By the end of this chapter you'll be able to…

  • 1Identify the x-axis, y-axis, origin and four quadrants of the Cartesian plane
  • 2Read off the coordinates of any point shown on a graph
  • 3Plot a point on the plane given its (x, y) coordinates
  • 4Decide which quadrant a point lies in from the signs of its coordinates
  • 5Identify points lying on the axes and explain why they don't belong to any quadrant
  • 6Compute the image of a point reflected across either axis or the origin
  • 7Compute horizontal and vertical distances between points sharing an axis-aligned coordinate
  • 8Plot four points and recognise the rectangle/square/rhombus/triangle they form
  • 9Find a missing vertex of a rectangle given three vertices
  • 10Connect Cartesian geometry to real-world applications like GPS, screens, chess and robotics
💡
Why this chapter matters
Coordinate Geometry is the bridge between algebra and geometry — turning shapes into equations and back. Every line, curve and shape you'll graph from Class 10 onwards starts here. The Cartesian plane is also the foundation of GPS, computer graphics, robotics, ML, and every chart you'll ever read.

Coordinate Geometry — Class 9 (CBSE)

If you understand this short chapter deeply, every graph you ever draw — straight lines in Class 10, parabolas in Class 11, electric fields in Class 12, neural networks in college — will feel obvious. Get it shaky here and you fight it forever.


1. A 17th-century Frenchman and a fly

It's 1637. René Descartes — soldier, philosopher, late-riser — is lying in bed watching a fly walk across the ceiling. The fly's path is complicated. Words can't describe its position. But Descartes has an idea:

Pick a corner. Measure the fly's distance from one wall, then the other. Two numbers — that's its address.

That insight — that any point in a plane can be described by a pair of numbers — is the foundation of coordinate geometry (also called analytic geometry or, in honour of Descartes, Cartesian geometry). It quietly fused algebra and geometry into one subject and made calculus, physics and modern engineering possible. Every map app, every video game, every spreadsheet chart works because of this idea.

You're going to learn it in about 35 minutes.


2. The big picture — one sentence

Coordinate geometry turns shapes into equations and equations into shapes.

That's the whole game. In Class 9 you learn the language — how to write addresses for points. From Class 10 onwards you'll use this language to describe lines, circles, parabolas, even the orbits of planets.


3. The Cartesian system — building the plane

3.1 Two perpendicular number lines

Take a horizontal number line and a vertical number line. Place them so they cross at right angles, with both zeros at the crossing point.

  • The horizontal line is the x-axis.
  • The vertical line is the y-axis.
  • Their crossing point is the origin, written .

Together they form the Cartesian plane (sometimes called the xy-plane). Every point in this flat plane now has a unique two-number address.

3.2 Ordered pairs — order matters

A point's address is written as an ordered pair .

  • — the abscissa — is the signed distance from the y-axis. Right is positive, left is negative.
  • — the ordinate — is the signed distance from the x-axis. Up is positive, down is negative.

The word ordered is important. and are different points. Always read along the corridor, then up the stairs — x first, then y.

Why this convention? Algebraic variables are usually listed alphabetically. x before y mirrors left-right before up-down, which mirrors how we write and read English. Every formula in higher math depends on this order. Don't fight it.

3.3 The four quadrants

The two axes slice the plane into four regions called quadrants, numbered anti-clockwise starting from the top-right:

QuadrantPositionSign of Sign of Example
Itop-right
IItop-left
IIIbottom-left
IVbottom-right

Mnemonic — All Students Take Calculus: In Quadrant I, All trig values are positive. In II, only Sin. In III, only Tan. In IV, only Cos. (You'll thank yourself in Class 11.)

3.4 Points on the axes — the "homeless" cases

A point on the x-axis has . Example: , , the origin . A point on the y-axis has . Example: , .

These points do not belong to any quadrant. They sit on the boundary. This is the #1 question students get wrong in exams. Don't be that student.


4. Plotting points — step by step

To plot :

  1. Start at the origin .
  2. First coordinate — x = 3. Move 3 units right along the x-axis. (Positive → right.)
  3. Second coordinate — y = −2. From your current position, move 2 units down, parallel to the y-axis. (Negative → down.)
  4. Mark the point. Label it.

The point is in Quadrant IV because .

Teacher's tip. In an exam, always label your axes (with arrows and units), the origin, and every point you plot. Unlabelled diagrams lose half-marks even when the work is right.


5. Reading coordinates from a graph

Given a point on the plane and asked "what are its coordinates?":

  1. Drop a perpendicular from the point to the x-axis. Where it meets is the x-coordinate.
  2. Drop a perpendicular to the y-axis. Where it meets is the y-coordinate.
  3. Write them as the ordered pair .

If the point sits on the gridlines exactly, read off the integer values. If between, estimate the nearest tenth.


6. Reflections — preview of transformations

A reflection is a flip across a line (the "mirror"). For each axis:

  • Reflection across the x-axis: — the x stays, the y flips sign.
  • Reflection across the y-axis: — the y stays, the x flips.
  • Reflection through the origin: — both flip.

Worked example. Reflect the point across the y-axis. Which quadrant does the image lie in?

Applying : the image is . Both coordinates are negative → Quadrant III.

Why this matters. In Class 10 you'll use reflections to derive the equations of perpendicular bisectors. In Class 12 they're the entry point to linear transformations and matrices. Every reflection you draw now pays off later.


7. Distance along an axis (Class 9 scope)

The full distance formula is a Class 10 topic. But Class 9 still expects you to handle horizontal and vertical distances:

  • Horizontal distance between and (same y) = .
  • Vertical distance between and (same x) = .

The absolute-value bars matter — distance is never negative.

Worked example. Find the distance between and .

Both points have , so they lie on the horizontal line . Distance units.


8. Shapes formed by points — the bridge to geometry

Plot four well-chosen points, join them in order, and a shape appears. This is where coordinate geometry starts to feel geometric.

Worked example. Plot . Name the figure.

  • and share → joined by a horizontal segment of length .
  • and share → another horizontal segment of length .
  • and share → vertical segment of length .
  • and share → vertical segment of length .

Two pairs of equal, parallel sides; all angles rectangle of length 6 and breadth 4. Area square units. Perimeter units.

Common follow-up exam question. "Is it a square?" — No. A square needs all four sides equal. Here length ≠ breadth.


9. Six worked exam examples

Example 1 — Quadrant identification (1 mark)

In which quadrant does lie? Quadrant II.

Example 2 — Axis recognition (1 mark)

Where does lie? on the y-axis, 6 units below the origin. Not in any quadrant.

Example 3 — Plotting + naming (3 marks)

Plot . What figure do they form? The four points lie on the axes. Joining them gives a rhombus (diagonals along the axes, lengths 6 and 8). It's not a square because the diagonals are unequal.

Example 4 — Reflection chain (2 marks)

Reflect first across the x-axis, then across the y-axis. Final coordinates? First reflection: . Second reflection: . Final: — Quadrant II.

Example 5 — Distance + shape (3 marks)

and . Find . Same . units.

Example 6 — HOTS (4 marks)

Three vertices of a rectangle are . Find the fourth vertex and the area. The given three give us sides along (vertical) and (horizontal).

  • Vertical side length: .
  • Horizontal side length: .
  • Fourth vertex shares with and with .
  • Area = sq units. (It's a square!)

10. Common pitfalls — the seven exam-killers

  1. Swapping x and y. Plotting as if it were . → Always read x first.
  2. Assigning points on axes to a quadrant. is on the y-axis, not in Quadrant I or II.
  3. Forgetting the sign of the second coordinate. goes DOWN from x-axis, not up.
  4. Mismatched scales on the two axes. Without equal scales, a square looks like a rectangle. Use the same unit on both axes unless the question says otherwise.
  5. Unlabelled diagrams. No arrows, no origin, no axis names → mark deduction.
  6. Reflection sign errors. -axis reflection flips , not . Re-derive on rough first if unsure.
  7. Distance without absolute value. Distance can never be negative. , always.

11. Real-world coordinate geometry

The Cartesian plane isn't a textbook abstraction — it's everywhere.

  • Google Maps & GPS. Latitude and longitude are y and x coordinates on a (mostly) spherical Cartesian system. The blue dot showing where you are is literally an pair, refreshed every second.
  • Computer screens. Every pixel on this screen has an address. (Annoyingly, the y-axis points down in screen coordinates — a convention from old CRT TVs.)
  • Chess. "Knight to e4" is just an ordered pair: column , row .
  • Spreadsheets. Cell B7 is the point in Excel's coordinate system.
  • Robotics. A factory robot arm picks objects at specific locations.
  • Sports analytics. Cricket pitch maps, basketball shot charts, football heatmaps — all use coordinates.
  • Medical imaging. An MRI scan locates a tumour by its position in the body.

When you plot a point in your notebook, you're using the same machinery that lands rockets on Mars.


12. Beyond NCERT — stretch problems

These won't be in your board exam, but if you can solve them you've mastered the chapter and you're set for olympiads and JEE Foundation.

Stretch 1 — Olympiad style

The points are three corners of a rectangle. A bug starts at , walks along the perimeter at 1 unit/sec. Where (which coordinates) is the bug at seconds?

Solution. Perimeter . At : walked 11 units. takes 4s ( at ). takes 3s ( at ). takes 4s, so at the bug has walked 4 units of CD → at exactly. Answer: .

Stretch 2 — PISA-style real-world

A drone is at km from a school. It reflects its position across the x-axis to drop a payload, then flies to the reflection of the new position across the y-axis. Where does it end up?

Solution. . Quadrant III, 2 km west and 5 km south of the school.

Stretch 3 — Counting

How many points with integer coordinates lie strictly inside a rectangle with vertices ?

Solution. "Strictly inside" excludes boundary. Integer x's strictly between 0 and 5: — 4 values. Integer y's strictly between 0 and 3: — 2 values. Total = 8 points.


13. CBSE exam blueprint for this chapter

Question typeMarksTypical questionTime to spend
Very-short-answer (VSA)1Quadrant of a given point; coordinate of a point on an axis30 sec
Short-answer-I (SA-I)2Plot 4 points and identify the figure2 min
Short-answer-II (SA-II)3Reflections, distance along an axis, mini-proof4–5 min
Long-answer (LA)4HOTS — vertex-finding, multi-step constructions6–8 min

Total marks this chapter typically carries: 4–5 / 80 in the Class 9 final. Not a heavy weighter, but the concepts are heavily reused in Class 10 (where Coordinate Geometry jumps to 6–8 marks with distance & section formulas).

Three exam-day strategies:

  1. Always start with a labelled diagram. Even for a 1-mark question. Markers love them; they also catch your own sign errors.
  2. Show working for reflections. Write explicitly, then substitute. One mark for the rule, one for the calculation.
  3. Read the question twice. "Reflection across the y-axis" and "reflection across the x-axis" sound similar and are tested often. A 2-second re-read saves a 2-mark mistake.

14. NCERT exercise walkthrough

The chapter has two short exercises in the latest NCERT (2024–25).

Exercise 3.1 — 2 questions on naming axes, quadrants and identifying coordinates from a description.

Exercise 3.2 — 2 questions on reading coordinates from a graph and plotting given points.

Both are covered by the worked examples and stretch problems above. For the model NCERT solutions with diagrams, open the chapter practice quiz — the questions are exact NCERT-style with step-marked solutions.


15. Connections — what this chapter prepares you for

  • Class 10, Coordinate Geometry — distance formula , section formula, area of a triangle from coordinates.
  • Class 10, Linear Equations in Two Variables — every linear equation becomes a line on the plane you just learned to draw.
  • Class 11, Straight Lines — slope, angle, intercept form.
  • Class 11, Conic Sections — circles, parabolas, ellipses are all described as pairs satisfying an equation.
  • Class 12, Vectors and 3D Geometry — add a axis and you have 3D space; everything you learned here generalises.

In Linear Equations in Two Variables (your next chapter) you'll plot your first lines on this plane.


16. 60-second recap

  • Two perpendicular axes (x horizontal, y vertical) crossing at the origin .
  • Ordered pair — x first, y second.
  • Four quadrants: I (+,+), II (−,+), III (−,−), IV (+,−).
  • Points on axes belong to NO quadrant.
  • Reflections: across x flips y, across y flips x, across origin flips both.
  • Distance along an axis = or .
  • Always label axes, origin and points in exam diagrams.

You've now seen everything CBSE will test, plus enough beyond-syllabus material to walk into any school's coordinate geometry round confidently. Take the practice quiz and the flashcard deck before moving on.

Key formulas & results

Everything you need to memorise, in one card. Screenshot this for revision.

Cartesian coordinate
(x, y) — abscissa x, ordinate y
Order matters: x is horizontal, y is vertical.
Quadrant I
x > 0, y > 0
Top-right.
Quadrant II
x < 0, y > 0
Top-left.
Quadrant III
x < 0, y < 0
Bottom-left.
Quadrant IV
x > 0, y < 0
Bottom-right.
Point on x-axis
(a, 0)
y = 0; not in any quadrant.
Point on y-axis
(0, b)
x = 0; not in any quadrant.
Reflection in x-axis
(x, y) → (x, −y)
y flips sign.
Reflection in y-axis
(x, y) → (−x, y)
x flips sign.
Reflection in origin
(x, y) → (−x, −y)
Both flip; same as 180° rotation about O.
Horizontal distance
d = |x₂ − x₁| (same y)
Distance is always non-negative.
Vertical distance
d = |y₂ − y₁| (same x)
Distance is always non-negative.
⚠️

Common mistakes & fixes

These are the exact errors that cost students marks in board exams. Read them once, save yourself the trouble.

WATCH OUT
Confusing the abscissa with the ordinate
x always comes first — left-right; y comes second — up-down. Remember 'along the corridor, up the stairs'.
WATCH OUT
Saying a point on the y-axis is in Quadrant II
Points ON an axis are NOT in any quadrant. (0, 5) lies on the y-axis only.
WATCH OUT
Plotting (−3, 4) in Quadrant IV
Negative x means left of the y-axis; positive y means above the x-axis. (−3, 4) sits in Quadrant II.
WATCH OUT
Mixing up x-axis and y-axis reflections
Reflection across the x-axis flips y. Mantra: 'reflect across X → X stays, Y flips'.
WATCH OUT
Forgetting absolute value in distance
Distance can never be negative. Always wrap with |…|: |x₂ − x₁|, not x₂ − x₁.
WATCH OUT
Using unequal scales on the two axes
Unless the question says otherwise, choose the same unit length on both axes — a square should look like a square.
WATCH OUT
Unlabelled diagrams in exams
Always label axes with arrows, mark the origin O, and tag every plotted point. Diagram alone is worth 1 mark in many questions.

Practice problems

Try each one yourself before tapping "Show solution". Active recall > rereading.

Q1EASY· Quadrant ID
In which quadrant does the point (−5, −2) lie?
Show solution
Step 1 — Read off the signs of the coordinates. x = −5 → negative. y = −2 → negative. Step 2 — Match to the quadrant table. Both negative → Quadrant III (bottom-left). ✦ Answer: Quadrant III. Why? Quadrant III is defined as the region where both x and y are negative. A quick mental check: bottom-left of the plane.
Q2EASY· Quadrant ID
In which quadrant does the point (3, −7) lie?
Show solution
Step 1 — Signs. x = +3 (positive), y = −7 (negative). Step 2 — Match the table. Positive x, negative y → Quadrant IV (bottom-right). ✦ Answer: Quadrant IV. Mental picture: from the origin, move 3 units right, then 7 units down — you land in the bottom-right region.
Q3EASY· Quadrant ID
In which quadrant does the point (−8, 4) lie?
Show solution
Step 1 — Signs. x = −8 (negative), y = +4 (positive). Step 2 — Match the table. Negative x, positive y → Quadrant II (top-left). ✦ Answer: Quadrant II. Quadrant II is anti-clockwise from Quadrant I; it covers the top-left of the plane.
Q4EASY· Axis ID
Where does the point (0, −9) lie?
Show solution
Step 1 — Check whether either coordinate is zero. x = 0, y = −9. The x-coordinate is zero. Step 2 — Recall the rule. Any point with x = 0 lies on the y-axis. Any point with y = 0 lies on the x-axis. Points on the axes do NOT belong to any quadrant. Step 3 — Locate it. y = −9 means 9 units below the origin. ✦ Answer: On the y-axis, 9 units below the origin. Common mistake: students often assign this to 'Quadrant III' because y is negative. It is on the boundary, not in any quadrant.
Q5EASY· Axis ID
Where does the point (4, 0) lie?
Show solution
Step 1 — Check coordinates. x = 4, y = 0. The y-coordinate is zero. Step 2 — Apply the rule. y = 0 means the point lies on the x-axis. Step 3 — Position. x = +4 means 4 units to the right of the origin. ✦ Answer: On the x-axis, 4 units to the right of the origin. Not in any quadrant.
Q6EASY· Reflection
Reflect (3, −4) across the x-axis.
Show solution
Step 1 — Recall the reflection rule for the x-axis. Reflection across the x-axis: (x, y) → (x, −y). The x stays the same; y flips sign. Step 2 — Apply. (3, −4) → (3, −(−4)) → (3, 4). ✦ Answer: (3, 4) — Quadrant I. Verification: the original point and its image are equidistant from the x-axis (4 units), one below and one above — exactly what a mirror across the x-axis produces.
Q7EASY· Reflection
Reflect (−2, 5) across the y-axis.
Show solution
Step 1 — Recall the y-axis reflection rule. (x, y) → (−x, y). The y stays the same; x flips sign. Step 2 — Apply. (−2, 5) → (−(−2), 5) → (2, 5). ✦ Answer: (2, 5) — Quadrant I. Mnemonic: 'reflect across Y → Y stays.' The mirror's the y-axis, so the y-coordinate is unchanged.
Q8EASY· Reflection
Reflect (4, −7) through the origin.
Show solution
Step 1 — Recall the origin-reflection rule. (x, y) → (−x, −y). Both signs flip. (Reflection through the origin = 180° rotation about O.) Step 2 — Apply. (4, −7) → (−4, −(−7)) → (−4, 7). ✦ Answer: (−4, 7) — Quadrant II. Geometric check: original is in Quadrant IV (+,−); image is in Quadrant II (−,+). They sit on opposite sides of O, exactly as a 180° rotation produces.
Q9EASY· Abscissa/Ordinate
What is the ordinate of the point (6, −3)?
Show solution
Step 1 — Recall the terminology. In the ordered pair (x, y), x is the abscissa and y is the ordinate. Step 2 — Identify y in (6, −3). y = −3. ✦ Answer: Ordinate = −3. Mnemonic — 'O for ordinate, O for over (up-down)': the ordinate is the vertical coordinate.
Q10EASY· Abscissa/Ordinate
What is the abscissa of the point (−5, 8)?
Show solution
Step 1 — Terminology. Abscissa = x-coordinate (horizontal distance from y-axis, signed). Step 2 — Identify x in (−5, 8). x = −5. ✦ Answer: Abscissa = −5. Mnemonic — 'A for abscissa, A for along (left-right)': the abscissa is the horizontal coordinate.
Q11MEDIUM· Plotting
Plot the points A(2, 3), B(−2, 3), C(−2, −3), D(2, −3). Name the figure ABCD.
Show solution
Step 1 — Identify which pairs share a coordinate. A & B both have y = 3 → joined by a HORIZONTAL segment. C & D both have y = −3 → also horizontal. A & D both have x = 2 → joined by a VERTICAL segment. B & C both have x = −2 → also vertical. Step 2 — Compute side lengths. AB = |2 − (−2)| = 4 units. CD = |2 − (−2)| = 4 units. AD = |3 − (−3)| = 6 units. BC = |3 − (−3)| = 6 units. Step 3 — Check angles. All sides meet at right angles (horizontal meets vertical), so all four angles are 90°. Step 4 — Classify. Two pairs of equal, parallel sides + four right angles → rectangle. Length 6 ≠ breadth 4, so it is NOT a square. ✦ Answer: ABCD is a rectangle with length 6 and breadth 4. Area = 24 sq units, perimeter = 20 units.
Q12MEDIUM· Axis points
A point P(a, b) lies on the x-axis. What is b? Where is P if a = −7?
Show solution
Step 1 — Apply the rule for points on the x-axis. Any point on the x-axis has y-coordinate 0. Therefore b = 0. Step 2 — Substitute a = −7. P = (−7, 0). Step 3 — Locate. Negative x → left of the y-axis. P is 7 units to the LEFT of the origin, on the x-axis. ✦ Answer: b = 0; P = (−7, 0), 7 units left of the origin.
Q13MEDIUM· Distance
Find the distance between A(−3, 5) and B(7, 5).
Show solution
Step 1 — Observe that both points share the same y-coordinate. y = 5 for both → AB is a HORIZONTAL segment lying on the line y = 5. Step 2 — Use the horizontal-distance formula. d = |x₂ − x₁| (absolute value because distance is non-negative). Step 3 — Substitute. d = |7 − (−3)| = |7 + 3| = |10| = 10. ✦ Answer: AB = 10 units. Why absolute value? Without |…|, we'd get +10 in one direction and −10 in the other. Distance has no direction.
Q14MEDIUM· Distance
Find the distance between P(4, −2) and Q(4, 6).
Show solution
Step 1 — Observe the shared coordinate. Both points have x = 4 → PQ is a VERTICAL segment on the line x = 4. Step 2 — Vertical distance formula. d = |y₂ − y₁|. Step 3 — Substitute. d = |6 − (−2)| = |6 + 2| = 8. ✦ Answer: PQ = 8 units. Note: had we written 'd = 6 − (−2) = 8' without the absolute-value bars, an examiner can deduct half a mark. Always wrap with |…|.
Q15MEDIUM· Plotting + identify
Plot P(3, 0), Q(0, 4), R(−3, 0), S(0, −4). What figure do they form? Find its area.
Show solution
Step 1 — Recognise where each point lies. P(3, 0) and R(−3, 0): on the x-axis, 3 units on either side of the origin. Q(0, 4) and S(0, −4): on the y-axis, 4 units on either side of the origin. Step 2 — Join them in order PQRS. This produces a quadrilateral whose vertices are on the axes — a 'kite'-like shape sitting symmetrically about both axes. Step 3 — Use the diagonal lengths. Diagonal PR (along x-axis): length = 3 − (−3) = 6. Diagonal QS (along y-axis): length = 4 − (−4) = 8. The diagonals are PERPENDICULAR (one is x-axis, the other is y-axis) and BISECT each other (both pass through the origin which is their midpoint). Step 4 — Classify. Perpendicular diagonals that bisect each other ⇒ rhombus. Since the diagonals are UNEQUAL (6 ≠ 8), it is not a square. Step 5 — Compute area. Area of a rhombus = (1/2) × d₁ × d₂ = (1/2) × 6 × 8 = 24 sq units. ✦ Answer: PQRS is a rhombus of area 24 sq units.
Q16MEDIUM· Composite reflection
Reflect (2, −5) first across the x-axis, then across the y-axis. What are the final coordinates?
Show solution
Step 1 — First reflection (across the x-axis). Rule: (x, y) → (x, −y). (2, −5) → (2, −(−5)) → (2, 5). Step 2 — Second reflection (across the y-axis). Rule: (x, y) → (−x, y). (2, 5) → (−2, 5). ✦ Answer: Final point (−2, 5) — Quadrant II. Deeper insight: composing reflections across the x-axis and y-axis is equivalent to reflecting through the origin in one step — same as (x, y) → (−x, −y). Check: (2, −5) → (−2, 5). ✓
Q17MEDIUM· Reasoning
Without plotting, predict the quadrant of (a, b) given a > 0 and b < 0.
Show solution
Step 1 — Translate the conditions. a > 0 → x-coordinate is positive. b < 0 → y-coordinate is negative. Step 2 — Match to the quadrant table. (+, −) → Quadrant IV (bottom-right). ✦ Answer: Quadrant IV. No plotting needed — the signs alone determine the quadrant.
Q18HARD· HOTS — missing vertex
Three vertices of a rectangle are (2, 4), (2, −2), (8, −2). Find the fourth vertex and the area.
Show solution
Step 1 — Identify which sides of the rectangle are given. Two of the given vertices share x = 2 → the LEFT vertical side runs from (2, −2) to (2, 4). Two of the given vertices share y = −2 → the BOTTOM horizontal side runs from (2, −2) to (8, −2). Step 2 — Use the rectangle property: opposite sides are equal and parallel. The fourth vertex must share x with (8, −2) (so the RIGHT side is vertical, parallel to the left). The fourth vertex must share y with (2, 4) (so the TOP side is horizontal, parallel to the bottom). Therefore the fourth vertex = (8, 4). Step 3 — Compute side lengths. Vertical side: |4 − (−2)| = 6. Horizontal side: |8 − 2| = 6. Step 4 — Compute the area. Area = length × breadth = 6 × 6 = 36 sq units. ✦ Answer: Fourth vertex = (8, 4). Area = 36 sq units. Bonus insight: since length = breadth = 6, this 'rectangle' is actually a SQUARE. A square is a special rectangle. Examiners reward this observation.
Q19HARD· HOTS — counting
How many points (x, y) with integer coordinates lie strictly inside the rectangle with vertices (0, 0), (5, 0), (5, 3) and (0, 3)?
Show solution
Step 1 — Interpret 'strictly inside'. Strictly inside means excluding the boundary — points ON the rectangle's sides do NOT count. Step 2 — Range of valid x-values. The rectangle spans x = 0 to x = 5. 'Strictly inside' means 0 < x < 5. Integer x's satisfying this: x ∈ {1, 2, 3, 4} → 4 values. Step 3 — Range of valid y-values. The rectangle spans y = 0 to y = 3. 'Strictly inside' means 0 < y < 3. Integer y's satisfying this: y ∈ {1, 2} → 2 values. Step 4 — Combine using the multiplication principle. Each valid x can pair with each valid y, independently. Total = 4 × 2 = 8. ✦ Answer: 8 integer-coordinate points strictly inside the rectangle. List them (verification): (1,1), (1,2), (2,1), (2,2), (3,1), (3,2), (4,1), (4,2) — exactly 8 points. ✓ This problem previews Pick's Theorem (Class 11 Olympiad: area = interior lattice + boundary/2 − 1).
Q20HARD· Olympiad
A bug walks anti-clockwise along the perimeter of the rectangle with vertices (0, 0), (4, 0), (4, 3), (0, 3) at 1 unit/sec, starting at (0, 0). Where is the bug at t = 11 sec?
Show solution
Step 1 — Compute the perimeter. P = 2(length + breadth) = 2(4 + 3) = 14 units. The bug walks at 1 unit/sec → completes a full loop every 14 seconds. Step 2 — Distance walked in 11 seconds. d = speed × time = 1 × 11 = 11 units. Since 11 < 14, the bug has NOT completed a full loop yet. Step 3 — Trace the path anti-clockwise from (0, 0). (0,0) → (4,0): 4 units along the bottom. Cumulative time = 4 s. At t = 4, bug is at (4, 0). (4,0) → (4,3): 3 units up the right side. Cumulative time = 4 + 3 = 7 s. At t = 7, bug is at (4, 3). (4,3) → (0,3): 4 units along the top (leftward). Cumulative time = 7 + 4 = 11 s. At t = 11, bug is at (0, 3). Step 4 — Conclusion. At t = 11, the bug arrives exactly at the corner (0, 3). ✦ Answer: The bug is at (0, 3) — the top-left corner of the rectangle. Follow-up: at t = 14, the bug returns to (0, 0). At t = 28, two full loops. This is a periodic motion problem.
Q21HARD· PISA — real-world
A drone is at (2, 5) km from a school. It reflects its position across the x-axis to drop a payload, then reflects its new position across the y-axis. Find its final location.
Show solution
Step 1 — Treat the school as the origin O(0, 0). Drone starts at (2, 5): 2 km EAST and 5 km NORTH of the school. Step 2 — First reflection (across the x-axis = the East-West axis). Rule: (x, y) → (x, −y). (2, 5) → (2, −5). The drone is now 2 km EAST and 5 km SOUTH of the school. Step 3 — Second reflection (across the y-axis = the North-South axis). Rule: (x, y) → (−x, y). (2, −5) → (−2, −5). The drone is now 2 km WEST and 5 km SOUTH. Step 4 — Interpret in real-world terms. Final coordinates (−2, −5) — Quadrant III. ✦ Answer: The drone ends up 2 km WEST and 5 km SOUTH of the school, in Quadrant III. Real-world check: this is exactly how some delivery drones plan return paths — using reflection symmetry to simplify route planning.

5-minute revision

The whole chapter, distilled. Read this the night before the exam.

  • Cartesian plane = two perpendicular axes (x horizontal, y vertical) meeting at the origin O(0, 0).
  • Point = ordered pair (x, y); x is the abscissa, y is the ordinate. Order matters.
  • Quadrants — I (+, +), II (−, +), III (−, −), IV (+, −).
  • Points on the axes don't belong to any quadrant: y-axis if x = 0, x-axis if y = 0.
  • Reflections — x-axis: (x, y) → (x, −y); y-axis: (x, y) → (−x, y); origin: (x, y) → (−x, −y).
  • Distance along an axis: |x₂ − x₁| or |y₂ − y₁| — always non-negative.
  • Always label axes, origin and points in exam diagrams — easy 1 mark.
  • Bridge to Class 10: distance formula, section formula, area of triangle from coordinates.

Questions students ask

The real ones — pulled from the Q&A community and tutor sessions.

It's a convention chosen so that (x, y) matches alphabetical order and the horizontal-then-vertical reading direction. Switching would break every formula that follows from this point on.

No — the full distance formula √((x₂ − x₁)² + (y₂ − y₁)²) is a Class 10 topic. Class 9 limits itself to distances along an axis: |x₂ − x₁| or |y₂ − y₁|.

No. The origin lies on both axes simultaneously and is treated as a boundary point, just like other points on the axes.

A quadrant is one of four regions of a 2D plane. An octant is one of eight regions of 3D space (formed by three perpendicular planes). You'll meet octants in Class 11 Three-Dimensional Geometry.

Conceptually yes — they're both two-number addresses for a position. But latitude/longitude lie on a sphere, not a flat plane, so the geometry is curved (spherical geometry). The intuition transfers; the formulas don't.

Usually 4–5 marks of the Class 9 final exam. Lighter than algebra or geometry chapters, but the concepts come back heavily in Class 10 (where Coordinate Geometry alone is worth 6–8 marks).

Yes — boards expect plotted points on actual graph paper with labelled axes, origin and scale. Practising on lined paper is fine for revision, but use graph paper for at least the last week.

Historical accident from CRT TVs that scanned top-to-bottom. The first pixel is top-left, so positive y points down. Mathematical y points up. Both conventions still exist side-by-side in modern software.
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