  • Circle area = π(1)² = π
  • Square area = 4
  • P = π/4 ≈ 0.785

8. Common Mistakes

  1. Forgetting all outcomes equally likely

    • Classical probability ASSUMES equal likelihood. For weighted dice, biased coins, this fails.
  2. Wrong sample space

    • For 2 coins, S = {HH, HT, TH, TT} (4 outcomes), not 3 (HH, HT, TT).
  3. Adding probabilities of intersecting events

    • P(A or B) ≠ P(A) + P(B) if events overlap. (Need inclusion-exclusion, Class 11.)
  4. Confusing P(E) and P(E')

    • P(E) + P(E') = 1, so P(NOT E) = 1 − P(E).
  5. Probability > 1

    • IMPOSSIBLE. If you get P > 1, you've made an error.

9. Real-World Applications

Insurance

Companies calculate probability of accidents, deaths to set premiums.

Weather

'70% chance of rain' = probability statement.

Cricket

  • Run rate, strike rate use probability concepts
  • Probability of winning given current score

Medicine

  • Probability of recovering from a disease
  • Drug effectiveness in trials

Gambling/Games

  • Lottery: P(winning) ≈ 1/14,000,000 (extremely low!)
  • Poker probabilities

Indian Context

  • IPL match predictions use probability
  • Election polling
  • Indian Statistical Institute leads probability research

10. Famous Probability Problems

Coin Toss Paradox

If you toss a fair coin 10 times and get 10 heads in a row, P(11th toss being head) = ?

  • Still 1/2!
  • Each toss is INDEPENDENT.

Monty Hall Problem

3 doors, prize behind one. You pick door 1. Host opens door 3 (empty). Should you switch to door 2?

  • YES! Switching increases probability from 1/3 to 2/3.
  • Famous and counterintuitive.

Birthday Paradox

In a room of 23 people, probability that 2 share a birthday is over 50%.

  • Counterintuitive but true.

11. Conclusion

Probability is the mathematics of UNCERTAINTY:

  • We can quantify how likely things are
  • Make informed decisions under uncertainty
  • Foundation for statistics, machine learning, gambling theory

Master:

  • Formula: P = favourable / total
  • Sample space for various experiments
  • Complementary events
  • Word problems (cards, dice, coins, real-life)

This chapter is BRIEF but IMPORTANT for board exam (~6-8 marks).

In Class 11-12, you'll learn:

  • Conditional probability
  • Bayes' theorem
  • Probability distributions
  • Statistics with probability

For now, master the basics. Practice 15+ problems.

Probability: the math of guessing right.

Key formulas & results

Everything you need to memorise, in one card. Screenshot this for revision.

Probability
P(E) = n(E)/n(S)
Favourable/Total
Range
0 ≤ P(E) ≤ 1
P(impossible)
0
P(sure)
1
Complementary
P(E') = 1 − P(E)
Sum
P(E) + P(E') = 1
⚠️

Common mistakes & fixes

These are the exact errors that cost students marks in board exams. Read them once, save yourself the trouble.

WATCH OUT
Probability > 1
Impossible. P is between 0 and 1. Check calculation.
WATCH OUT
Wrong sample space size
Two coins: 4 outcomes (HH, HT, TH, TT). Two dice: 36 outcomes. Cards: 52.
WATCH OUT
Forgetting independence
Coin tosses are independent — previous results don't affect next.

NCERT exercises (with solutions)

Every NCERT exercise from this chapter — what it covers and how many questions to expect.

Practice problems

Try each one yourself before tapping "Show solution". Active recall > rereading.

Q1EASY· Coin
If a coin is tossed, what is the probability of getting a head?
Show solution
✦ Answer: Sample space = {H, T}. Favourable = {H}. P(H) = 1/2.
Q2MEDIUM· Card
A card is drawn from a deck of 52. Find P(face card) and P(red face card).
Show solution
Step 1 — Face cards. Face cards: J, Q, K of each suit (4 suits × 3 = 12 face cards) Step 2 — P(face card). P = 12/52 = 3/13 Step 3 — Red face cards. Red suits: Hearts, Diamonds (2 suits × 3 face cards = 6) Step 4 — P(red face card). P = 6/52 = 3/26 ✦ Answer: P(face card) = 3/13; P(red face card) = 3/26.
Q3HARD· Two dice
Two dice are rolled. Find P(sum = 7), P(sum > 9), and P(doubles).
Show solution
Step 1 — Total outcomes. 6 × 6 = 36 Step 2 — P(sum = 7). Combinations: (1,6), (2,5), (3,4), (4,3), (5,2), (6,1) — 6 outcomes P(sum=7) = 6/36 = 1/6 Step 3 — P(sum > 9), i.e., sum 10, 11, or 12. Sum 10: (4,6), (5,5), (6,4) — 3 outcomes Sum 11: (5,6), (6,5) — 2 outcomes Sum 12: (6,6) — 1 outcome Total: 6 outcomes P(sum>9) = 6/36 = 1/6 Step 4 — P(doubles). Doubles: (1,1), (2,2), (3,3), (4,4), (5,5), (6,6) — 6 outcomes P(doubles) = 6/36 = 1/6 Step 5 — Verify. All values 6/36 = 1/6 ✓ ✦ Answer: P(sum=7) = P(sum>9) = P(doubles) = 1/6.

5-minute revision

The whole chapter, distilled. Read this the night before the exam.

  • P(E) = favourable/total
  • 0 ≤ P(E) ≤ 1
  • P(sure) = 1; P(impossible) = 0
  • P(E) + P(NOT E) = 1
  • 1 coin: 2 outcomes; 2 coins: 4; 3 coins: 8
  • 1 die: 6 outcomes; 2 dice: 36
  • Deck of cards: 52 (4 suits × 13)
  • Face cards: J, Q, K (12 total)
  • Sum of probabilities of all outcomes = 1

CBSE marks blueprint

Where the marks come from in this chapter — so you can plan your prep.

Typical chapter weightage: 6-8 marks

Question typeMarks eachTypical countWhat it tests
MCQ12-3Definitions, simple P
Short2-31-2Card, dice, coin problems
Long50-1Multi-step probability
Prep strategy
  • Master sample space for coins (2,4,8), dice (6,36), cards (52)
  • Practice 20+ problems
  • Use complementary events when easier

Where this shows up in the real world

This chapter isn't just an exam topic — it lives in the world around you.

Insurance

Premiums based on probability of accidents, deaths. Indian LIC uses actuarial probability.

Weather forecasts

'70% chance of rain' is a probability statement. IMD uses probabilistic models.

Cricket analytics

Win probability, strike rate analysis use probability.

Indian elections

Polling uses sample probability to predict outcomes.

Exam strategy

Battle-tested tips from teachers and toppers for this chapter.

  1. Write sample space clearly
  2. Count favourable outcomes carefully
  3. Use complementary when easier
  4. Verify P between 0 and 1

Going beyond the textbook

For olympiad aspirants and curious learners — topics that build on this chapter.

  • Bayes' theorem
  • Random variables
  • Probability distributions
  • Monte Carlo methods

Where else this chapter is tested

CBSE board isn't the only one — other exams test this chapter too.

CBSE Class 10 BoardHigh
Maths OlympiadMedium
JEE FoundationHigh

Questions students ask

The real ones — pulled from the Q&A community and tutor sessions.

For fair experiments. Fair coin: P(H) = P(T) = 1/2. Fair die: each face 1/6. If coin is biased or die loaded, classical probability doesn't apply directly.
Verified by the tuition.in editorial team
Last reviewed on 20 May 2026. Written and reviewed by subject-matter experts — read about our process.
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