By the end of this chapter you'll be able to…

  • 1State the scientific definition of work and apply it to identify zero-work and negative-work situations
  • 2Compute kinetic energy (½mv²) and gravitational potential energy (mgh) for any body
  • 3State and apply the work-energy theorem to solve numericals without using acceleration
  • 4State the law of conservation of mechanical energy and trace KE↔PE swaps in a free fall or pendulum
  • 5Compute average power; distinguish instantaneous and average power
  • 6Convert between joules, kilowatt-hours and other energy units
  • 7List five distinct forms of energy and identify the transformation chain in everyday devices
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Why this chapter matters
Energy is the most powerful single idea in physics. Conservation of energy applies to mechanics, heat, electricity, chemistry, biology, cosmology — every field of natural science. Master this chapter and the rest of physics begins to feel unified.

Before you start — revise these

A 5-minute refresher here will save you 30 minutes of confusion below.

Work and Energy — Class 9 (CBSE)

Lift a book. Push a wall. Run up a flight of stairs. In daily speech, all three feel like "work." In physics, only one of them is actually work. This chapter teaches the scientific definition of work, the related idea of energy, and the rule that energy can never be created or destroyed — only changed from one form to another.


1. The story — the redefinition of work

In ordinary life, "work" means effort: studying for an exam, pushing a heavy box, even thinking hard. In physics, the definition is much more precise — and counterintuitive.

Work, in physics, is done when a force produces a displacement in the direction of the force.

So pushing a wall (with no displacement) = ZERO work, even though you sweat doing it. Lifting a book = work was done against gravity. Carrying a book horizontally = ZERO work on the book (no vertical displacement in the direction of the lifting force).

This redefinition allows physics to connect work directly to ENERGY — the capacity to do work. Energy can never be created or destroyed (conservation law), only transformed.

This chapter is short on equations and long on careful thinking. Let's begin.


2. Scientific definition of work

For a constant force acting on a body that moves a displacement in the direction of the force:

SI unit: joule (J) = N·m = kg·m²/s².

Three conditions must be met for work to be done:

  1. A force is applied.
  2. The body moves (there's displacement).
  3. The displacement has a component along the direction of the force.

If any of these is missing, work done = 0.

Three special cases

(a) Force and displacement in same direction (positive). A horse pulls a cart forward; positive work on the cart.

(b) Force and displacement in opposite directions (negative). Friction on a moving box; brake on a car. The agent of force REMOVES energy from the body.

(c) Force perpendicular to displacement . A boy carries a suitcase horizontally — his lifting force (vertical) is perpendicular to his horizontal motion. Zero work done on the suitcase.

Famous examples of zero work

  • Pushing a wall that doesn't move: no displacement → zero work.
  • A satellite orbiting the Earth at constant altitude: gravity (toward centre) is perpendicular to motion (along orbit) → zero work.
  • Carrying a book at constant height while walking forward: lifting force is vertical, motion is horizontal → zero work on book.

In everyday speech, all three "feel like effort." In physics, none counts as work.


3. Energy — the capacity to do work

Energy is what a body needs to be able to do work. If a body can do work, it has energy. SI unit: same as work, joule (J).

Forms of energy (preview)

  • Mechanical (kinetic + potential).
  • Thermal (heat).
  • Chemical (in food, fuel, batteries).
  • Electrical (in moving charges, current).
  • Light / radiant (in EM waves).
  • Sound (in vibrating media).
  • Nuclear (in atomic nuclei).

Class 9 focuses on mechanical energy in detail.


4. Kinetic energy — energy of motion

Energy possessed by a body due to its motion.

Derivation

A body of mass at rest is acted on by force to accelerate it to velocity over a distance . The work done equals the kinetic energy gained.

From the equation of motion: , with : , so .

Work done: .

KE is a scalar. SI unit: joule.

Properties

  • KE is always (because of the square).
  • KE depends on mass and velocity. A doubled mass doubles KE. A doubled velocity QUADRUPLES KE (because of ).
  • KE is the SAME regardless of direction of motion (scalar). Two cars moving north and south at the same speed have the same KE.

Example

A 1000 kg car moving at 20 m/s:

That's the energy stored in the car's motion. To bring it to rest, brakes must do 200 kJ of negative work (converting that KE to heat, sound, friction).


5. Work-energy theorem

The work done on a body equals the change in its kinetic energy.

This is one of the most useful results in mechanics. Why?

Many problems give you mass, initial speed, final speed and ask about distance — without explicitly providing acceleration. Use + the fact to bypass acceleration entirely.

Example: a 5 kg block moving at 10 m/s is brought to rest by a 25 N braking force. Distance over which it stops?

By work-energy theorem: .


6. Potential energy — energy of position/configuration

Energy stored in a body due to its position or shape.

Gravitational potential energy

A body of mass raised through height above the ground gains potential energy:

This is the work done against gravity to lift the body. When the body falls, PE converts to KE.

Other forms of PE

  • Elastic PE in a stretched/compressed spring: (Class 11).
  • Chemical PE in a stretched chemical bond.
  • Electrostatic PE between two charges.

Reference level matters

PE is defined relative to a chosen ZERO reference (often the ground). The same body at the same height has different PE values measured from different references — but DIFFERENCES in PE (which is what matters physically) are the same.


7. Conservation of mechanical energy

For a body moving under gravity alone (no friction, no air resistance):

This is the law of conservation of mechanical energy — a special case of the more general law of conservation of energy.

A falling object — energy snapshots

A 1 kg ball is dropped from a height of 20 m. Track its energy at three points (g = 10 m/s²).

At height 20 m (just released):

  • (at rest)
  • Total = 200 J

At height 10 m (halfway down):

  • Velocity from
  • Total = 200 J ✓

At the ground ():

  • Total = 200 J ✓

Total mechanical energy is constant. As PE decreases, KE increases by exactly the same amount.


8. Law of conservation of energy

Energy can neither be created nor destroyed; it can only be transformed from one form to another. Total energy of an isolated system is constant.

When mechanical energy seems to disappear (e.g., a bouncing ball gradually stops), it doesn't actually vanish — it converts to heat (friction), sound (vibration), and deformation. Total energy is always conserved.

Energy transformations in real life

  • Pendulum: alternates between KE (at bottom) and PE (at top). Friction at the pivot + air resistance slowly convert it to heat. Pendulum eventually stops.
  • Falling object on a spring: KE → elastic PE → KE → ... (with damping due to friction).
  • Hydroelectric dam: PE of water at top → KE of falling water → KE of turbine → electric energy → light/heat/motion.
  • You eating food: chemical PE in food → ATP (chemical) → mechanical (muscle contraction) + heat (metabolism).

The Sun → photosynthesis (chemical) → food → eat → ATP → motion. The energy you spend doing pushups originally came from the Sun, fixed by plants billions of years ago for fossil fuels (or seconds ago for fresh food).


9. Power — rate of doing work

How FAST work is done.

SI unit: watt (W) = J/s.

  • A 100-watt bulb consumes 100 J of electrical energy every second.
  • A typical human at rest dissipates ~100 W as heat (like a light bulb).
  • A microwave: ~1000 W. A car engine: ~75,000 W (100 horsepower).

Average vs instantaneous power

Average power . Instantaneous power = (force × instantaneous velocity, when is constant).

Commercial unit of energy — the kilowatt-hour

Electricity bills are charged in kilowatt-hours (kWh) because joules are too small.

One unit of electricity on your bill = 1 kWh = the energy used by a 1 kW heater running for 1 hour.

Example

A 60-watt bulb runs for 5 hours. How many units of electricity does it consume?

Power = 60 W = 0.06 kW. Time = 5 h. Energy = P × t = 0.06 × 5 = 0.3 kWh.

That's 0.3 units. At Rs. 5 per unit (typical residential rate), the cost is Rs. 1.50.


10. Worked example — pendulum complete cycle

A 1 kg pendulum bob is released from a height of 0.5 m above its lowest point. Find: (a) Its KE at the lowest point. (b) Its speed at the lowest point. (c) The height it would reach on the other side (ignoring friction).

(g = 10 m/s²)

Step 1 — PE at the highest point = .

Step 2 — At the lowest point, all PE has converted to KE. .

Step 3 — Find velocity from KE. .

Step 4 — On the other side, all KE converts back to PE. .

So the pendulum rises to the SAME height on the other side. Energy is conserved.

(In reality, friction at the pivot + air resistance gradually reduce the swing.)


11. Closing thought

You started with a simple, almost philosophical definition of work as "displacement in the direction of force." Three chapters later, this work-energy framework explains:

  • Why your car needs 4× the braking distance at twice the speed (KE ∝ v²).
  • Why hydroelectric dams generate immense power (huge mass × big height drop).
  • Why a small bullet can do massive damage (high KE despite low mass, because of ).
  • Why electricity bills charge in kWh, not joules.
  • Why total energy of the universe has been constant since the Big Bang.

Work and energy is the most CONCEPTUAL chapter of Class 9 physics — and the one that pays the most dividends in later studies. Master conservation of energy and most subsequent physics looks easy.

Key formulas & results

Everything you need to memorise, in one card. Screenshot this for revision.

Work done
W = F × s (force parallel to displacement)
SI unit: joule (J). If F perpendicular to s, W = 0.
Negative work
W = −F × s (force opposite to displacement)
Friction, braking, retarding force.
Kinetic energy
KE = ½ m v²
Scalar, always ≥ 0. Doubles v → 4× KE.
Gravitational PE
PE = m g h
Relative to chosen reference. h is height above reference.
Work-energy theorem
W_net = ΔKE = ½m(v² − u²)
Most useful in 'no time given' problems.
Conservation of mech. energy
KE + PE = constant (no friction)
Sum is conserved throughout the motion.
Conservation of energy (general)
Total energy of an isolated system is constant
Energy can change form but never be created or destroyed.
Power
P = W / t = F × v (for constant F)
SI unit: watt (W) = J/s.
Commercial energy
1 kWh = 3.6 × 10⁶ J
1 kWh = 1 unit on electricity bills.
⚠️

Common mistakes & fixes

These are the exact errors that cost students marks in board exams. Read them once, save yourself the trouble.

WATCH OUT
Saying 'I worked hard reading a book — that's work in physics'
No displacement of the book → ZERO work on the book. Physics work requires force × displacement in that force's direction.
WATCH OUT
Saying KE depends linearly on velocity
KE = ½mv². Doubling v gives 4× KE. Tripling v gives 9× KE. This is why braking distance scales as v².
WATCH OUT
Forgetting that PE = mgh is a RELATIVE quantity
PE depends on the chosen reference level (often the ground). The same body at the same height has different PE values for different references. ΔPE is what's physically meaningful.
WATCH OUT
Using m in grams instead of kg in KE = ½mv²
SI requires kg. KE in joules requires m in kg, v in m/s. Otherwise you'll be off by 1000×.
WATCH OUT
Saying total energy decreases over time in real systems
Mechanical energy decreases due to friction, but the 'lost' energy converted to heat/sound. Total energy is conserved when ALL forms are counted.
WATCH OUT
Confusing work and power
Work = total energy transferred (joules). Power = rate of energy transfer (watts = J/s). A bulb consuming '60 W' has POWER 60 W; over 1 hr it does 60 × 3600 = 216,000 J of work.
WATCH OUT
Confusing kWh and kW
kW = power (rate). kWh = energy = power × time. A '1 kW' heater running for 2 hours uses 2 kWh.

Practice problems

Try each one yourself before tapping "Show solution". Active recall > rereading.

Q1EASY· Definition
Define work and state its SI unit.
Show solution
Step 1 — Define. Work is done when a force acts on a body and produces a displacement in the direction of the force. Symbolic: W = F × s. Step 2 — SI unit. joule (J), where 1 J = 1 N × 1 m = 1 kg·m²/s². ✦ Answer: Work = force × displacement (in the direction of the force). SI unit: joule.
Q2EASY· KE
Find the kinetic energy of a 2 kg object moving at 10 m/s.
Show solution
Step 1 — KE = ½mv². = ½ × 2 × 10² = ½ × 2 × 100 = 100 J. ✦ Answer: 100 J.
Q3EASY· PE
A 5 kg object is raised to a height of 3 m. Find its potential energy. (g = 10 m/s²)
Show solution
Step 1 — PE = mgh = 5 × 10 × 3 = 150 J. ✦ Answer: 150 J.
Q4EASY· Zero work
Give two examples where the force applied on an object does zero work.
Show solution
Step 1 — Recall: work = 0 if (i) no displacement OR (ii) force perpendicular to displacement. Step 2 — Examples. (i) Pushing a wall that doesn't move: Force applied, but no displacement → W = 0. (ii) Carrying a suitcase while walking on a horizontal floor: Lifting force is vertical; motion is horizontal → force perpendicular to displacement → W = 0 on the suitcase. (Alternative) (iii) Satellite orbiting in a perfect circle: gravity points to centre (perpendicular to motion) → W = 0 by gravity. Energy doesn't change → orbit speed constant. ✦ Answer: (i) Pushing a wall (no displacement); (ii) Carrying a suitcase horizontally (force perpendicular to motion).
Q5EASY· Power
A man lifts a load of 20 kg through a height of 5 m in 10 s. Find the work done and his power. (g = 10 m/s²)
Show solution
Step 1 — Find work. W = F × s = mg × h = 20 × 10 × 5 = 1000 J. Step 2 — Find power. P = W / t = 1000 / 10 = 100 W. ✦ Answer: Work = 1000 J. Power = 100 W. A typical adult can sustain ~ 100 W of mechanical power over an hour or two. Athletes peak at 500–1500 W for short bursts.
Q6MEDIUM· Work-energy
A 2 kg ball moving at 5 m/s is brought to rest by a force of 20 N. How far does it travel before stopping?
Show solution
Step 1 — Use work-energy theorem. W = ΔKE. Initial KE = ½ × 2 × 5² = 25 J. Final KE = 0. W = 0 − 25 = −25 J (negative because the force decelerates the body). Step 2 — Relate to F × s. Braking force F = 20 N (opposite to motion). W = −F × s ⇒ −25 = −20 × s ⇒ s = 1.25 m. ✦ Answer: 1.25 m. Work-energy theorem shortcut: avoided calculating acceleration explicitly.
Q7MEDIUM· Conservation
A ball of mass 0.5 kg is dropped from a height of 10 m. Find its kinetic energy and velocity just before it hits the ground. (g = 10 m/s²)
Show solution
Step 1 — Use conservation of mechanical energy. At top: PE = mgh = 0.5 × 10 × 10 = 50 J. KE = 0. At bottom: PE = 0. KE = total energy. KE_bottom = 50 J. Step 2 — Find velocity. KE = ½mv² = 50 ⇒ ½ × 0.5 × v² = 50 ⇒ v² = 200 ⇒ v ≈ 14.14 m/s. ✦ Answer: KE just before impact = 50 J. Velocity ≈ 14.14 m/s. Verification with v² = 2gh: 2 × 10 × 10 = 200 ⇒ v ≈ 14.14 m/s. ✓
Q8MEDIUM· Power units
An electric bulb of 100 W is used for 10 hours daily. Calculate the energy consumed in 30 days in (a) joules, (b) kilowatt-hours.
Show solution
Step 1 — Total time in 30 days. t = 30 × 10 = 300 hours. Step 2 — Energy in kWh. E = P × t = 0.1 kW × 300 h = 30 kWh. Step 3 — Energy in joules. 1 kWh = 3.6 × 10⁶ J. E = 30 × 3.6 × 10⁶ = 1.08 × 10⁸ J. ✦ Answer: (a) 1.08 × 10⁸ J. (b) 30 kWh = 30 'units'.
Q9MEDIUM· Negative work
A ball thrown upward decelerates from 20 m/s to 0 m/s while rising a height of 20 m. Calculate (a) the work done by gravity on the ball, (b) the change in its kinetic energy. (m = 1 kg, g = 10 m/s²)
Show solution
Step 1 (a) — Force of gravity is downward; displacement is upward (opposite directions). W_gravity = −F × s = −mg × h = −1 × 10 × 20 = −200 J. Step 2 (b) — Change in KE. Initial KE = ½ × 1 × 20² = 200 J. Final KE = 0. ΔKE = 0 − 200 = −200 J. Step 3 — Note that W = ΔKE = −200 J. The work-energy theorem holds: gravity took 200 J of KE from the ball (which went into PE). ✦ Answer: (a) W_gravity = −200 J. (b) ΔKE = −200 J. They are equal — exactly as predicted by the work-energy theorem.
Q10MEDIUM· Force ratio
Two bodies A and B of masses 1 kg and 4 kg have the same kinetic energy. Find the ratio of their velocities.
Show solution
Step 1 — Same KE. ½ m_A v_A² = ½ m_B v_B² m_A × v_A² = m_B × v_B². Step 2 — Substitute. 1 × v_A² = 4 × v_B² v_A² / v_B² = 4 v_A / v_B = 2. ✦ Answer: v_A : v_B = 2 : 1. The lighter body needs to move FASTER to have the same KE.
Q11HARD· Combined
A 100 g cricket ball moving horizontally at 30 m/s is brought to rest by a fielder's hands in 0.1 s. Calculate (a) the average force exerted by the fielder's hands, (b) the work done by the hands.
Show solution
Step 1 — Convert mass. m = 100 g = 0.1 kg. Step 2 (a) — Use impulse-momentum. F × t = m × Δv ⇒ F × 0.1 = 0.1 × 30 = 3 ⇒ F = 30 N. Step 3 (b) — Use work-energy theorem. Initial KE = ½ × 0.1 × 30² = ½ × 0.1 × 900 = 45 J. Final KE = 0. W_hands = ΔKE = 0 − 45 = −45 J. The hands do −45 J of work on the ball (taking 45 J of KE away). Equivalently, the BALL does +45 J of work on the hands. ✦ Answer: (a) Force = 30 N. (b) Work done by hands on ball = −45 J (negative; hands absorbed 45 J of KE).
Q12HARD· Free fall energy
A stone of mass 2 kg is thrown vertically upward with an initial velocity of 20 m/s. Find (a) the maximum height reached, (b) the total energy at any point during the motion. (g = 10 m/s²)
Show solution
Step 1 (a) — Use v² = u² − 2gh at top (v = 0). 0 = 400 − 20h ⇒ h = 20 m. Step 2 (b) — Total mechanical energy. At the start (h = 0): KE = ½ × 2 × 20² = 400 J. PE = 0. Total = 400 J. At the top (h = 20): KE = 0. PE = mgh = 2 × 10 × 20 = 400 J. Total = 400 J. ✓ At any intermediate point: KE + PE = 400 J (no air resistance). Step 3 — Note conservation. As the stone rises, KE → PE. As it falls, PE → KE. Total never changes (frictionless). ✦ Answer: (a) 20 m; (b) 400 J — constant throughout the motion.
Q13HARD· Electricity bill
A household uses 5 bulbs of 60 W each for 5 hours a day, 1 fan of 75 W for 8 hours a day, and a fridge of 100 W running continuously. Calculate the daily and monthly (30 days) electricity consumption in kWh, and the cost at Rs. 6 per unit.
Show solution
Step 1 — Bulbs. 5 × 60 = 300 W × 5 h = 1500 Wh = 1.5 kWh per day. Step 2 — Fan. 75 W × 8 h = 600 Wh = 0.6 kWh per day. Step 3 — Fridge. 100 W × 24 h = 2400 Wh = 2.4 kWh per day. Step 4 — Daily total. 1.5 + 0.6 + 2.4 = 4.5 kWh/day. Step 5 — Monthly total. 4.5 × 30 = 135 kWh. Step 6 — Cost. 135 × 6 = Rs. 810. ✦ Answer: Daily consumption = 4.5 kWh. Monthly = 135 kWh. Monthly bill = Rs. 810.
Q14HARD· HOTS
An object of mass 40 kg is raised through a height of 5 m on the moon. Compare the work done with that on Earth. Also, when the object is dropped from this height, find its velocity just before hitting the ground (a) on Earth, (b) on Moon. (g_E = 10 m/s², g_M = 1.6 m/s²)
Show solution
Step 1 — Work done to lift an object = mgh. On Earth: W_E = 40 × 10 × 5 = 2000 J. On Moon: W_M = 40 × 1.6 × 5 = 320 J. Ratio: W_E / W_M = 10/1.6 ≈ 6.25. Lifting on Moon takes only 1/6.25 = 16 % of the Earth's work. Step 2 — Velocity on dropping. PE at height = KE at ground. ½ m v² = mgh ⇒ v = √(2gh). (a) Earth: v = √(2 × 10 × 5) = √100 = 10 m/s. (b) Moon: v = √(2 × 1.6 × 5) = √16 = 4 m/s. Step 3 — Why same conclusion? Less work to lift on Moon → less PE → less KE on landing → smaller v. ✦ Answer: Lifting work: Earth 2000 J, Moon 320 J (factor 6.25). Landing velocity: Earth 10 m/s, Moon 4 m/s (factor 2.5).
Q15HARD· HOTS
Why is the kinetic energy of a body always positive while its potential energy can be positive, negative or zero?
Show solution
Step 1 — KE formula. KE = ½mv². Mass is always positive. v² is the square of velocity, always ≥ 0. Hence KE ≥ 0 always. KE can be zero (body at rest) or positive (body moving); never negative. Step 2 — PE formula. PE = mgh. m and g are positive. h is height ABOVE the chosen reference level. • h > 0 (above reference): PE > 0. • h = 0 (at reference): PE = 0. • h < 0 (below reference): PE < 0 (mathematically allowed; physically real — a basement is at negative PE relative to the ground floor). Step 3 — Practical example. A miner at 100 m below ground has PE = −100 mg J relative to the surface. Negative because you need to do positive work AGAINST gravity to bring her back up. ✦ Answer: KE is always positive because it depends on v² (always ≥ 0). PE depends on height ABOVE the reference; can be negative if the body is below the reference. The reference is arbitrary, and so is the sign — only DIFFERENCES in PE matter physically.

5-minute revision

The whole chapter, distilled. Read this the night before the exam.

  • Work: W = F × s (force in direction of displacement). SI: joule (J).
  • Three zero-work cases: no force / no displacement / force perpendicular to displacement.
  • Negative work: force opposite to displacement (friction, braking).
  • Energy = capacity to do work. SI: joule.
  • Kinetic energy: KE = ½mv². Scalar, always ≥ 0. Doubling v gives 4× KE.
  • Gravitational PE: PE = mgh. Reference-level-dependent. Can be negative.
  • Work-energy theorem: W_net = ΔKE. Bypasses needing to compute acceleration.
  • Conservation of mechanical energy: KE + PE = constant (in absence of friction).
  • Conservation of energy (general): total energy of an isolated system is constant. Energy transforms; never created or destroyed.
  • Power: P = W/t (watts). 1 W = 1 J/s.
  • Commercial unit: 1 kWh = 3.6 × 10⁶ J = '1 unit' on electricity bills.

Questions students ask

The real ones — pulled from the Q&A community and tutor sessions.

The PHYSICAL work on the suitcase is zero (force vertical, displacement horizontal). The fatigue comes from continuously activating your muscles to maintain the upward force (against gravity), which is BIOCHEMICAL work in your muscles — not mechanical work on the suitcase. Physics work ≠ effort.

Yes — a ball held at the top of a building. It's at rest (KE = 0) but has gravitational PE due to height. The moment you release it, PE → KE.

Mechanical energy = KE + PE. It's conserved only when no non-conservative forces (friction, air drag) act. Energy in general is conserved across ALL forms — including heat, sound, etc. that friction generates. Friction converts KE to heat; total energy is still constant, just not all of it remains mechanical.

Different physical concepts. KE measures the 'cost' to bring a body to rest — depends on (force × distance), and distance grows with v² when stopping under uniform deceleration. Momentum measures 'quantity of motion' — depends on (force × time), and time grows with v. Different integrations give different powers of v.

Classically, no — KE = ½mv² grows without limit as v grows. But Einstein's special relativity (Class 11) caps the speed at c (the speed of light). As v approaches c, the body's KE grows toward infinity — meaning infinite energy would be needed to reach c. Hence c is the universal speed limit.

Convenience. A typical home uses 100–1000 kWh per month. The same in joules would be 3.6 × 10⁸ to 3.6 × 10⁹ J — unwieldy. kWh's chosen size matches typical electrical appliance consumption.
Verified by the tuition.in editorial team
Last reviewed on 18 May 2026. Written and reviewed by subject-matter experts — read about our process.
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