By the end of this chapter you'll be able to…

  • 1Define 6 trigonometric ratios
  • 2Apply ratios in right triangles
  • 3Memorise ratios at 0°, 30°, 45°, 60°, 90°
  • 4Use identities (sin²θ + cos²θ = 1, etc.)
  • 5Apply complementary angle relations
💡
Why this chapter matters
Foundation for all trigonometry, calculus, physics, engineering. Indian heritage (Aryabhata invented sine).

Before you start — revise these

A 5-minute refresher here will save you 30 minutes of confusion below.

Introduction to Trigonometry — Class 10 Mathematics

"Triangles + Ratios = Trigonometry. The mathematics that measures the sky."

1. About the Chapter

Trigonometry = 'measurement of triangles' (Greek: 'trigonon' + 'metron'). Used in:

  • Astronomy (measuring stars)
  • Surveying (measuring heights)
  • Engineering (forces, designs)
  • Physics (waves, oscillations)

This chapter introduces the six trigonometric ratios and basic identities.

Indian Heritage

  • Aryabhata (5th century CE): defined sine ('jya'); coined trigonometric ratios
  • Brahmagupta, Bhaskara II: refined and extended trigonometry
  • Sanskrit 'jya' became Arabic 'jiba' became Latin 'sinus' → English 'sine'

2. Right-Angled Triangle Review

For △ABC with right angle at B:

         A
         /|
        / |
       /  | ← perpendicular (P)
      /θ_|
     B    C
     base (B)
   hypotenuse from B to A

Wait, let me redraw. In a right triangle with right angle at C:

  • Side opposite to angle A = a (perpendicular for angle A)
  • Side opposite to angle B = b
  • Side opposite to right angle (C) = c (hypotenuse)

For ANGLE θ (one of the acute angles):

  • Opposite side: side opposite to θ
  • Adjacent side: side next to θ (not hypotenuse)
  • Hypotenuse: longest side, opposite to 90° angle

3. The Six Trigonometric Ratios

For an acute angle θ in a right triangle:

Sine (sin θ)

sin θ = Opposite / Hypotenuse = P / H

Cosine (cos θ)

cos θ = Adjacent / Hypotenuse = B / H

Tangent (tan θ)

tan θ = Opposite / Adjacent = P / B

Cosecant (cosec θ) — reciprocal of sin

cosec θ = Hypotenuse / Opposite = H / P = 1 / sin θ

Secant (sec θ) — reciprocal of cos

sec θ = Hypotenuse / Adjacent = H / B = 1 / cos θ

Cotangent (cot θ) — reciprocal of tan

cot θ = Adjacent / Opposite = B / P = 1 / tan θ

Memory Aid (SOH CAH TOA)

  • SOH: Sin = Opposite/Hypotenuse
  • CAH: Cos = Adjacent/Hypotenuse
  • TOA: Tan = Opposite/Adjacent

4. Reciprocal Relations

These give 3 more ratios:

  • sin θ × cosec θ = 1 → cosec θ = 1/sin θ
  • cos θ × sec θ = 1 → sec θ = 1/cos θ
  • tan θ × cot θ = 1 → cot θ = 1/tan θ

Also:

  • tan θ = sin θ / cos θ
  • cot θ = cos θ / sin θ

5. Trigonometric Ratios of Specific Angles

TABLE (MEMORISE!)

Anglesincostancosecseccot
0101
30°1/2√3/21/√322/√3√3
45°1/√21/√21√2√21
60°√3/21/2√32/√321/√3
90°1010

Memory Tricks

  • sin 0°, 30°, 45°, 60°, 90° = √0/2, √1/2, √2/2, √3/2, √4/2
  • That is: 0, 1/2, √2/2, √3/2, 1

cos is sin in REVERSE order:

  • cos 0°, 30°, 45°, 60°, 90° = 1, √3/2, √2/2, 1/2, 0

tan = sin / cos (gets ∞ where cos = 0)


6. Pythagoras and Trigonometry

From Pythagoras: P² + B² = H²

Divide by H²: (P/H)² + (B/H)² = 1

This gives: sin²θ + cos²θ = 1 — fundamental identity!


7. Trigonometric Identities (MEMORISE)

Three Key Identities

Identity 1: sin²θ + cos²θ = 1

Identity 2: 1 + tan²θ = sec²θ

Identity 3: 1 + cot²θ = cosec²θ

Derivations

Identity 2: Divide Identity 1 by cos²θ:

  • sin²θ/cos²θ + 1 = 1/cos²θ
  • tan²θ + 1 = sec²θ → 1 + tan²θ = sec²θ ✓

Identity 3: Divide Identity 1 by sin²θ:

  • 1 + cos²θ/sin²θ = 1/sin²θ
  • 1 + cot²θ = cosec²θ ✓

Useful Forms

  • sin²θ = 1 − cos²θ
  • cos²θ = 1 − sin²θ
  • sec²θ − tan²θ = 1
  • cosec²θ − cot²θ = 1

8. Trigonometric Ratios of Complementary Angles

If A + B = 90° (complementary):

  • sin A = cos B (sin(90°−A) = cos A)
  • cos A = sin B
  • tan A = cot B
  • cot A = tan B
  • sec A = cosec B
  • cosec A = sec B

Examples

  • sin 30° = cos 60° = 1/2 ✓
  • tan 45° = cot 45° = 1 ✓
  • sec 60° = cosec 30° = 2 ✓

9. Worked Examples

Example 1: Find Ratios

In right △ABC, ∠B = 90°, AB = 3, BC = 4. Find sin C, cos C, tan C.

  • AC (hypotenuse) = √(9+16) = 5
  • For angle C: opposite = AB = 3, adjacent = BC = 4, hypotenuse = 5
  • sin C = 3/5, cos C = 4/5, tan C = 3/4

Example 2: Use Identity

Find sin A if cos A = 5/13.

  • sin²A + cos²A = 1
  • sin²A = 1 − 25/169 = 144/169
  • sin A = 12/13

Example 3: Specific Values

Evaluate: sin 30° × cos 60° + sin 60° × cos 30°

  • = (1/2)(1/2) + (√3/2)(√3/2)
  • = 1/4 + 3/4 = 1

(This is actually sin(30° + 60°) = sin 90° = 1, using formula sin(A+B), but for Class 10 we calculate directly.)

Example 4: Prove Identity

Prove: (1 − sin²θ) × sec²θ = 1

  • LHS = cos²θ × (1/cos²θ) = 1
  • = RHS ✓

Example 5: Complementary Angles

sin 60° = cos ?

  • 60° = 90° − 30°
  • sin 60° = cos 30°
  • So the answer is 30°

10. Common Mistakes

  1. Confusing opposite and adjacent

    • 'Opposite' is OPPOSITE to the angle θ; 'Adjacent' is the OTHER side (not hypotenuse).
  2. Wrong specific angle values

    • MEMORISE the table. Don't guess.
  3. Forgetting reciprocal relations

    • cosec ≠ cos. cosec = 1/sin.
  4. Identity confusion

    • sin²θ + cos²θ = 1 (NOT sin θ + cos θ = 1).
  5. tan at 90°

    • tan 90° is UNDEFINED (∞), not 0.

11. Indian Heritage of Trigonometry

Aryabhata (476-550 CE)

  • Defined SINE (jya), COSINE (kojya), VERSINE
  • Tables of sines for various angles
  • Used in astronomy

Brahmagupta (598-668 CE)

  • Extended Aryabhata's work
  • Brahmagupta-Fibonacci identity

Bhaskara II (1114-1185 CE)

  • Refined trigonometric calculations
  • Indian astronomy depended heavily on this

Madhava (1340-1425 CE)

  • INFINITE SERIES for sin, cos, arctan
  • 200 years before Newton!
  • Astonishing achievement

Word Origin

Sanskrit 'jya' → Arabic 'jiba' → Latin 'sinus' → English 'sine'

A direct line from Indian mathematics to global use.


12. Conclusion

Trigonometry is one of the MOST USED branches of mathematics:

  • Astronomy: distances to stars, planet orbits
  • Engineering: forces, structures, machines
  • Physics: waves, oscillations, optics
  • Computer graphics: rotations, animations

Master:

  • 6 trigonometric ratios (SOH CAH TOA)
  • Specific angle values (0°, 30°, 45°, 60°, 90°)
  • 3 identities (sin² + cos² = 1, etc.)
  • Complementary angles relations

Chapter 9 will apply these to REAL-WORLD problems (heights and distances).

Trigonometry: the mathematics of triangles, taught by Indians to the world.

Key formulas & results

Everything you need to memorise, in one card. Screenshot this for revision.

sin θ
Opposite/Hypotenuse
SOH
cos θ
Adjacent/Hypotenuse
CAH
tan θ
Opposite/Adjacent
TOA
cosec θ
1/sin θ = H/P
sec θ
1/cos θ = H/B
cot θ
1/tan θ = B/P
Identity 1
sin²θ + cos²θ = 1
Most important
Identity 2
1 + tan²θ = sec²θ
Identity 3
1 + cot²θ = cosec²θ
sin 30°
1/2
Specific
sin 45°
1/√2
Specific
sin 60°
√3/2
Specific
⚠️

Common mistakes & fixes

These are the exact errors that cost students marks in board exams. Read them once, save yourself the trouble.

WATCH OUT
Confusing opposite and adjacent
For angle θ: opposite is OPPOSITE the angle; adjacent is next to it (not hypotenuse).
WATCH OUT
Mixing reciprocal ratios
cosec ≠ cos. cosec is 1/sin. sec is 1/cos. cot is 1/tan.
WATCH OUT
Identity formula
sin²θ + cos²θ = 1 (SQUARED, not just sin θ + cos θ).
WATCH OUT
Wrong specific values
MEMORISE the table. Don't guess.

Practice problems

Try each one yourself before tapping "Show solution". Active recall > rereading.

Q1EASY· Ratios
If sin A = 3/5, find cos A.
Show solution
✦ Answer: sin²A + cos²A = 1; (3/5)² + cos²A = 1; cos²A = 1 − 9/25 = 16/25; cos A = 4/5.
Q2EASY· Specific
What is tan 60°?
Show solution
✦ Answer: tan 60° = √3 (from memorised table).
Q3MEDIUM· Identity
Prove: (1 − cos²θ)(1 + cot²θ) = 1.
Show solution
Step 1 — Use identities. (1 − cos²θ) = sin²θ (1 + cot²θ) = cosec²θ = 1/sin²θ Step 2 — Multiply. LHS = sin²θ × 1/sin²θ = 1 = RHS ✓ ✦ Proved.
Q4HARD· Application
If 5 sin θ = 3, find the values of cos θ, tan θ, sec θ, cosec θ, cot θ.
Show solution
Step 1 — Find sin θ. 5 sin θ = 3 ⟹ sin θ = 3/5 Step 2 — Find cos θ using identity. sin²θ + cos²θ = 1 9/25 + cos²θ = 1 cos²θ = 16/25 cos θ = 4/5 (positive since θ is acute) Step 3 — Find tan θ. tan θ = sin θ / cos θ = (3/5)/(4/5) = 3/4 Step 4 — Find reciprocal ratios. cosec θ = 1/sin θ = 5/3 sec θ = 1/cos θ = 5/4 cot θ = 1/tan θ = 4/3 ✦ Answer: cos θ = 4/5, tan θ = 3/4, sec θ = 5/4, cosec θ = 5/3, cot θ = 4/3.

5-minute revision

The whole chapter, distilled. Read this the night before the exam.

  • Six ratios: sin, cos, tan, cosec, sec, cot
  • SOH CAH TOA mnemonic
  • Reciprocal: cosec=1/sin, sec=1/cos, cot=1/tan
  • Identity 1: sin²θ + cos²θ = 1
  • Identity 2: 1 + tan²θ = sec²θ
  • Identity 3: 1 + cot²θ = cosec²θ
  • Specific values: 0°, 30°, 45°, 60°, 90° (memorise)
  • Complementary: sin(90°−θ) = cos θ etc.
  • Aryabhata invented sine ('jya')

CBSE marks blueprint

Where the marks come from in this chapter — so you can plan your prep.

Typical chapter weightage: 10-12 marks

Question typeMarks eachTypical countWhat it tests
MCQ13Definitions, specific values
Short Answer2-32Identities, ratios
Long Answer51Prove identities, find all ratios
Prep strategy
  • MEMORISE table of specific angles cold
  • MEMORISE 3 identities
  • Practice 20+ proof problems
  • Master SOH CAH TOA mnemonic

Where this shows up in the real world

This chapter isn't just an exam topic — it lives in the world around you.

Surveying

Indian Survey department uses trigonometry to map terrain.

Astronomy

Aryabhata used trigonometry for astronomical calculations 1500 years ago.

Engineering

Bridge angles, roof slopes, machine parts all use trigonometry.

Exam strategy

Battle-tested tips from teachers and toppers for this chapter.

  1. Memorise specific angle values
  2. Use identities to simplify
  3. Show step-by-step proofs
  4. Check answer for reasonableness

Going beyond the textbook

For olympiad aspirants and curious learners — topics that build on this chapter.

  • sin(A+B), cos(A+B) formulas (Class 11)
  • Trigonometric equations
  • Inverse trigonometric functions
  • Hyperbolic functions

Where else this chapter is tested

CBSE board isn't the only one — other exams test this chapter too.

CBSE Class 10 BoardVery High
Maths OlympiadVery High
JEEVery High
NEET PhysicsVery High

Questions students ask

The real ones — pulled from the Q&A community and tutor sessions.

Trigonometry is essential because: (1) measure heights and distances without direct measurement; (2) describe waves (sound, light, radio); (3) calculate forces in physics; (4) navigate (GPS uses spherical trigonometry); (5) computer graphics rely on it. From ancient astronomy to modern engineering.
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Last reviewed on 20 May 2026. Written and reviewed by subject-matter experts — read about our process.
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