Introduction to Trigonometry — Class 10 Mathematics
"Triangles + Ratios = Trigonometry. The mathematics that measures the sky."
1. About the Chapter
Trigonometry = 'measurement of triangles' (Greek: 'trigonon' + 'metron'). Used in:
- Astronomy (measuring stars)
- Surveying (measuring heights)
- Engineering (forces, designs)
- Physics (waves, oscillations)
This chapter introduces the six trigonometric ratios and basic identities.
Indian Heritage
- Aryabhata (5th century CE): defined sine ('jya'); coined trigonometric ratios
- Brahmagupta, Bhaskara II: refined and extended trigonometry
- Sanskrit 'jya' became Arabic 'jiba' became Latin 'sinus' → English 'sine'
2. Right-Angled Triangle Review
For △ABC with right angle at B:
A
/|
/ |
/ | ← perpendicular (P)
/θ_|
B C
base (B)
hypotenuse from B to A
Wait, let me redraw. In a right triangle with right angle at C:
- Side opposite to angle A = a (perpendicular for angle A)
- Side opposite to angle B = b
- Side opposite to right angle (C) = c (hypotenuse)
For ANGLE θ (one of the acute angles):
- Opposite side: side opposite to θ
- Adjacent side: side next to θ (not hypotenuse)
- Hypotenuse: longest side, opposite to 90° angle
3. The Six Trigonometric Ratios
For an acute angle θ in a right triangle:
Sine (sin θ)
sin θ = Opposite / Hypotenuse = P / H
Cosine (cos θ)
cos θ = Adjacent / Hypotenuse = B / H
Tangent (tan θ)
tan θ = Opposite / Adjacent = P / B
Cosecant (cosec θ) — reciprocal of sin
cosec θ = Hypotenuse / Opposite = H / P = 1 / sin θ
Secant (sec θ) — reciprocal of cos
sec θ = Hypotenuse / Adjacent = H / B = 1 / cos θ
Cotangent (cot θ) — reciprocal of tan
cot θ = Adjacent / Opposite = B / P = 1 / tan θ
Memory Aid (SOH CAH TOA)
- SOH: Sin = Opposite/Hypotenuse
- CAH: Cos = Adjacent/Hypotenuse
- TOA: Tan = Opposite/Adjacent
4. Reciprocal Relations
These give 3 more ratios:
- sin θ × cosec θ = 1 → cosec θ = 1/sin θ
- cos θ × sec θ = 1 → sec θ = 1/cos θ
- tan θ × cot θ = 1 → cot θ = 1/tan θ
Also:
- tan θ = sin θ / cos θ
- cot θ = cos θ / sin θ
5. Trigonometric Ratios of Specific Angles
TABLE (MEMORISE!)
| Angle | sin | cos | tan | cosec | sec | cot |
|---|---|---|---|---|---|---|
| 0° | 0 | 1 | 0 | ∞ | 1 | ∞ |
| 30° | 1/2 | √3/2 | 1/√3 | 2 | 2/√3 | √3 |
| 45° | 1/√2 | 1/√2 | 1 | √2 | √2 | 1 |
| 60° | √3/2 | 1/2 | √3 | 2/√3 | 2 | 1/√3 |
| 90° | 1 | 0 | ∞ | 1 | ∞ | 0 |
Memory Tricks
- sin 0°, 30°, 45°, 60°, 90° = √0/2, √1/2, √2/2, √3/2, √4/2
- That is: 0, 1/2, √2/2, √3/2, 1
cos is sin in REVERSE order:
- cos 0°, 30°, 45°, 60°, 90° = 1, √3/2, √2/2, 1/2, 0
tan = sin / cos (gets ∞ where cos = 0)
6. Pythagoras and Trigonometry
From Pythagoras: P² + B² = H²
Divide by H²: (P/H)² + (B/H)² = 1
This gives: sin²θ + cos²θ = 1 — fundamental identity!
7. Trigonometric Identities (MEMORISE)
Three Key Identities
Identity 1: sin²θ + cos²θ = 1
Identity 2: 1 + tan²θ = sec²θ
Identity 3: 1 + cot²θ = cosec²θ
Derivations
Identity 2: Divide Identity 1 by cos²θ:
- sin²θ/cos²θ + 1 = 1/cos²θ
- tan²θ + 1 = sec²θ → 1 + tan²θ = sec²θ ✓
Identity 3: Divide Identity 1 by sin²θ:
- 1 + cos²θ/sin²θ = 1/sin²θ
- 1 + cot²θ = cosec²θ ✓
Useful Forms
- sin²θ = 1 − cos²θ
- cos²θ = 1 − sin²θ
- sec²θ − tan²θ = 1
- cosec²θ − cot²θ = 1
8. Trigonometric Ratios of Complementary Angles
If A + B = 90° (complementary):
- sin A = cos B (sin(90°−A) = cos A)
- cos A = sin B
- tan A = cot B
- cot A = tan B
- sec A = cosec B
- cosec A = sec B
Examples
- sin 30° = cos 60° = 1/2 ✓
- tan 45° = cot 45° = 1 ✓
- sec 60° = cosec 30° = 2 ✓
9. Worked Examples
Example 1: Find Ratios
In right △ABC, ∠B = 90°, AB = 3, BC = 4. Find sin C, cos C, tan C.
- AC (hypotenuse) = √(9+16) = 5
- For angle C: opposite = AB = 3, adjacent = BC = 4, hypotenuse = 5
- sin C = 3/5, cos C = 4/5, tan C = 3/4
Example 2: Use Identity
Find sin A if cos A = 5/13.
- sin²A + cos²A = 1
- sin²A = 1 − 25/169 = 144/169
- sin A = 12/13
Example 3: Specific Values
Evaluate: sin 30° × cos 60° + sin 60° × cos 30°
- = (1/2)(1/2) + (√3/2)(√3/2)
- = 1/4 + 3/4 = 1
(This is actually sin(30° + 60°) = sin 90° = 1, using formula sin(A+B), but for Class 10 we calculate directly.)
Example 4: Prove Identity
Prove: (1 − sin²θ) × sec²θ = 1
- LHS = cos²θ × (1/cos²θ) = 1
- = RHS ✓
Example 5: Complementary Angles
sin 60° = cos ?
- 60° = 90° − 30°
- sin 60° = cos 30°
- So the answer is 30°
10. Common Mistakes
-
Confusing opposite and adjacent
- 'Opposite' is OPPOSITE to the angle θ; 'Adjacent' is the OTHER side (not hypotenuse).
-
Wrong specific angle values
- MEMORISE the table. Don't guess.
-
Forgetting reciprocal relations
- cosec ≠ cos. cosec = 1/sin.
-
Identity confusion
- sin²θ + cos²θ = 1 (NOT sin θ + cos θ = 1).
-
tan at 90°
- tan 90° is UNDEFINED (∞), not 0.
11. Indian Heritage of Trigonometry
Aryabhata (476-550 CE)
- Defined SINE (jya), COSINE (kojya), VERSINE
- Tables of sines for various angles
- Used in astronomy
Brahmagupta (598-668 CE)
- Extended Aryabhata's work
- Brahmagupta-Fibonacci identity
Bhaskara II (1114-1185 CE)
- Refined trigonometric calculations
- Indian astronomy depended heavily on this
Madhava (1340-1425 CE)
- INFINITE SERIES for sin, cos, arctan
- 200 years before Newton!
- Astonishing achievement
Word Origin
Sanskrit 'jya' → Arabic 'jiba' → Latin 'sinus' → English 'sine'
A direct line from Indian mathematics to global use.
12. Conclusion
Trigonometry is one of the MOST USED branches of mathematics:
- Astronomy: distances to stars, planet orbits
- Engineering: forces, structures, machines
- Physics: waves, oscillations, optics
- Computer graphics: rotations, animations
Master:
- 6 trigonometric ratios (SOH CAH TOA)
- Specific angle values (0°, 30°, 45°, 60°, 90°)
- 3 identities (sin² + cos² = 1, etc.)
- Complementary angles relations
Chapter 9 will apply these to REAL-WORLD problems (heights and distances).
Trigonometry: the mathematics of triangles, taught by Indians to the world.
