By the end of this chapter you'll be able to…

  • 1Define tangent to a circle
  • 2Apply 'tangent perpendicular to radius' theorem
  • 3Apply 'equal tangents from external point' theorem
  • 4Solve problems with tangent lengths
💡
Why this chapter matters
Tangent properties used in engineering, optics, design. Foundational geometry.

Before you start — revise these

A 5-minute refresher here will save you 30 minutes of confusion below.

Circles — Class 10 Mathematics

"A circle is the simplest yet most profound shape — perfect symmetry around a single point."

1. About the Chapter

After studying circles in Class 9 (basic definitions, chord properties), Class 10 focuses on TANGENTS to circles — lines that touch a circle at exactly one point.

Why Important

Tangent properties are used in:

  • Wheel and gear systems
  • Optics (light rays at tangent angles)
  • Engineering designs
  • Astronomy (planetary orbits)

2. Recap — Circle Basics

Definitions

  • Circle: set of all points equidistant from a fixed point (centre)
  • Radius: distance from centre to circle
  • Chord: line segment with both endpoints on the circle
  • Diameter: longest chord, passes through centre = 2 × radius
  • Arc: portion of the circumference
  • Sector: pie-slice region

Position of a Line Relative to a Circle

A line can be:

  1. Non-intersecting (does not touch circle)
  2. Tangent (touches at exactly 1 point)
  3. Secant (intersects at 2 points)

3. Tangent to a Circle

Definition

A tangent is a line that touches a circle at EXACTLY ONE POINT.

Point of Contact

The single point where tangent touches the circle.

Common Examples

  • Tyre touching the road
  • Coin balanced on edge of table
  • Sun's rays just grazing the horizon

4. Properties of Tangents (KEY THEOREMS)

Theorem 1: Tangent is Perpendicular to Radius at Point of Contact

The tangent at any point of a circle is perpendicular to the radius drawn to the point of contact.

If OP is radius to point P on circle, and AB is tangent at P, then OP ⊥ AB.

Proof (Outline)

Suppose tangent AB touches circle at P. Among all line segments from O to AB, OP is the shortest (since others go from O to points outside circle). Shortest distance from a point to a line is perpendicular. So OP ⊥ AB.

Theorem 2: Tangents from External Point are Equal

The lengths of two tangents drawn from an external point to a circle are equal.

If P is external, and PA, PB are tangents (touching circle at A, B), then PA = PB.

Proof (Outline)

  • OA = OB (both radii)
  • ∠OAP = ∠OBP = 90° (tangent ⊥ radius)
  • OP common to both △OAP and △OBP
  • △OAP ≅ △OBP (RHS criterion)
  • Therefore PA = PB

Number of Tangents from a Point

  • Inside circle: 0 tangents
  • On circle: 1 tangent
  • Outside circle: 2 tangents

5. Worked Examples

Example 1: Find Tangent Length

A point P is at a distance of 13 cm from the centre of a circle of radius 5 cm. Find the length of the tangent from P to the circle.

Setup:

  • OP = 13 cm (distance from centre to external point)
  • OQ = 5 cm (radius to tangent point Q)
  • OQ ⊥ PQ (tangent perpendicular to radius)

Apply Pythagoras in △OPQ:

  • PQ² = OP² − OQ² = 169 − 25 = 144
  • PQ = 12 cm

Recognise the 5-12-13 triple.

Example 2: Equal Tangents

From external point P, two tangents PA and PB are drawn to a circle. If PA = 7 cm, find PB.

  • By theorem: PA = PB
  • PB = 7 cm

Example 3: Inscribed Quadrilateral

A circle is inscribed in a triangle ABC, touching sides at D, E, F. If AB = 10, BC = 11, AC = 13, find lengths of tangents.

Let tangents from each vertex = x, y, z.

  • AD = AF = x
  • BD = BE = y
  • CE = CF = z

Then:

  • AB = x + y = 10
  • BC = y + z = 11
  • AC = x + z = 13

Adding: 2(x+y+z) = 34 → x+y+z = 17

  • z = 17 − 10 = 7
  • x = 17 − 11 = 6
  • y = 17 − 13 = 4

Example 4: Tangent Equation Style

Two tangents from external point to circle are 8 cm. Find the radius if the point is 10 cm from centre.

  • Tangent length = 8
  • Distance from centre = 10
  • Radius² = 10² − 8² = 100 − 64 = 36
  • Radius = 6 cm

6. Real-World Applications

Engineering

  • Pulley systems use tangent properties
  • Gear designs based on circles and tangents
  • Belt drives between two pulleys

Optics

  • Light rays reflecting off lenses use tangent geometry
  • Spectacle lenses designed with tangents

Astronomy

  • Planetary orbit tangents
  • Eclipses involve tangent lines from Sun to Earth/Moon

Construction

  • Road curves designed using tangent geometry
  • Arches in architecture

Modern Tech

  • GPS uses tangent properties for distance
  • Robotics uses circular motion with tangents

7. Common Mistakes

  1. Forgetting perpendicularity

    • At point of contact, TANGENT IS PERPENDICULAR to radius.
  2. Tangent passes through centre

    • NO. Tangent is OUTSIDE circle (except at point of contact).
  3. Tangents from interior point

    • From point INSIDE circle: NO tangent possible.
  4. Length confusion

    • Tangent length is measured FROM external point TO point of contact.
  5. Pythagoras error

    • In △OPQ: OP is hypotenuse (distance to external point), OQ is leg (radius), PQ is leg (tangent length).

8. Indian Context

Circles in Indian Mathematics

  • Aryabhata approximated π to 3.1416
  • Madhava of Kerala (14th c.) gave infinite series for π
  • Indian Vedic geometry used circles extensively

Modern Use

  • Indian Railways tracks use circular curves
  • Highway design uses tangent transitions

9. Worked Example with Two Tangents

Example: Tangents from External Point

From external point P, two tangents are drawn touching circle at A and B. If angle APB = 60°, find angle AOB.

In quadrilateral OAPB:

  • ∠OAP = 90° (tangent ⊥ radius)
  • ∠OBP = 90° (tangent ⊥ radius)
  • ∠APB = 60° (given)
  • Sum of angles in quadrilateral = 360°
  • ∠AOB = 360° − 90° − 90° − 60° = 120°

10. Conclusion

The geometry of tangents is elegant and PROFOUND:

  • Tangent ⊥ Radius at point of contact
  • External tangents are EQUAL in length
  • Used everywhere — engineering, optics, design

Master:

  • Two key theorems
  • Pythagoras in tangent problems
  • Equal tangent lengths

This chapter is high-yield for board exams. Practice 15+ problems.

Circles and tangents: geometry's most graceful relationship.

Key formulas & results

Everything you need to memorise, in one card. Screenshot this for revision.

Tangent property 1
Tangent ⊥ Radius at point of contact
Tangent property 2
Tangents from external point are EQUAL
Tangent length (using Pythagoras)
Tangent² = (distance from centre)² − radius²
From external point
2 tangents possible
⚠️

Common mistakes & fixes

These are the exact errors that cost students marks in board exams. Read them once, save yourself the trouble.

WATCH OUT
Tangent passes through center
Tangent touches circle at ONE point; does NOT pass through center. Only chord/diameter passes through center.
WATCH OUT
From inside point, tangent possible
From point INSIDE circle: NO tangent possible. From point ON circle: 1 tangent. From point OUTSIDE: 2 tangents.

NCERT exercises (with solutions)

Every NCERT exercise from this chapter — what it covers and how many questions to expect.

Practice problems

Try each one yourself before tapping "Show solution". Active recall > rereading.

Q1EASY· Property
How many tangents can be drawn from a point on the circle?
Show solution
✦ Answer: Only ONE tangent. (From point on circle: 1 tangent; outside: 2; inside: 0.)
Q2MEDIUM· Pythagoras
From a point P at distance 15 cm from centre of circle of radius 9 cm, find tangent length.
Show solution
Step 1 — Setup. OP = 15 (centre to external point) OQ = 9 (radius to point of contact Q) PQ = tangent length (perpendicular) Right triangle at Q. Step 2 — Apply Pythagoras. PQ² = OP² − OQ² = 225 − 81 = 144 PQ = 12 cm Step 3 — Recognise. (9, 12, 15) is 3 × (3, 4, 5) Pythagorean triple. ✦ Answer: Tangent length = 12 cm.
Q3HARD· Multiple tangents
A circle is inscribed in a triangle ABC where AB = 8 cm, BC = 10 cm, AC = 12 cm. Find the lengths of tangents from A, B, C to the circle.
Show solution
Step 1 — Variables. Let tangent from A = x, from B = y, from C = z. Step 2 — Sides as sum of tangents. AB: tangent from A + tangent from B = x + y = 8 BC: y + z = 10 AC: x + z = 12 Step 3 — Add all three. 2(x + y + z) = 30 x + y + z = 15 Step 4 — Find each. z = 15 − 8 = 7 (from AB sum) x = 15 − 10 = 5 (from BC sum) y = 15 − 12 = 3 (from AC sum) Step 5 — Verify. x + y = 5 + 3 = 8 ✓ y + z = 3 + 7 = 10 ✓ x + z = 5 + 7 = 12 ✓ ✦ Answer: Tangent from A = 5 cm, from B = 3 cm, from C = 7 cm.

5-minute revision

The whole chapter, distilled. Read this the night before the exam.

  • Tangent: line touching circle at exactly 1 point
  • Tangent ⊥ Radius at point of contact
  • Tangents from external point are EQUAL
  • From outside: 2 tangents; on: 1; inside: 0
  • Use Pythagoras in right triangle (centre, contact, external point)

CBSE marks blueprint

Where the marks come from in this chapter — so you can plan your prep.

Typical chapter weightage: 6-8

Question typeMarks eachTypical countWhat it tests
MCQ12Properties
Short2-31-2Tangent length
Long50-1Inscribed circle problems
Prep strategy
  • Memorise 2 key theorems
  • Master Pythagoras in tangent problems
  • Practice inscribed circle problems

Where this shows up in the real world

This chapter isn't just an exam topic — it lives in the world around you.

Wheels and pulleys

Tyre on road, belt on pulley use tangent geometry.

Optics

Light rays reflecting from circles/spheres follow tangent geometry.

Road design

Curved roads transition via tangent lines.

Exam strategy

Battle-tested tips from teachers and toppers for this chapter.

  1. Always note tangent ⊥ radius
  2. Use Pythagoras in tangent problems
  3. Equal tangents from external point save calculation

Going beyond the textbook

For olympiad aspirants and curious learners — topics that build on this chapter.

  • Power of a point
  • Pole and polar
  • Conic sections

Where else this chapter is tested

CBSE board isn't the only one — other exams test this chapter too.

CBSE Class 10 BoardHigh
Maths OlympiadHigh
JEE FoundationHigh

Questions students ask

The real ones — pulled from the Q&A community and tutor sessions.

Because of congruent triangles. Drawing radius to each tangent point creates two right triangles with: same hypotenuse (line from external point to centre), same legs (radii), and shared hypotenuse. They're congruent (RHS), so tangent lengths are equal.
Verified by the tuition.in editorial team
Last reviewed on 20 May 2026. Written and reviewed by subject-matter experts — read about our process.
Editorial process →
Header Logo