Three vertices of a parallelogram ABCD are A(3,-1,2), B(1,2,-4), and C(-1,1,2). Find the coordinates of the fourth vertex D.
Hint. The diagonals of a parallelogram bisect each other. In ABCD, the diagonals are AC and BD, so set their midpoints equal.
Midpoint of AC = ((3-1)/2,(-1+1)/2,(2+2)/2)=(1,0,2). Let D=(x,y,z). Midpoint of BD = ((1+x)/2,(2+y)/2,(-4+z)/2). Setting this equal to (1,0,2): (1+x)/2=1 gives x=1; (2+y)/2=0 gives y=-2; (-4+z)/2=2 gives z=8.
✦ Working through each part gives: D = (1, -2, 8).
